Sorry. The trick is a bit clunky, but it is a trick I made up, nothing pro. A deck just seems to be a couple of 2s short. I think you can still do this trick with one deck, in this case I would just cannibalise some of the 2s from the row you are about to discard. Problem with that is that you have to talk your volunteer through it. Maybe we should just change the trick to two decks to make it absolutely smooth.
I wasn't reading your mind from here. If you had picked two, then I would have known two was the missing number because you will always be able to put the cards in groups that add up to nine.
Just to throw a message out there, I thought Plazity's trick was the best, I loved it. I felt obliged to come up with something mathsy, but I can't really see mine being performed. Out of interest, has anyone tried my trick and got it to work?
Not a mistake, 4*3 is twelve and I used an ace and a two to make 12 - I am not adding the values of the cards, I just use the ace as a one to spell out the digits of 12.
You're quite right. That is a weakness. It doesn't necessarily kill the trick if we reuse some of the aces from 5,5,A,A,6. We were only going to put them back in the deck anyway. But it's hard to talk your volunteer through that when your eyes are shut. If you really want to perform the trick, you could use two decks. Or two decks with the 10s and pictures removed. Depends how much effort you think it's worth!
You shouldn't need more than three of any kind, but you do need to put the old cards back in the deck. Starting with something like 555 is more tricky but doesn't necessarily kill the trick.
Bi. I dare say that as impressive aa this presentation is, this trick is even better when the Magician does the first 2 steps behind the scenes sladh under cover and turns this into a 1 step Prediction where they do not reveal their methods.
Nice trick. Very niceuse of basic math properties. However, I got a question: are you sure you always have enough cards to spell the products? Is it possible (or not) to run out of aces (for instance) during the process?
I don't really get it, but it looks interesting. Anyway, I like how you mentioned charmed in the description, that is one of my favorite shows! You are really smart, I could never think of that.
I haven't do it with cards but on a paper 4 6 7 were the numbers I picked so as the trick has been done that would give me 1 2 1 8 2 1 and again 3 6 3 2 4 6 3 i picked 2 and my number so there should be only 2 groups but I got three groups????
hi there i ended up with the cards 9 9 7 2 6 3 6 3 at the end so what would i do then would i do the calucatibg of 9 when they have pickerd their card or b4
what if you get a 5,5,A,A,6 in the second part? where will you get the other A? coz 3x5 is 15 that makes it two Ace's then 6x3 is 18 that needs another ace where will you get the other ace?
Had it figured out before you told about casting out nines. Not saying it's a bad trick, au contraire, but it is a bit easily figured out by anyone a tad intelligent.
I don't get what he did at the end. You can turn over any card, so why did he say the 3? I get that you can group them to add up to 9, but I don't get the "turn one over, and the one you turned over is a 3"
I found a flaw in your trick. If you choose 1, 2 and 3 as the first 3 numbers, it won't work because at the end you will only get 5 cards not 6 or more
THE POWER OF 3 *shoots fire ball* i watched that show when i was liek 3 XD this is a enginious therey,did u come up with it? it makes mostly logical sense,amazing . have you ever considered becoming a ''partner'' you have a substantially large veiwing audience,original videoes,and a phd XD,you'd deffinatly get in (then again you being the math guru you probebly guessed that already and have other resons) so once agian...amazing
@elizze6 All the cards at the end total 9 or 18 or 27 or so no. If you total up all the cards and it is 3 less than one of those numbers, then the overturned card must be a 3. If they totaled 5 less, it'd be a 5.
Hmm. Well, my card was a six, but even starting with 888, the end result was 126126126, so the maths would work.... Then again, like people said, 3×3=9, so you're basically multiplying it by 9
@shelly1332 He was trying to say what you would do if you had a person infront of you. But in the video, He is just showing you how you woould have done it if theere was a person infront of you
just incase but here when you multiple a number by 3 twice you are actually multiplying by 9 and when the number is 10 or more you use two cards (2:17) 3x4=12 and he used an Ace for the digit 1 and Two for digit 2. the best thing about a multiple of 9 is that all digits add up to a multiple of 9, so at the end he sorted all the face vaule of the card in piles that adds up to nine 2, 7 (2+7=9) and 2, 3, 4 (2+3+4=9) but he couldn't sorted the second 6 card in a pile so he did 9-6=3 for 7, the pile would have been 2, 3, 4 (2+3+4=9) and (3, 6) (3+6=9) and the second 2 will not be in a pile so 9-2=7.
you can also do this by taking away all 10's, J's, Q's, K's, and two 7's, one 5, and one 8. have them pick a card and keep it face down. with the cards remaining, add them to 9, you will end up with cards that do not add up to 9, and if there is no cards left over that add up to 9 then it means they have a nine in their hand.... this method is a bit more tedious because you have to count more pairs of 9... but either way its fun.
After your first multiplication by 3 your possibilities are 3, 6, 9, 12, 15, 18, 21, 24, 27. since you started with 3 numbers, you cannot make more than 3 of any one number (for example, 3 7s would give you 21, 21, 21. So you need 3 2s and 3 1s). After this you will have a maximum of 6 cards (since any one starting card can only give you a maximum of 2 cards). Multiplying these by 3 gives you a maximum of 9 cards (3 starting cards make 6, 6 make 9 since the first digit after multiplying by 3 will be either a 1 or 2). Of those 9 cards, you will only ever see the same number 3 times. Look above to the result (3,6,9,ect...). Lets look at the results for tripling those. They are broken up into the individual numbers (21= 2, 1) and then tripled again. So your resulting numbers will be the same ones above. The question is can you run out of enough cards to pull off the trick? No, because whenver you triple them you only ever get 3 of any value. For example: they choose 3 4s. They triple to 12, 12 , 12 (becomes 1,1,1,2,2,2). They then triple again to 36, 36, 36 (3,3,3,6,6,6). Take 3 6s. 18, 18, 18 (1,1,1,8,8,8) becomes 3,3,3, 24, 24, 24 (2,2,2,3,3,3,4,4,4). So no number should show up more than 3 times, no matter what the combination is so long as they break down the numbers to single digits and multiply by 3 again.
I was quite pleased with my 42 of Hearts reference :)
Thank you, I felt obliged to be the most mathsy and to use a unique effect.
Sorry. The trick is a bit clunky, but it is a trick I made up, nothing pro. A deck just seems to be a couple of 2s short.
I think you can still do this trick with one deck, in this case I would just cannibalise some of the 2s from the row you are about to discard. Problem with that is that you have to talk your volunteer through it.
Maybe we should just change the trick to two decks to make it absolutely smooth.
I wasn't reading your mind from here.
If you had picked two, then I would have known two was the missing number because you will always be able to put the cards in groups that add up to nine.
Just to throw a message out there, I thought Plazity's trick was the best, I loved it. I felt obliged to come up with something mathsy, but I can't really see mine being performed.
Out of interest, has anyone tried my trick and got it to work?
The cards will always make piles that add up to nine, so you can predict the missing card.
Not a mistake, 4*3 is twelve and I used an ace and a two to make 12 - I am not adding the values of the cards, I just use the ace as a one to spell out the digits of 12.
O, that is a nice trick. I just have to work out a routine for it :)
You're quite right. That is a weakness.
It doesn't necessarily kill the trick if we reuse some of the aces from 5,5,A,A,6. We were only going to put them back in the deck anyway. But it's hard to talk your volunteer through that when your eyes are shut.
If you really want to perform the trick, you could use two decks. Or two decks with the 10s and pictures removed. Depends how much effort you think it's worth!
if you run out of numbers, you can use kings as 4, queens as 3, jacks as 2
i watched it two times to understand that u wasnt adding the values of the cards!! i did it and its pretty cool! thanks!
Congratulation for the third place :) you really deserved it. Your videos are great!
That's nice.
You shouldn't need more than three of any kind, but you do need to put the old cards back in the deck. Starting with something like 555 is more tricky but doesn't necessarily kill the trick.
Bi. I dare say that as impressive aa this presentation is, this trick is even better when the Magician does the first 2 steps behind the scenes sladh under cover and turns this into a 1 step Prediction where they do not reveal their methods.
cool vid, don't understand the math but understand what to do so, thanks
It'll be very easy to find out the value of the card if you do this way. (27- value of the remaining cards). In this case 27- 24 = 3.
Thank you.
Show us the mathematical explanation as well..:)
When you triple a number twice you're just multiplying it by 9. In the decimal system any number divisible by 9 has the sum of the digits = 9.
Reila Z cool! Thank you :)
actually the sum of the digits is divisible by 9. 111*9 = 999 sum of digits of 999 is 27 =3*9.
This isn't blackjack.
he's not Adding it to the value of the card, simply using as a One to make a double digit number.
Nice trick. Very niceuse of basic math properties. However, I got a question: are you sure you always have enough cards to spell the products? Is it possible (or not) to run out of aces (for instance) during the process?
I don't really get it, but it looks interesting. Anyway, I like how you mentioned charmed in the description, that is one of my favorite shows! You are really smart, I could never think of that.
I completely agree.
I haven't do it with cards but on a paper
4 6 7 were the numbers I picked
so as the trick has been done that would give me
1 2 1 8 2 1
and again
3 6 3 2 4 6 3
i picked 2 and my number
so there should be only 2 groups but I got three groups????
Glad someone got it ;)
Well spotted, they are indeed.
what happens if the total is 20 sumthing..and also waht happens if you run out off a card?
twice or more, and it will work. So try starting with one and keep tripling.
No way, you totally peeked. I'M ON TO YOU, JAMES.
hi there i ended up with the cards 9 9 7 2 6 3 6 3
at the end so what would i do then would i do the calucatibg of 9 when they have pickerd their card or b4
what if you get a 5,5,A,A,6 in the second part? where will you get the other A? coz 3x5 is 15 that makes it two Ace's then 6x3 is 18 that needs another ace where will you get the other ace?
3: I AM THE BEST
1,2,4,5,6,7,8,9,0: NO YOUR NOT!
3: BUT THAT SINGING BANANA SAID I AM
i wish this won.
that is sooooo cool!
Thats one genius math trick!
Thank you :)
@shelly1332 Congratulations, but I think you misunderstood the idea of a tutorial.
@dieguis12 The trick still works as you will have one group of with only one card which is the 9
The power of three will make us free.
Had it figured out before you told about casting out nines. Not saying it's a bad trick, au contraire, but it is a bit easily figured out by anyone a tad intelligent.
The Power of Three Will Set Us Free, The Power of Three Will Set Us Free, The Power of Three Will Set Us Free!
I don't get what he did at the end. You can turn over any card, so why did he say the 3? I get that you can group them to add up to 9, but I don't get the "turn one over, and the one you turned over is a 3"
My card wasn't 3 D:
Though I did get 3 groups that added up to twice as much as 9
All three had an Ace and an 8
Very smart
what if you run out of cards!?
I found a flaw in your trick. If you choose 1, 2 and 3 as the first 3 numbers, it won't work because at the end you will only get 5 cards not 6 or more
THE POWER OF 3 *shoots fire ball* i watched that show when i was liek 3 XD
this is a enginious therey,did u come up with it? it makes mostly logical sense,amazing . have you ever considered becoming a ''partner'' you have a substantially large veiwing audience,original videoes,and a phd XD,you'd deffinatly get in (then again you being the math guru you probebly guessed that already and have other resons) so once agian...amazing
did you come up with this by yourself?
if you did, your a very talented human lol
No it's an old trick
@elizze6 All the cards at the end total 9 or 18 or 27 or so no. If you total up all the cards and it is 3 less than one of those numbers, then the overturned card must be a 3. If they totaled 5 less, it'd be a 5.
While I like it, there's something a bit disappointing about multiplying by 3 twice instead of three times.
@TheWolzen Oh ok for some reason I missed that he was predicting the card we turned over based on the other cards
Wait, what values are he spelling out the second time? With the 5 cards on the top.
gratz
thanks
Great Trick. Thanks for the entertainment.
Hmm. Well, my card was a six, but even starting with 888, the end result was 126126126, so the maths would work....
Then again, like people said, 3×3=9, so you're basically multiplying it by 9
Ah, i see, so how many cards you start out with is how many sums to 9 that will be at the end i guess.
@shelly1332 He was trying to say what you would do if you had a person infront of you. But in the video, He is just showing you how you woould have done it if theere was a person infront of you
i get it.
trpling it 2 time will always get yo a multiple of nine so there fore being able to add up
wtf i dont get it i picked 2? help me!
be careful of 90
my card was the 4 of diamonds not the 3
awesome..
did not understand the trick, i would have flipped the 7 in the end, why would it be a 3?
just incase but here when you multiple a number by 3 twice you are actually multiplying by 9
and when the number is 10 or more you use two cards (2:17) 3x4=12 and he used an Ace for the digit 1 and Two for digit 2.
the best thing about a multiple of 9 is that all digits add up to a multiple of 9, so at the end he sorted all the face vaule of the card in piles that adds up to nine
2, 7 (2+7=9) and 2, 3, 4 (2+3+4=9) but he couldn't sorted the second 6 card in a pile so he did 9-6=3
for 7, the pile would have been 2, 3, 4 (2+3+4=9) and (3, 6) (3+6=9) and the second 2 will not be in a pile so 9-2=7.
Think he said remove the cards from round 1, "because you might need those later"
1:19 ;)
Cool trick ^^
my card was a five
w8.. Ace is 1 or 11 so why are u using it to make numbers like 12? Ace + 2 = 3 OR 13
i dont understand
At 2:26 u did a mistake. 4 * 3 = 11 and u made it 13
you can also do this by taking away all 10's, J's, Q's, K's, and two 7's, one 5, and one 8. have them pick a card and keep it face down. with the cards remaining, add them to 9, you will end up with cards that do not add up to 9, and if there is no cards left over that add up to 9 then it means they have a nine in their hand.... this method is a bit more tedious because you have to count more pairs of 9... but either way its fun.
i dont get the trick
nice .. very nice but over 4 mins ... hopefully it doesent affect the results lol ... good luck :D
؟؟؟؟
i got it the 6th time i wathced it =]
you never told us to remember the card.
worng !
i pick 2
i had 6 >.>
first view rating and comment, nice vid ;)
💖💖❤❤💘💘
suwee...xD
errrrrrr hmmmmmmm...fucked if i know. i chose 6
3x9 = 27
3x1 = 3
3x1 = 3
3x8 = 24
3x2 = 6
Does not always work. Many times you will run out of the same number cards when making double digits. Its a "by chance" trick.
ask them to pick 3 DIFFERENT cards. don't know if that will work always though. haven't tried it
After your first multiplication by 3 your possibilities are 3, 6, 9, 12, 15, 18, 21, 24, 27. since you started with 3 numbers, you cannot make more than 3 of any one number (for example, 3 7s would give you 21, 21, 21. So you need 3 2s and 3 1s). After this you will have a maximum of 6 cards (since any one starting card can only give you a maximum of 2 cards). Multiplying these by 3 gives you a maximum of 9 cards (3 starting cards make 6, 6 make 9 since the first digit after multiplying by 3 will be either a 1 or 2). Of those 9 cards, you will only ever see the same number 3 times. Look above to the result (3,6,9,ect...). Lets look at the results for tripling those. They are broken up into the individual numbers (21= 2, 1) and then tripled again. So your resulting numbers will be the same ones above. The question is can you run out of enough cards to pull off the trick? No, because whenver you triple them you only ever get 3 of any value. For example: they choose 3 4s. They triple to 12, 12 , 12 (becomes 1,1,1,2,2,2). They then triple again to 36, 36, 36 (3,3,3,6,6,6). Take 3 6s. 18, 18, 18 (1,1,1,8,8,8) becomes 3,3,3, 24, 24, 24 (2,2,2,3,3,3,4,4,4). So no number should show up more than 3 times, no matter what the combination is so long as they break down the numbers to single digits and multiply by 3 again.
what kind of stupid trick is this. its lame. I'm not impressed