Signal addition in MATALB

[@KnowledgeAmplifier1]

Code:
clc
clear all
close all
n1=input('Enter the time sample range of x');
x=input('Enter the sequence');
n2=input('Enter the time sample range of y');
y=input('Enter the sequence');
u=min(min(n1),min(n2));
t=max(max(n1),max(n2));
r=u:1:t;
z1=[];
temp=1;
for i=1:length(r)
if(r(i)max(n1))
z1=[z1 0];
else
z1=[z1 x(temp)];
temp=temp+1;
end
end
z2=[];
temp=1;
for i=1:length(r)
if(r(i)max(n2))
z2=[z2 0];
else
z2=[z2 y(temp)];
temp=temp+1;
end
end
z=z1+z2;
subplot(3,1,1);
stem(r,z1);
subplot(3,1,2);
stem(r,z2);
subplot(3,1,3);
stem(r,z);

[@Sanjeev_3333]

Thankyou very much sir. You explained it really in a very easy way. 🙏🏻. Saved me from my lecturer 🙏🏻🙏🏻🙏🏻 .

[@KnowledgeAmplifier1]

Glad to hear that SANJEEV CHAVAN! Happy Learning :-)

[@aditiparetkar2862]

thank you sir for your efforts , very well explained!

[@KnowledgeAmplifier1]

Glad the explanation was helpful to you Aditi Paretkar! Happy Learning :-)

[@piyushagrawal6448]

Sir, can you please post and explain code for convolution of two discrete time signals

[@KnowledgeAmplifier1]

Hello Piyush Agrawal, you can refer the below videos --
Convolution in MATLAB(without conv function) | MATRIX Method | DSP
ruclips.net/video/nzVPoc4PRgI/видео.html
Plot the convolution result in MATLAB | CONVOLUTION using MATRIX method (Part 2)
ruclips.net/video/nuvgtEzEM1c/видео.html
Hope this will be helpful! Happy Learning :-)

[@piyushagrawal6448]

@@KnowledgeAmplifier1 Thanks a lot sir for timely response

[@KnowledgeAmplifier1]

@@piyushagrawal6448 no problem ! Happy Learning

[@corinnegarcia1100]

Thank you so much for this, you saved my life

[@KnowledgeAmplifier1]

Welcome Corinne Garcia
. Happy Learning :-)

[@VarshaSingh-jd1ql]

can you let me know a bit how to do via functions ?
I tried like this but error:
function [y, r] = seqadd (n1,n2)
u=min(min(n1),min(n2));
t=max(max(n1),max(n2));
r=u:1:t;
temp=1;
y1 = [];
for i=1:length(r)
if(r(i)max(n1))
y1=[y1 0];
else
y1=[y1 x(temp)];
temp=temp+1;
end
end
y2 = [];
temp=1;
for i=1:length(r)
if(r(i)max(n2))
y2=[y2 0];
else
y2=[y2 y(temp)];
temp=temp+1;
end
y=y1+y2;
end

[@haidisaid6689]

Is this addition of two discrete time signals or two digital signals?

[@subratkumarpanda3957]

Can u pls provide the code for a sampling signal

[@waliddk801]

Hi sir ty for the video, i've a question, how can we do it with multiplication, what changes we make?

[@KnowledgeAmplifier1]

refer this video----ruclips.net/video/26wr4XDg36o/видео.html
hope this will be helpful.

[@gokulmukil6617]

can you give signal multiplication and division code

[@KnowledgeAmplifier1]

Hello gokul , you can refer this video :
ruclips.net/video/26wr4XDg36o/видео.html
Hope this will be helpful ! Happy Learning :-)

[@jatingoyal4947]

thanks .. can u pls provide code for this signal
Find convolution between x1[n] = (0.5^(n-2) u [n-2] )and
X2 [n] = u [n+2] .

[@rahulmeena3269]

It shows error x(temp) undefined x and y

[@KnowledgeAmplifier1]

Give x & y properly

[@rahulmeena3269]

Can u plz explain how z1=[z1 x(temp)] are equal??

[@KnowledgeAmplifier1]

It will put the x(temp) value in z1 array , working like concatenation

[@rahulmeena3269]

Bro here is not working
Show invalid index

[@rahulmeena3269]

(Y1,r)=add(x1,n1,x2,n2) am using this one in scilab

[@HarisKhan05]

Hi
Can u explain how to add continous signals having different time range?

[@KnowledgeAmplifier1]

Same code you can apply for adding continuous signal of different range as in Computer Everything is discrete only , nothing can be continuous :-)

[@koutuhal]

Nice

[@KnowledgeAmplifier1]

Thanks Arijit . Happy Coding :-)

[@subratkumarpanda3957]

Gg

[@daetramp1528]

no offense just asking btw

[@vaishnavisrivastava2269]

Code?

[@KnowledgeAmplifier1]

I have given the code in the comment section . Anyway giving here too , Happy Coding :-)
clc
clear all
close all
n1=input('Enter the time sample range of x');
x=input('Enter the sequence');
n2=input('Enter the time sample range of y');
y=input('Enter the sequence');
u=min(min(n1),min(n2));
t=max(max(n1),max(n2));
r=u:1:t;
z1=[];
temp=1;
for i=1:length(r)
if(r(i)max(n1))
z1=[z1 0];
else
z1=[z1 x(temp)];
temp=temp+1;
end
end
z2=[];
temp=1;
for i=1:length(r)
if(r(i)max(n2))
z2=[z2 0];
else
z2=[z2 y(temp)];
temp=temp+1;
end
end
z=z1+z2;
subplot(3,1,1);
stem(r,z1);
subplot(3,1,2);
stem(r,z2);
subplot(3,1,3);
stem(r,z);

[@subratkumarpanda3957]

😭😭

[@daetramp1528]

why you talking like you scolding me?