You are indeed correct...... my bad.... thanks for pointing it out ..... however, in this case, it does not change the answer because all it does... is add C' to the AxA' term ..... and AxA'xC' is still zero... best wishes 😊
@@tonzaifavour I try to respond to all questions on all my videos ..... does not matter how old they are .... I would not be able to do this if my channel had 100K subscribers with loads of comments each day .... but it's small enough that I can still handle all the comments that come in each day 👍
There is a COMPOUND rule that allows you to remove the c' ..... and I not only gave it to you in another video, but I actually provided the proof by breaking it down using the simple basic steps.......so here is the compound rule ..... A +A'B = A + B .... (note A' gone .. for good 😁)..... here is the proof ruclips.net/video/vSH5eusYiVg/видео.html
@@StephenMendes I might be wrong but I think (AB + C)' = (A'+B') * C' . You somehow got A' + B'C'. I don't understand what you did. (prime means there is a bar)
@@MalekaParvin-z4k It is YOU who do not understand .... both sides of the above equality have the identical truth table .... IF you know how to "find a truth table from an expression" ? ..... so there must be a flaw in your understanding of that
You deserve a subscriber and a like! Thank you for your videos
Thank you so so much, way better than my prof!!!
Really helpful.
Lot of thanks ❤
I think De Morgan usage in (AB+C)' should be (AB)'xC' (we should consider AB as an individual term), then it may become (A'+B')xC', not A'+(B'xC')
You are indeed correct...... my bad.... thanks for pointing it out ..... however, in this case, it does not change the answer because all it does... is add C' to the AxA' term ..... and AxA'xC' is still zero... best wishes 😊
@@StephenMendes thank you for your kind reply, same to you yoo :)
Wow!! i love this video, it's just enriched my brain.Thanks alot.................
Good explanation but the fifth part of your equation was covered up until your tutorial finish.
Sorry for that 😊
Can you please explain how C + not C becomes C but not B + B becomes 1
C + not C becomes 1 and B + not B becomes 1 ..... does not matter what letter we use 😁
@@StephenMendesthe fact you're responding to over a year old video is amazing❤
@@tonzaifavour I try to respond to all questions on all my videos ..... does not matter how old they are .... I would not be able to do this if my channel had 100K subscribers with loads of comments each day .... but it's small enough that I can still handle all the comments that come in each day 👍
Terima kasih bro
when d not multiplies ab+c double bar I don't know how an addition sign comes.
How did you removed the c' in 3:41 iam so confused there literally no rules that i know that you can do that please help me
There is a COMPOUND rule that allows you to remove the c' ..... and I not only gave it to you in another video, but I actually provided the proof by breaking it down using the simple basic steps.......so here is the compound rule ..... A +A'B = A + B .... (note A' gone .. for good 😁)..... here is the proof ruclips.net/video/vSH5eusYiVg/видео.html
@@StephenMendes thanks alot god bless you
I need help with deriving a boolean expression given the logic circuit
I have video for that too .... here is the link.... ruclips.net/video/cElozbxsaGo/видео.html
If it has in Flip-Flops then I have videos for that also.... in my Playlist named "ELET1215 - Digital Electronics 2 - MSI & Asynchronous Logic"
why is it that at 3:41 you're allowed to simplify C + C'AB' + D' + AB to C + A(B'+B) + D', isn't C + C' = 1? How do you factor out the C?
C + C' = 1 only when the letters match.... in the above example the C' is ATTACHED to AB' and the C is not therefore you cannot use that rule
1.2 Show the behaviour of the circuit below using a Truth table
huh ?
hi ,can u help for the problem?
I don't know what the problem is ? ..... so I cannot know whether I can help or not 🙂
I don't think you are using the De Morgan's theorem properly
oh really ? ..... well teach us then 🙂..... exactly where in the video is the error ? ..... and do show us the "proper" way 😁
I suggest you also build the circuit and prove your truth table when you are done ..... cause what I have shown in video is 100% correct
@@StephenMendes I might be wrong but I think (AB + C)' = (A'+B') * C' . You somehow got A' + B'C'. I don't understand what you did. (prime means there is a bar)
How to write XNOR of AND expression with no negations from the truth tables?
got it
Please I need help
exnor circuit to bolean expresion
love the accent
What did you do with c bar
Can you say PLZZ.....a'+ab=???
answer is: a' +b
@@StephenMendesaccording to Truth table you can not say a`+ab=a`+b
@@MalekaParvin-z4k It is YOU who do not understand .... both sides of the above equality have the identical truth table .... IF you know how to "find a truth table from an expression" ? ..... so there must be a flaw in your understanding of that