Video is in very simple Hindi n English . Obtaining Norton's equivalent circuit by easy calculations for Rn and In ie Norton's Resistance and current resp.
Short circuit ie 0 resistance in parallel with any resistance is equal to 0 resistance ie short circuit.Now No current will pass from 4 ohm resistance .
It is part of method, for finding RN i.e. first remove independent V. S. then apply 1 Amp test current or 1V test voltage at open circuited load terminals for energy source in circuit.
Here current is moving from V1 to V0,that means V1is at higher voltage. Direction of current indicates that current is moving from higher voltage node to lower voltage node.
Parallel combination of a resistor and short circuit (0 Ohm) is 0 Ohm. Or any resistance parallel to short ckt has no role as no current flows in resistive branch.
I have circuit which don't have independent source but have dependent source, I tried every method but don't get Rth of circuit Circuit details 10 ohm 5 ohm are in series Vx across 5 ohm Dependant source 4Vx is in series with 10 ohm and 5 ohm 15 ohm parallel to above elements And this circuit having open circuit terminals a and b
very nice mam..,i really enjoyed the lec ..
Thank you.
Excellent teaching mam 👏👏
Mam my answer comming using.thevnins volatage Vth..Rth=Vth/ISC=0.5... at
Thank you mam..Upload more problems with their solution
I have uploaded some videos. Pls check them on my channel.
more solved examples
ruclips.net/video/i_VtXMLFmOs/видео.html
nice vdio mam I like ur teaching Wat very easy
Thank you. You can ask for more topics of Electronics.
Thank you ma'am...you just saved me.. 🌷🙏🙏
Welcome with some other topics on Electronics.
Explained in very simple manner. Tu mam
Thank you.
thank you maam love from iit
here's a better video on norton with dependent sources from a DTUite
ruclips.net/video/i_VtXMLFmOs/видео.html
Excellent method mam
Thank you.
Mam u explain very well
But plz arrange big board........🙏
Thank you. I will definitely use a big board if needed.
Tq mam. Your explanation is very clear.
Thank you.
You can ask for more topics of Electronics
thanks mam
Good mam
lot of knowledge mamji
Thank you. Welcome.
28-06-2020 ko dekh rha hu doute clear ho gya mam
örnek için teşekkürker . Thanks for example :)
Thank you.
Mam can we use DC voltage in that circuit too? For testing.
Yes. You can find Rn using 1V voltage source also.
Many many thanks mam,,,upload more video from Alexander exercise, it will be great,,,anyway,,,thanks a lot mam,,,from Bangladesh, 🙏🙏🙏🙏
Super mam
Excellent mam
Thank you.
aapne 4 ohm ka register kiyon remove kiya
Short circuit ie 0 resistance in parallel with any resistance is equal to 0 resistance ie short circuit.Now No current will pass from 4 ohm resistance .
Madam notes are available, in this subjects
Mam mesh analysis lgayen tu zero q ata current.
Plz help me🥺🥺🥺
Apply mesh analysis in outer loop because in middle there is current source ie 6 + 5*Is/2 -3*Is =0 and we get Is = In = 12 amp
awesome
Thank you.
Thank you
Yes but it is difficult to show circuit
Mam please tell me what happens if dependent source is just right side of 3 ohms. Please mam.
In that situation Norton's current In =1.5 Is + 0.5 Is = 2 Is.Then apply KCL at that node in terms of V/R or KVL in outer loop.
Mam then how to get node voltage if I do it in nodal analysis.
Since a short ckt is there in last In branch,so node voltage would be 0 there. Apply Ohm's law in first branch ,or KCL.
Mam how to apply kvl as there is a current source in first branch.
Can we apply superposition theorem for depending sources
Yes, but at least two independent sources must be in circuit.Consider every independent source individually, dependent source will be there everytime.
Ok thanks mam then we have again to apply kvl or kcl for calculating the the depending sources
ruclips.net/video/eMIywjuCx-s/видео.html is the link for superposition theorem for dependent source
Why u included 1A mam
It is part of method, for finding RN i.e. first remove independent V. S. then apply 1 Amp test current or 1V test voltage at open circuited load terminals for energy source in circuit.
why use half deflection in this experiment
I think you are talking about voltage drop across 3ohm resistance. For that take the branch upto ground only. Don't need to go around the loop.
Mam that will be vo-v1
Here current is moving from V1 to V0,that means V1is at higher voltage. Direction of current indicates that current is moving from higher voltage node to lower voltage node.
why remove the 4 ohm resister😑😑😑
Parallel combination of a resistor and short circuit (0 Ohm) is 0 Ohm. Or any resistance parallel to short ckt has no role as no current flows in resistive branch.
Uplode more problems maim
Instead of kcl
I want sher one eg
Sure, u can ask.
Mam can I get your email id please,
Because some of the examples student unable to solve
Thanks and You can ask your problems here also.
Yes but it is difficult to show circuit
I have circuit which don't have independent source but have dependent source,
I tried every method but don't get Rth of circuit
Circuit details
10 ohm 5 ohm are in series
Vx across 5 ohm
Dependant source 4Vx is in series with 10 ohm and 5 ohm
15 ohm parallel to above elements
And this circuit having open circuit terminals a and b
Dnyaneshwar, Pls refer this video link for ur problem..... ruclips.net/video/wvPje3RmP68/видео.html
I will send solution of ur problem very soon.
nice vdio mam I like ur teaching Wat very easy
Thank you.
Ask for more topics of Electronics.