i know it's awesome awesome concept with awesome presentation but here is a better video on thevenin using dependent sources ruclips.net/video/D1QxFA9_U5w/видео.html
After finding current in closed loop u can also directly find Vth without writing another equation Its will consume less time. Vth = voltage drop across 6ohm resistance (IR or 2x6)=12V
Thanks mam I was solving JB Gupta book's questions, i knew only about simple independent source type questions of Vth & Rth I easily solved all after watching your video☺️
Draw a random thevenin's circuit and a Norton's circuit and observe both circuits...they are source transformations of each other by that observation we get Rth=Vth/isc
the current way to find Rth is to take Isc ( short circuit current ) at terminal AB and then using mess analysis find the value of Isc and then Rth using formula Rth=Vth/Isc which is equal to 12.4 ohms
In KVL we consider all voltage drops in the considering loop here outer loop. As no current in second loop so drop across 10 Ohm is 0.But drop across open terminals will be taken as Vth.
Mam I think we needn't apply kvl to the outer loop because no current will flow through 10 ohm resistance .we need to apply kvl only in the inner loop and the voltage across 6 ohm resistance will be Vth.Correct me if I'm wrong.
Mam Why we ignore 10ohm and 6ohm resistors as 10ohm is in series with the circuit current also flow in 10 ohm is Potential difference depends on it between a and b terminal Waiting for your reply
entire current is flowing back from 6ohm resistance to source ..there is no return path from 10ohm resistance bcuz its open while finding vth 1st case.
while finding VTh, open circuiied load terminal so no current across 10ohm for that case only. Next to find RTh, connect a test voltage at terminal AB, you have to consider 10ohm this time.
Mam we take test source when there is only dependent source but here we have both independent and dependent source ...... In spite of taking test source at ab terminal we will find the short circuit current at AB terminal and then find Rth using formula Rth=Vth/Isc (short circuit current) do check this once again
To find Vth, load resistance is removed in first step. So there is only one loop remaining in this ckt. In that loop one current I is flowing which is already given here .another mesh is not existing as it is opened at load.
Ma'am, could you solve this problem by using kcl method because there is a dependent voltage source in first loop ma'am what would we take as as a reference node. Can I take voltage source current dependant as a reference node kindly resolve my queries
Take second (next) sign in voltage source in moving direction such as from voltage source [+ -] take - sign, which is second sign if we are moving rightward. In resistors take - sign , if moving in direction of current and vice-versa.
In this ckt ,we have two unkowns (i and Vth). So we need two equations to solve them. You can get second equation through other ways like Currrent i in loop I using ohm's law i.e. i= V/R =(20+2i)/12i. Or use KCL at middle top node
entire current from source is flowing through 6ohm resistance back to source ..there is no return path from 10ohm resistance bcuz its open while finding vth (1st case.)
Manoj, when dependent source is present in circuit like 2i here as it is a voltage source that depends on current i in loop I ,then apply test voltage(1v) or test current (1amp) at load terminal while solving for Rth. If u use test current (1amp) then apply KCL ie nodal analysis to find V0 across it.
Mam the decoration done on board with different chalk colours is worth appreciating 💜
i know it's awesome awesome concept with awesome presentation but here is a better video on thevenin using dependent sources ruclips.net/video/D1QxFA9_U5w/видео.html
@@SupremeTuber bhai bada bakwas samjahaya tune kuch palle hi nahi pada pehle khud pad phir dusro ko pada
Bhai padne aata hai ya chalk ka colour dekhne aata hai
Since the current flowing through the current controlled voltage source 2i is i it is just a 2 Ohm resistor. You have beautiful penmanship. Best.
After finding current in closed loop u can also directly find Vth without writing another equation Its will consume less time.
Vth = voltage drop across 6ohm resistance (IR or 2x6)=12V
Yes, you can use that also.
More over I thin kvl is applied to a closed loop..
Thanks ma'am.I am from bits pilani,it really helped me.You are as good as our professors here
That was just straight up awesome... That's more like it
Thank you.
Thanks mam
I was solving JB Gupta book's questions, i knew only about simple independent source type questions of Vth & Rth
I easily solved all after watching your video☺️
Thank u.
I didn’t understand how we got Rth while in finding Rth we use short circuit current (isc) at AB...by ohms law Rth=Vth/isc
Draw a random thevenin's circuit and a Norton's circuit and observe both circuits...they are source transformations of each other by that observation we get Rth=Vth/isc
Life savior ❤🛐
I don't understand what you are saying but I get it what you write Thanks 😀
Ma'am At 4:46 did we take any value of test voltage or test voltage is always 1V?
You can take any value but Calculationis for Rth with 1V are easy ie Rth= 1V / io.
@@rashmiagnihotritiwari8211 ok ma'am... thanku so much ma'am for these videos
Very technically informative video, Mam.😊😊
Thank u so much.
Thanks alot...i didn't get anything our stupid college progessor say ....thank u maam ....😍😍🤗
thank you for clearing my doubt.
the current way to find Rth is to take Isc ( short circuit current ) at terminal AB and then using mess analysis find the value of Isc and then Rth using formula Rth=Vth/Isc which is equal to 12.4 ohms
Madam G, Aap ne Vth across terminal A-B 1v put kia, kaha se aa giya 1v???
This is part of the process to find Rth in dependent source ckts, since source is needed there: it may be a 1V source or a1Amp Current source.
Mam FABULOUS JOB..the way you teach is awesome..
Thank you. You can ask for more topics of EC.
Awesome mam ... 🙏🙏😁
excellent mam jo doubt 1 hour se clr na hua 10 min me
ho gya
👌👌Superb👌👌👌
thank u ma'am..keep doing the good work..
0:57 why 10 ohms is not consider while solving???? mam
In KVL we consider all voltage drops in the considering loop here outer loop. As no current in second loop so drop across 10 Ohm is 0.But drop across open terminals will be taken as Vth.
Yes mam got your point.. Thank u mam.. And while considering signs it depends on us if we can take entering or leaving current sign,
@6:58 we know value of "i" ..why you have not put directly
it's the value of i0 not i
Thank you very much mam....your video was so helpful to me....
awesome video maam! THank you!
Superb.. Keep it up mam
Mam I think we needn't apply kvl to the outer loop because no current will flow through 10 ohm resistance .we need to apply kvl only in the inner loop and the voltage across 6 ohm resistance will be Vth.Correct me if I'm wrong.
Yes, its another way to find Vth .Here I tried to give a general method that suits to other problems also.
Nice teaching mam👍👍🙂
Mam
1:32 time
Vth concept not understand
Waiting for your reply
rj kumar ,Vth is voltage across open circuiied load terminal I.e.AB terminal and KVL is the method , used to find it.
Thankyou for reply
very good explanation nd great teaching maam
Thanks. You need more videos on EC....
Mam यदि किसी dependent circuit me Rth ki value negative में आता है तो उसका answer negative में देगे या फिर positive me
Nice explanation ....
Very nicely explained ma'am.
Aapka video bahut acha laga
Nice mam...apne khubsurat i k sath yeh chees samajh diya...thanks a lot mam...
Thanks mam for such helpful lecture.
Mam
Why we ignore 10ohm and 6ohm resistors as 10ohm is in series with the circuit current also flow in 10 ohm
is Potential difference depends on it between a and b terminal
Waiting for your reply
The same i cudn't understand
entire current is flowing back from 6ohm resistance to source ..there is no return path from 10ohm resistance
bcuz its open while finding vth 1st case.
while finding VTh, open circuiied load terminal so no current across 10ohm for that case only. Next to find RTh, connect a test voltage at terminal AB, you have to consider 10ohm this time.
Only 10ohm resistor is not considered as there is no current flow when we open circuiied AB terminal..
great help for those who need help BUT too fast......... slow down a little bit; it's not a love story!
Slow your speed of video
Mam...when we apply kvl for outer loop then
10ohm resistance ke across me drop nahi hoga???
Yes,no drop.Reason: there is no current due to open circuit .
Thnq mam...
Thank you mam nice explanation
Mam can't we do this problem using nodal analysis
Yes we can solve it using KCL.
[20+2i-Vth] /6i = Vth/6 ....( I )
Vth/6 = i.....( II )
@@rashmiagnihotritiwari8211 very much helpful mam. Thank you so much
Very nice ma'am.
Mam we take test source when there is only dependent source but here we have both independent and dependent source ...... In spite of taking test source at ab terminal we will find the short circuit current at AB terminal and then find Rth using formula Rth=Vth/Isc (short circuit current)
do check this once again
Two equations are required as unknown variables are also two ie i and VTh.So apply KVL in outer and inner loops.
Yes,you can do like that also.
Okay mam thank you so much
Mom I thought we got Vth to help us in finding Rth bt I wonder where 12v has been used..help please!!!!
very good
Good
mam how you take only 'i' for outerloop and mesh1 ...i.e. i1 for outerloop and i2 for mesh1...
To find Vth, load resistance is removed in first step. So there is only one loop remaining in this ckt. In that loop one current I is flowing which is already given here .another mesh is not existing as it is opened at load.
Thanks. Nice explanation.
Thank you.
Ma'am, could you solve this problem by using kcl method because there is a dependent voltage source in first loop ma'am what would we take as as a reference node. Can I take voltage source current dependant as a reference node kindly resolve my queries
First find I in loop ie (20+2i)volts/12 ohm=i.herewe got i= 2amp. Now get thevenin voltage Vth= VAB= 6* i= 12 volts.
Mam when to put 1volt or1 ampere
You can use any of them .When you take 1 volt then find current io in the branch we applied this 1volt. Then Rth= 1 volt/ io.
Thanks for your time
THANK YOU MAM.
Maam please make a video on concept of capacitor and inductor charging and transient basics
I have uploaded videos on transient analysis. Pls see them.
Nice job
Thank you.
Thq so much mam
By using 1v we can find Vth please exapian
To find Vth, no change in original ckt .Only open ckt the load terminals to find Vth there..Then apply KVL here in meahes.
Mam is questions me kvl use kiye to usme 10ohm resistor use nahi ki app yaha pe doubt HH🙄🙄
No dropavross 10 Ohm resistor.Reason: there is no current due to open circuit .
mam please provide +&- sign properly with direction of flow of current.
Take second (next) sign in voltage source in moving direction such as from voltage source [+ -] take - sign, which is second sign if we are moving rightward. In resistors take - sign , if moving in direction of current and vice-versa.
Thanqu mam💕
Ye outerloop kisi book me nhi dekha ma'am kaise ho rha h
In this ckt ,we have two unkowns (i and Vth). So we need two equations to solve them.
You can get second equation through other ways like Currrent i in loop I using ohm's law i.e. i= V/R =(20+2i)/12i.
Or use KCL at middle top node
THANKS Teacher
We need one more way to find rth
Thanks a lot.
Very many thanks ma'am
Thank you.
Thnks mam😇🙏
thank u mam. upload more
Thank you. I have uploaded some more videos,pls see those videos.
Mam dependent current source hua to ka karenge
ruclips.net/video/Oz7OMk_xy_0/видео.html
ruclips.net/video/btw6swstlk0/видео.html
Pls see these videos.
Thanks you ma'am
Thank Teacher!
Ap kiu 1v ka hi test voltage use Kiya ??? Dusra koi kiu nahi liya???
1V test voltage is used for simple calculations only. Other voltage ratings like 2V, 3V can also be used.
@@rashmiagnihotritiwari8211
Will I get same result?
Yes.
thanku mamji
You are so cute mam 🥰
Thanks ma'am
Rth will be 13 Ohm?
12.4
👍🏼👍🏼👍🏼👍🏼👍🏼👍🏼
BE LOVED VIDEO U DO
For Both she didn't considered 10 ohms resistance.
For Vth, mesh II is an open Circuit. No current over there so need not to consider 10ohm as there is no voltage drop.
entire current from source is flowing through 6ohm resistance back to source ..there is no return path from 10ohm resistance bcuz its open while finding vth (1st case.)
nice madam
Thanks mam
Mam, how to know that when we should apply a test voltage source and when not to??
Waiting for ur reply
Manoj, when dependent source is present in circuit like 2i here as it is a voltage source that depends on current i in loop I ,then apply test voltage(1v) or test current (1amp) at load terminal while solving for Rth.
If u use test current (1amp) then apply KCL ie nodal analysis to find V0 across it.
Thanks for ur reply mam
@@manojchowdary662 u r welcome with some other topics of EC
Thanku mam
Complete unit ki vidio bnao jis me sari theorm ho
I uploaded Reciprocity theorem. Millman and Resonant circuit in next few days. Any other topic...
v.good explanation..... But your black board is too small
Abdullah Shah ,thanks ! your advice will be well considered.
yours diagrams are too easy but our paper is too tough
Abdullah Shah ,which university papers ? I would like solve those also.
Osmania university
I will definitely use a big board if needed. Thanks for suggestion.
if you don't understand the concept while watching this video go check out this one
ruclips.net/video/D1QxFA9_U5w/видео.html
Galat Kiya he solve.
It is one of the simplest methods ie KVL. It can also be solved using Ohm's law or Nodal analysis.
keep it up madam
Use big board maammmmmm
Pole zero pole
Poor sound
bekar lga bilkul...
Thankyou ma'am
Thanks mam
Thnx mam
thanks mam