Motion in a Vertical Circle - Circular Motion | Class 11 Physics

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Koi use nahi hai.....?????

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[@ammaster9144]

Meri friend bano gye saika

[@BilalShaikh-ke3fw]

This is such a amazing session for vertical circular motion
Thanks to make my topic crystal clear
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Thank you so much 💓 💗 💛 💖

[@mallappa3000]

I am impressed very much by your presentation. excellent
Sir
1)could you please explain what happens if the string is cut
2) minimum velocity at the lowest position is
less than the square root 5 gr and greater than the square root 2 gr
3)minimum velocity at the lowest position is less than the square root 2 gr
4) is it possible to add animation
5) a graph showing tension, minimum velocity (y-axis), and angular position along the x-axis
With warm regards
Dr. M S Hebbal

[@nine-eleven911]

Dear Dr. M S Hebbal, I am a fellow student and I am trying to answer your questions.
1) If the string is cut, the tension becomes zero, the bob will move in a direction which is tangential to the velocity.
2) If the minimum velocity is less than root 5 gr, the bob will not be able to complete one rotation, if it is greater than root 5gr, then the rotation will be completed and the next rotation will begin but will end halfway as it will have insufficient velocity.
3) did not understand the question.
4) does not concern me
5) I don't think such a graph exists. If it does, than I have not seen one.
Hope it helps....
Warm Regards,
Anurag Patil

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@@nine-eleven911 😂👍👍

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Sir aap bohut acha padhate ho

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Ohh 😮😯 😯 my god sir mana apka jasa kabi bi koi bi teacher nahi dakha and apka teach karna ka style bhut he sweet ha, cute ha . Apka liya mara pass word bi nahi ha jis sa apko complete define kar saku lots of Love💖💖💖💖💖💖 very very thanku sir

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Rajwant sir se padh ja kr

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I am satisfied with your explanation sir 🥰 such a nice explanation sir 🥰

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Kamaal ka samajhate hai mast insaan ho sir aap❤❤❤❤ God bless you

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Best explanation sir ❣️

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Aap such mein osm teacher

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[@mohammadowais1075]

Tm =4mg

[@xyz714]

Thank you sir for this video . This is so much help full

[@BrijSingh-jz5hx]

Now I got to know..from where didi my teacher teaches us 😂
She 1st learns from you then stick it to us in class

[@tilakraj9625]

Very very good explain sir

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Nyc nyc nyc video sir 👌🏻👌🏻

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[@kiranpreetkaurkiranpreet6475]

very very nice explanation sir👌👌❤❤

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Sure sir

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Superb video👍👍🙏🙏

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Good explanation sir thanks

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[@aritrabarman8763]

Sir tension T at point where cos 90=0 is 3mg.

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Thank you so much sir 💞💞

[@sachinkumarsingh4956]

Sir thank you so much thanks sir 😊😊

[@comedyking-up4jr]

Sir one short video banao

[@comedyking-up4jr]

For 12th

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[@shtakshirajput6875]

Tm>3mg

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Sir aap bade hi pyaare hain

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Sir please take 12th classes

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Thanks sir

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Thank you Sir 😇❤️

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[@PiyushGhatge]

Best video on circular motion

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[@harinikotla564]

Sir a request (we can't see the board while uh are explaining )

[@priyasrivastava3891]

T=mg...

[@ROHIT-sk3ox]

3 mg

[@javeersangwan6851]

It's very easy thank you sir 🤩🤩🤩🤩

[@ramishnaushad9662]

Sir plz start ch 7🙏🏼🙏🏼, system of particle and rotational motion 🙏🏼🙏🏼🙏🏼🙏🏼

[@anemiecreater4361]

Sir 🙏🙏🙏 make the videos of chapter 7

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This is not for cbse right ?

[@ms10382]

17:06 wohi yar confuse kr diya

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good lecture thank u

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Note ka liya payment kaisa kara plese make vido

[@parikshitmittal3790]

sir the pen is very thin and it is not visible

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sir ke haath me scale fit hai

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Is it enough for neet?

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No

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Jai shree ram

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OSCILLATIONS PLZ🙏🙏🙏🙏

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[@Nihal0285]

3mg

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Maza aya tho I'm straight

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[@weird_a_weird]

T = 3mg

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Hello

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Thank u sir

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🙌🙌

[@trkindia7838]

Explanation.. not up the level.

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👏💯

[@AnkitYadav0008]

Sir when you said bob

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Thank you sir❤

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Thanks sir

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Thank you so much sirrr ❤

[@ayushbhawaria2535]

T=3mg

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Thank you sir 🙏🙏

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Thank you very much sir

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Thanku so much sir 🙏🙏🙏

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