You are an incredible woman. Currently I am studying for advanced functions and data management in the summer to prepare myself for grade 12 year and your videos have helped me a tremendous amount -- Thank you so much, you are an amazing teacher! ❤👏👏👏
Hi Miss I'm confused regarding question 2b) on the quiz. More specifically, how you said, "Don't worry about preceding, do following" I did following, but I also did proceeding (2-0.01=1.99). You said we're doing (x+h) here, but I don't see where it said that. Can you please clarify because my end answer was 640km/h - I used (1.99, 1281.2) as my second coordinates.
You only need to do one (following or preceding) and it depends on what your teacher asks for. (x+h) is just indicating a small following interval which is usually what you would choose. I did the calculation and used the coordinates that you had determined above, and I got 671.94 Perhaps you made a calculation error? (Sorry for taking so long to reply I've been very sick with a terrible cold)
@@mshavrotscanadianuniversit6234 Got it Miss awesome, yes I think I made a calculation error. I hope you get better soon, everyone's getting the cold ah!!
Hello Ms. Havrot, in another way, could we have used the 0.01 method in the preceding and final interval so 1.99 and 2.01 plugged them into the quotient formula and then averaged them. Would that answer be still accurate?
Of course you can but I think you will see that if you are using that small of an interval that the difference between the two methods will be very small. In calculus the definition is always the limit f(x+h)-f(x)/h as h approaches 0 (more on that in calculus and vectors)
Hello, hope all is well. The formula you wrote for instantaneous rate of change, does it have any relations to point slope form? Could we have solved the problem you were doing near the end of the video with point slope form or are they completely different from the IRC formula?
Slope of a line is found between two points on a line. The instantaneous rate of change is slope at one point on a curve and involves making the distance between two points smaller and smaller. Calculus allows you to find this IRC using rules.
Miss firstly I wanted to say thank you so much for your videos, they are truly extremely helpful. I just wanted to ask you something, in grade 11 physics we learned that a distance time graph can only have a positive slope, not negative. Our teacher said that distance doesn't decrease because it's a scalar quantity, and that only displacement decreases. I was a bit confused regarding that so I just wanted to ask you about it because at 5:44 there were negative slopes in a distance time graph.
You physics teacher is absolutely correct. In many a math question you take the definition that speed is the absolute value of the change in displacement over absolute value of the change in time where displacement can be distance, height or depth (see page 102), so if you are using d, for these examples you are actually talking about the displacement from a certain point. For example on page 106 in your textbook they use distance vs time to show the movement away from the motion detector. Thanks for your comment and also for watching my channel! Please encourage your friends to subscribe as well : )
Thank you for the super helpful video!! I have a quick question, for question 6 c) in chapter 2.3, how did the answer sheet find such exact coordinates? Is there an algebraic way to solve this question, I simply looked at my sketched graph, aligned the ruler to the secant and shifted it to the right and arrived at the answer of (1,1). Thank you so much for your time!!!
The question asks for an estimate, and by what you have done that should be adequate. There is a way, using calculus, to find the exact value, but that would be for another day!
I understand your confusion. You have to recognize that we are simply looking at the steepness of the slope. If the slope gets more steep, whether positive or negative it is speeding up. It’s all about the tangent lines. Listen again to my explanation at 6:17.
The limit definition uses f(x) and f(x+h) so it is using a following interval. A question should tell you whether to use a preceding, following or centered interval but generally a small following interval is acceptable.
You are an incredible woman. Currently I am studying for advanced functions and data management in the summer to prepare myself for grade 12 year and your videos have helped me a tremendous amount -- Thank you so much, you are an amazing teacher! ❤👏👏👏
You will find it much easier with all your prep! Good for you and thanks for the compliment and for watching 😊
What city do you live it ?
super helpful thanks! You make it really simple :)
Great! Are you doing summer school?
Hi Miss I'm confused regarding question 2b) on the quiz. More specifically, how you said, "Don't worry about preceding, do following" I did following, but I also did proceeding (2-0.01=1.99). You said we're doing (x+h) here, but I don't see where it said that. Can you please clarify because my end answer was 640km/h - I used (1.99, 1281.2) as my second coordinates.
You only need to do one (following or preceding) and it depends on what your teacher asks for. (x+h) is just indicating a small following interval which is usually what you would choose. I did the calculation and used the coordinates that you had determined above, and I got 671.94 Perhaps you made a calculation error? (Sorry for taking so long to reply I've been very sick with a terrible cold)
@@mshavrotscanadianuniversit6234
Got it Miss awesome, yes I think I made a calculation error. I hope you get better soon, everyone's getting the cold ah!!
I’ve never had such a bad cough 😷
Hello Ms. Havrot, in another way, could we have used the 0.01 method in the preceding and final interval so 1.99 and 2.01 plugged them into the quotient formula and then averaged them. Would that answer be still accurate?
Of course you can but I think you will see that if you are using that small of an interval that the difference between the two methods will be very small. In calculus the definition is always the limit f(x+h)-f(x)/h as h approaches 0 (more on that in calculus and vectors)
You’re such a blessing.
Why thank you! Hopefully my videos will ensure that you have a successful year ❤️
you are a lifesaver! thank you for the lesson!
You’re welcome! Please encourage others to subscribe and learn ! 😊
Hello, hope all is well. The formula you wrote for instantaneous rate of change, does it have any relations to point slope form? Could we have solved the problem you were doing near the end of the video with point slope form or are they completely different from the IRC formula?
Slope of a line is found between two points on a line. The instantaneous rate of change is slope at one point on a curve and involves making the distance between two points smaller and smaller. Calculus allows you to find this IRC using rules.
why cant I have you as my online teacher :(
But you can!! 😀
Miss firstly I wanted to say thank you so much for your videos, they are truly extremely helpful. I just wanted to ask you something, in grade 11 physics we learned that a distance time graph can only have a positive slope, not negative. Our teacher said that distance doesn't decrease because it's a scalar quantity, and that only displacement decreases. I was a bit confused regarding that so I just wanted to ask you about it because at 5:44 there were negative slopes in a distance time graph.
You physics teacher is absolutely correct. In many a math question you take the definition that speed is the absolute value of the change in displacement over absolute value of the change in time where displacement can be distance, height or depth (see page 102), so if you are using d, for these examples you are actually talking about the displacement from a certain point. For example on page 106 in your textbook they use distance vs time to show the movement away from the motion detector. Thanks for your comment and also for watching my channel! Please encourage your friends to subscribe as well : )
Hello Mrs. Havrot I really appreciate what you are doing you are a life saver. But could I get a digital link to the quiz of this unit.
mshavrot.pbworks.com/f/IMG_6642.jpg.pdf
Here you go! Glad that I can help you out. : )
Thank you for the super helpful video!! I have a quick question, for question 6 c) in chapter 2.3, how did the answer sheet find such exact coordinates? Is there an algebraic way to solve this question, I simply looked at my sketched graph, aligned the ruler to the secant and shifted it to the right and arrived at the answer of (1,1). Thank you so much for your time!!!
The question asks for an estimate, and by what you have done that should be adequate. There is a way, using calculus, to find the exact value, but that would be for another day!
@@mshavrotscanadianuniversit6234 I see, thank you!!
Why do we use a 0.01 interval and not another number? 12:41
Because you want to choose a small number … you could also use 0.001 but generally a 0.01 interval is sufficient.
at 5:52, how is the slope increasing? because I thought it would decrease?
I understand your confusion. You have to recognize that we are simply looking at the steepness of the slope. If the slope gets more steep, whether positive or negative it is speeding up. It’s all about the tangent lines. Listen again to my explanation at 6:17.
ohh that makes sense, thank you so much ! @@mshavrot_math
But why use 2.001 and 2 instead of 2.001 and 1.999 like normal?
The limit definition uses f(x) and f(x+h) so it is using a following interval. A question should tell you whether to use a preceding, following or centered interval but generally a small following interval is acceptable.
you seriosuly m y dawg