Sallen-Key Differential Filter Amplifier
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- Опубликовано: 25 сен 2023
- A combination of three operational amplifiers is used in the shown analog circuit to implement a differential lowpass filter amplifier with an overall gain that is controllable by the ratio of two resistor and also a potentiometer or variable resistor in the circuit. A combination of KCL, superposition, virtual short, inverting amplifier and non-inverting amplifier op amp topology is used to analyze the circuit and find the overall voltage transfer function which has a second order denominator due to two capacitors in the Sallen-Key VCVS filter topology. Bode magnitude plot (magnitude frequency response) of the filter, Poles of the system and overall gain are discussed as well.
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Thank you for the video.
Thank you for watching. Glad that you liked this Sallen Key differential amplifier circuit.
Thanks for watching. Here are more Sallen-Key Filter Design examples using Op Amps:
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ruclips.net/video/HeZRtnRXpEI/видео.html presents a circuit with op amps and feedback loops to design an analog computer that solves a second order differential equation.
For more analog signal processing examples see: ruclips.net/p/PLrwXF7N522y4c7c-8KBjrwd7IyaZfWxyt
I hope these Analog High-pass, Low-pass and Band-pass filter design and analysis examples are interesting and helpful.
You lost me at the end but I enjoyed the process anyway. Thanks.
Thanks for watching and sharing your feedback. Glad that you enjoyed the process and analysis of the circuit. At the end of this video I am conducting S domain pole-zero and Transfer Function analysis. Here are few more Sallen-Key Filter Design examples that might help:
Sallen-Key Filter Design ruclips.net/video/yHBsKTAn3VA/видео.html
Sallen-Key Transfer Function ruclips.net/video/LYARYxwUJgc/видео.html
Thanks again for watching. I hope the new video is helpful: How to find Bode Plot, Freq Response, Transfer Function of Analog Filters ruclips.net/video/vZFkPeDa1H8/видео.html . I hope you find it interesting as well. :)
I wouldn't know how to choose a suitable k factor. The RC time product is easy to choose if frequencies are given, though.
Well said about the RC time constant that is defined by the choice of cutoff frequency of the filter. A good choice for K=2 which translates to using same value for the two last resistors at the out put of the circuit. Otherwise the choice of K also affects the position of poles (roots of denominator of transfer function). I hope this is helpful.
@@STEMprof I'm trying to design a pipelined variant of the processor I designed, and, at some point, I devised a way to evaluate contention on resources such as the Arithmetic Logic Unit or memory access. Suddenly I thought of using digital-to-analog conversion so as to quickly evaluate contention and execute the instruction step with the highest value without resourcing to cumbersome, multiple, slow binary addition and comparation: a few op-amps and resistors would do. Like a set of neurons. Nothing similar to filters or PSUs, but in this case I think op-amps would do a wonderful job.