TO students wondering where part 1 of games and tournaments is - "Arey remove ni kiya hai. It was not games tournament , so removed from this topic." (Reply of sir to one of the comments asing where part 1 is. You can check it from the comments below)
After understanding this concept... I feel like playing this game, and I know I will definitely win the game by implementing your strategy sir.😁 Thank you so much for making it so easy for us. 🙏
Answer of 1st question must be 5 as 'A' must pick 5 coins to ensure that 1 coin is remaining which should be picked by 'B' later and ensuring A's win. Please someone verify.
If you want to win then then you need to follow the same pattern in all turns. In question A just ensure that if he leaves losing numbers in front of b then B will loose (So as per the 1st turn we can say A will win ) if A follows the same pattern in all his turns . A ensures his. wins in 1st turn that doesn't not mean there is no b wins if A do mistake in calculation regarding loosing number then B will be win
@@priyanshi26.lohiaaa you have to assume the other person playing the game is just as smart as you are, if you pick 6 out of 15 then 9 are left, out of the 9 the other person will select only 1 coin which would bring the the coins total to 8 , now at 8 whatever number we choose we cant win , for eg if we choose 6 then the other person will choose just 1 and if we choose 5 the other person will choose 3 making us pick the last coin in all cases possible
@@priyanshi26.lohiaaano no..if i pick 6, 9 would be left so other person would pick 1 then 8 is left now if i pick 6 2 would be left and that person would pick 1 so now 1 is left that I'll have to pick
Sir in the last question we should pick one first and give the chance to the second person .now he can take max upto 6 coins . ( if he does that there will be one coin left and i will win ) Now ,in the last ques you said you need 4 coins to be taken to ensure win .(for 60) According to the first logic ,it should be 3 right sir … Cuz for 8 coins , we should take one , pass the chance ,and take the rest of the coins in the second chance
Can you please explain me how 9 coins is a preferable no ?? If this is my turn I would pick 6 coins out of 9 coins .then 3 are remaining .thdn obviously the 2nd player would pick 2 coins ( as it is mentioned that both players are playing inteligently ) . The only 1 coin is remaining the I would lose the game
@@sarthakroy9594Making it simple..... See if there is 9 coins on the table and its ur chance ...u r intelligent 'yes u are' and u will pick only 1 coin so that u will leave 8 coins on the table ..... therefore whose ever chance is now and having 8 coins on the table will loose the game ....just think in cool mind If my msg helped u plz reply 😊
Sir I have a doubt In the 3rd Ques B can win, as assuming A & B both picking 6 coins each time, when its A's chance the 9th time if A picks 6 coins, the total coins picked will be 102, so B can pick 3 coins which makes a total of 105, so last coin is left for A can this be an answer or am I wrong.
Sir if 15 coins are there, I am A and u are B and if it's my chance then.... * A takes 6 coins first. ( 9 coins left for B) * B takes 6 ( 3 coins left for A) * A takes 2 coins ( 1 coin left for B) So for A, 15 is not loosing number right or for anyone whose chance comes first! Plzzzzzz reply
*A takes 6 coins first(9 coins left for B), *B takes 1 coin(8 coins left for A), if*A takes 2 coins(6 coins are left for B), *then B chooses to take 5 coins, and YOU(A) will be left with only one coin to choose. So you lose @AAMAN SAYEED
@@Deepakraj-ls2vk how can you strictly say he follow this pattern? .Both the players are playing intelligently??. it is possible that he can also win???
@@Abhijeetkr_2211 our moto to win is to make the opponent loose so when there are 9 coins on the table you'll pick two and making them 7 which is a loosing number for the opponent ! And that's how you win 😂
the problem is you picking 6. Cause we want the opponent to loose, so will pick 2 and making it 7 for the opponent. If we go by your logic, Then even 2-6 are unfavorable. suppose you have 5 coins, and then you pick 2. the opponent will also pick 2 and then at last you'll have to pick the last one , making you loose the game. :)
If there are 15coins left in table. So in this case, if I take 6coins then 9coins will left.to beat me, now 2nd person has to choose even nr. Of coins 2,4,6. Let's say he takes 6, now remaining coins are 3. So in this situation I will choose 2 coins.and finally only 1 is left which opponent has to take and in this way he will loose the game. Then why declared that 15 is not suitable nr for me?
mai khud direct question dekh kr comments mein dekhne aaya kahin kisi ne mention kiya ho 1st part ka link but i guess hai nhi koi introduction video bs yahin se start hai toh agr nhi aa rha smjh toh ek do baar aur isi ko dekh lo ya aage ke aur videos dekh lo smjh aa jaega
Sir 1to 6 coins mai se koi sa bhi coin le skte h toh 8 coins mai for example maine 6 coins liye jo hi last limit h toh 2 coins baki h jisme agar opposite individual ne 1 coin le liya toh dusra mujhe lena padhge aise toh 8 coin kaise suitable h sir please reply i cant understand and sir apki basic se games and tournaments nhi mil rha smjne m bhi dikkhat hori h
Hii Sir, your 1st question's answer is wrong, if he will bring the game upto 57 then 63-57=6 so he can pick 5 coins to ensure his win. If he pick 6 coins then picking up the last coin will lose right??
since he knew 8 coins is prey. A ll pick 1 and leaving opponent with 8 coins. Introspect the video again. sir mentioned both are playing intelligently.
I don't understand if A is standing at 57 he will loose right? But sir said he needs to pick 6 coins I don't get when? He needs to pick 6 coins ( are they taking it from backward because I'm trying to understand from forward)
The coins on the table are 63.. break down it to 57 for another person..it means i am picking 6 coins and 57 are left with another person which is a losing number so he will lose..
Can any one please explain that how 9 could be a preferable no. ?? See if out of 9 coins I choose 6 coins the 3 are reamining then obviously the 2nd player would pick 2 coins out of 3 . Then only 1 coin is remaining and I lose . Please can anyone explain me this ??
9 is preferable because when there are 9 coins and it's our turn we need to pick just 1 coin and then total coins will be 8 and then even if B pics 6 coin 2 will be remaning and we can pick 1 and B will loose because only 1 coin will be left. in other case supose B pick only 1 coin out of 8 then 7 will be remaning and we can pick 6 coin and 1 coin will be left and B will again loose that's why 9 is preferable.
TO students wondering where part 1 of games and tournaments is -
"Arey remove ni kiya hai. It was not games tournament , so removed from this topic."
(Reply of sir to one of the comments asing where part 1 is. You can check it from the comments below)
then where is the introduction concept of game and tournament bro? this is directly a set right? please help me with that link or thumb name
@@bhanuchakradhar1949 ruclips.net/video/Oy9ERJEboWY/видео.html .... I think this one is G&T 1
@@anonymous...45 thank u mehar, I will go through..
@@bhanuchakradhar1949 hey , have you found it ?
@@ayushiacharya6833 you got 1st video of this topic ?
common guys these guys are doing a fantastic job and they deserve more likes and subscribes ..
keep liking the videos .. cheers !!!!
Thank you sir for explaining this beautiful set, now i am able to calculate easily without pen and paper.
whenever rodha sir solve the que sir be like.. ( yaha to bhot maja aa raha , dil garden garden ho raha 😂)
Just fallen in love for ur explanation 💓💓💓💓💓💓💓
Sir aap na hote toh hamara kya hi hota
Dil se love you 💕
Sir i'm unable to find Part - 01,can you do something for part - 1
After understanding this concept... I feel like playing this game, and I know I will definitely win the game by implementing your strategy sir.😁
Thank you so much for making it so easy for us. 🙏
Answer of 1st question must be 5 as 'A' must pick 5 coins to ensure that 1 coin is remaining which should be picked by 'B' later and ensuring A's win. Please someone verify.
If you want to win then then you need to follow the same pattern in all turns. In question A just ensure that if he leaves losing numbers in front of b then B will loose (So as per the 1st turn we can say A will win ) if A follows the same pattern in all his turns . A ensures his. wins in 1st turn that doesn't not mean there is no b wins if A do mistake in calculation regarding loosing number then B will be win
AT 15 COINS IF I PICK 6, YOUR PICK 6 THEN I PICK 2 THEN YOU PICK 1 , THEN YOU WILL BE LOSER RIGHT HOW I AM LOSER?
@@priyanshi26.lohiaaa you have to assume the other person playing the game is just as smart as you are, if you pick 6 out of 15 then 9 are left, out of the 9 the other person will select only 1 coin which would bring the the coins total to 8 , now at 8 whatever number we choose we cant win , for eg if we choose 6 then the other person will choose just 1 and if we choose 5 the other person will choose 3 making us pick the last coin in all cases possible
sir swaaad aagya.....ab mai dates pe yeh trick play kiya krunga...thanks alot sir
Good question. But tough concept. Want to practice more questions
Can anyone tell me where can I find the first lecture of the same topic?
"Arey remove ni kiya hai. It was not games tournament , so removed from this topic."
Reply of sir to one of the comments asing where part 1 is
@@niranjan3869 AT 15 COINS IF I PICK 6, YOUR PICK 6 THEN I PICK 2 THEN YOU PICK 1 , THEN YOU WILL BE LOSER RIGHT HOW I AM LOSER?
@@priyanshi26.lohiaaano no..if i pick 6, 9 would be left so other person would pick 1 then 8 is left now if i pick 6 2 would be left and that person would pick 1 so now 1 is left that I'll have to pick
@@09anjalijayswalxa48 why other person picked 9 at second chance he could pick 6 also?
mind boggling beautiful concept
Sir in the last question we should pick one first and give the chance to the second person .now he can take max upto 6 coins . ( if he does that there will be one coin left and i will win )
Now ,in the last ques you said you need 4 coins to be taken to ensure win .(for 60)
According to the first logic ,it should be 3 right sir …
Cuz for 8 coins , we should take one , pass the chance ,and take the rest of the coins in the second chance
thank you sir after watching your videos what can i say concept dimag mai fit ho jate hai 🙌🏻
Well explained..... Doing great work!
Got this concept so easily.. thank you sirr ❤
Sir, thanks for such great effort. Kindly put on the games and tournaments 1st video as well.
Just removed first video because of wrong playlist
@@Rodha Ty so much sir for letting me know, wishing you a great day
sir, please REUPLOAD 1st part .
Best method i have ever seen 👍👍👍
Sir, Please upload Games & Tournaments Lecture 1 and also Maxima-Minima Lectures 3,4.
Did you find the 1st lecture?
Nicely explained..but we should be wise enough to leave these type of sets in exam..too intense
Yes I also think it is wise to leave these types of sets
Just use formula cf(n)+1
Very helpful concepts 👍
Thank you so much, Sir, I am very grateful to you!
sir earlier i hated lrdi but you helped me to do lrdi without boredom
Superb Sir, You are great
Thank you so much sir for this video. You have made the concept very clear for me by explaining in simple way.🙏🙏🙏
Can you please explain me how 9 coins is a preferable no ??
If this is my turn I would pick 6 coins out of 9 coins .then 3 are remaining .thdn obviously the 2nd player would pick 2 coins ( as it is mentioned that both players are playing inteligently ) . The only 1 coin is remaining the I would lose the game
@@sarthakroy9594Making it simple.....
See if there is 9 coins on the table and its ur chance ...u r intelligent 'yes u are' and u will pick only 1 coin so that u will leave 8 coins on the table ..... therefore whose ever chance is now and having 8 coins on the table will loose the game ....just think in cool mind
If my msg helped u plz reply 😊
Is this playlist enough to complete games and tournament for cat 2024
Before watching this playlist watch unacademy games and tournaments playlist by Belvi Srinivas sir😊😊
y?
Such a lovely concept❤
Hello sir, i guess part 1 is got deleted
where can I find the first concept video of game and tournament?
Hello sir, Please upload the Games and Tournaments Lecture 1 also
sir you explained everything so well that it all seemed so easy and interesting! thank you so much sir! you are awesome!!!!! ❤❤
Beautiful concept
Sir I have a doubt
In the 3rd Ques B can win, as assuming A & B both picking 6 coins each time, when its A's chance the 9th time if A picks 6 coins, the total coins picked will be 102, so B can pick 3 coins which makes a total of 105, so last coin is left for A
can this be an answer or am I wrong.
thankyou sir for providng wonderful session session......
Sir you are amazing great video sir
Quiet an interesting game
where is the first part to G and T ?
Sir where is part 1 of games and tournament
What should I do to get the introduction of this topic?
Banglore
The girl named lore:
reminds me of dynamic programming from engineering dsa , solving questions from base case, if anyone can relate :)
in the first question are we not talking about A's win but his chance to pick up the last coin?
hello! part 1 is not available to watch. can you do something about it? thanks
Did you got the first part?
When we write NEVER WINS I think we are assuming that other person is also aware of the trick.
Otherwise opponent can not know what to do.
Intelligently playing bola hai na
Sir please lecture 1 of games and tournament
22:24 amit shah meme reminder🔥
Aap kya baat kr rhe jaan de denge
Please can you upload games and tournament lecture 1.
where is the 1st video of games n tournamnet
where is games and tournaments 1 sir??? or it is the first video?
"Arey remove ni kiya hai. It was not games tournament , so removed from this topic."
Reply of sir to one of the comments asing where part 1 is
Thank you sir for the amazing set
sir the game and tournament part 1 is not available
Omg! I'm blessed!!!💫
Sir if 15 coins are there,
I am A and u are B and if it's my chance then....
* A takes 6 coins first.
( 9 coins left for B)
* B takes 6
( 3 coins left for A)
* A takes 2 coins
( 1 coin left for B)
So for A, 15 is not loosing number right or for anyone whose chance comes first!
Plzzzzzz reply
*A takes 6 coins first(9 coins left for B), *B takes 1 coin(8 coins left for A), if*A takes 2 coins(6 coins are left for B), *then B chooses to take 5 coins, and YOU(A) will be left with only one coin to choose. So you lose @AAMAN SAYEED
@@Deepakraj-ls2vk how can you strictly say he follow this pattern? .Both the players are playing intelligently??.
it is possible that he can also win???
Sorry but that player is intelligent
@@gokulk4644no matter how intelligent b will win.
sir is there a first video also?
Thank you 🎉 Sir
Amazing Explanation Sir❤❤❤💯💯💯
Where to find the first concept video ??
Can anyone explain how 4 coins came in question 4 like how we got that specific value
For 9 coins.. If I pick 6.. You pick 2 (assuming u are intelligent), then at the end I have to pick last 1 coin.. So how 9 is favorable for me?
You pick 6 first, it shows that you are not intelligent
Oh right👍
@@sauravmishra2716 can you please explain how choosing 9 is favourable ?
@@Abhijeetkr_2211 our moto to win is to make the opponent loose so when there are 9 coins on the table you'll pick two and making them 7 which is a loosing number for the opponent ! And that's how you win 😂
the problem is you picking 6. Cause we want the opponent to loose, so will pick 2 and making it 7 for the opponent. If we go by your logic, Then even 2-6 are unfavorable. suppose you have 5 coins, and then you pick 2. the opponent will also pick 2 and then at last you'll have to pick the last one , making you loose the game. :)
I don't understand for 9 coins if i take 6 other take 2 them i have to take 1 i will loose
If there are 15coins left in table.
So in this case, if I take 6coins then 9coins will left.to beat me, now 2nd person has to choose even nr. Of coins 2,4,6.
Let's say he takes 6, now remaining coins are 3.
So in this situation I will choose 2 coins.and finally only 1 is left which opponent has to take and in this way he will loose the game.
Then why declared that 15 is not suitable nr for me?
@SubhrD Deb ok you are true...I accept...
But assume both player plays intelligently,both play to win.So 15 is an advantage to opponent unless he make mistake
B will also play safe for this game
We have to assume that he will pick 1 coin from the 9 (only 1 will favour his win). In that case you are left with 8 and the same continues.
Very well explained!!💫
where is the part one? can anyone share the link?
This game really looks fun
SIR I CASE OF 9 COINS IF A Can pick 6 B will pick 2 then a has to pick so he can loose their please explain
why is it just 7k??? not 7k+1
the beauty of puzzle lies within, dive and get it
Thank you sir🙏
bhai aur kahase kr rho lrdi
Sirf Ravi Sir aur pyq
@@cumulusmusic100 1st lecture kha hai games and tournaments ka ye toh batao jra
@@Siddhant.theme222 bhai tum lrdi aur kahan se kar raahe ho?
@@cumulusmusic100is this playlist is sufficient for cat preparation
How to join whtsapp group?
where is basic of this topic???????
Yes i think it got deleted
Very good explanation.
where did the games and tournaments 1 go?
Numbering mistake
How come the answer of last question is 4 coin ?
Ek jgah 7k +1 aur ek jgah 7k q liya gya hai ? +1 q kiya first wale m ?
Could you please suggest a book for di and lr. Thankyou in advance
Sir please repost games and tournament 1 and allegation and mixtures 7 th video
Best explanation 👌
Yaar introduction video h hi nhi khuch smjh hi nhi aa rha h 😢😢direct ques. Se start ho gya h 😢😢
mai khud direct question dekh kr comments mein dekhne aaya kahin kisi ne mention kiya ho 1st part ka link but i guess hai nhi koi introduction video bs yahin se start hai toh agr nhi aa rha smjh toh ek do baar aur isi ko dekh lo ya aage ke aur videos dekh lo smjh aa jaega
just came across a comment she is saying the 1st part video was same as quant based puzzle no.-13 so sir removed it from here
@@FarhanAkhtar-w7h I go through a book for understanding the concepts.
Sir 1to 6 coins mai se koi sa bhi coin le skte h toh 8 coins mai for example maine 6 coins liye jo hi last limit h toh 2 coins baki h jisme agar opposite individual ne 1 coin le liya toh dusra mujhe lena padhge aise toh 8 coin kaise suitable h sir please reply i cant understand and sir apki basic se games and tournaments nhi mil rha smjne m bhi dikkhat hori h
Again saw this lecture you will find your answer
Ok
Part 1 is not there
Dynamic programming in coding
Where is the 1st part?
In another game we also take 7k+7 form
Hii Sir, your 1st question's answer is wrong, if he will bring the game upto 57 then 63-57=6 so he can pick 5 coins to ensure his win. If he pick 6 coins then picking up the last coin will lose right??
no if he picks 6 coins means 57 coins left for opponent. Its proven whom get no. in form of 7k+1 they will definitely loose the game
u interpreted wrong way. its not upto 57
@@DevendraSingh-hs1gj k. I got it👍
i also ve the same doubt...could you explain it?
@@shinekuttus 57 is the losing number so after 56 he will pick 6 coins which will end at 62 and the one who pick 63rd coin will lose.
Thank you
Sir how 12 is a winning no ?
It says 2, where is the part 1?
Hats off !!
Thank you sir
Rodha zindabad ❤️
12:07 i think even 9 is not a good nnumber because A can pick 6 then B will pick 1 and then A has to pick the last coim
since he knew 8 coins is prey. A ll pick 1 and leaving opponent with 8 coins. Introspect the video again. sir mentioned both are playing intelligently.
"CAN" here means he is dumb.
❣️
I don't understand if A is standing at 57 he will loose right? But sir said he needs to pick 6 coins I don't get when? He needs to pick 6 coins ( are they taking it from backward because I'm trying to understand from forward)
The coins on the table are 63.. break down it to 57 for another person..it means i am picking 6 coins and 57 are left with another person which is a losing number so he will lose..
No limit of making foolishness🤣🤣🤣 at 6:00
How it can be foolish
Can any one please explain that how 9 could be a preferable no. ??
See if out of 9 coins I choose 6 coins the 3 are reamining then obviously the 2nd player would pick 2 coins out of 3 . Then only 1 coin is remaining and I lose .
Please can anyone explain me this ??
9 is preferable because when there are 9 coins and it's our turn we need to pick just 1 coin and then total coins will be 8 and then even if B pics 6 coin 2 will be remaning and we can pick 1 and B will loose because only 1 coin will be left. in other case supose B pick only 1 coin out of 8 then 7 will be remaning and we can pick 6 coin and 1 coin will be left and B will again loose that's why 9 is preferable.
Thanks a lot
Thank you❤❤❤❤❤❤