No, that's only for sin and cosine. If it makes sense, the reason it's pi on the top is because you can only travel π around the unit circle before tan is undefined (π to 3π/2). Hope this makes sense
Missing a lot, you should do 1/4 of the period instead of 1/2, if you did that it would be very easy to explain what the Amplitude is doing in cotangent and tangent. If you a base cotx you know your start is at 0 and end is at pi. At pi/4 you have (0, 1), at pi/2 you have (0, 0), and at 3pi/4 you have (0, -1). If youre given 2cotx then your points at pi/4 and 3pi/4 would be (0,2) and (0, -2) respectively. So the amplitude (A) when it comes to cot and tan simply sets the y corsinate for each of those point equal to A.
In the beginning of the video he said the critical points were from diving the period by 2. The period was pi/2 so wouldn't the critical points thing be pi/4?
your asymptote for pi/four is wrong. it should be pi/2. you're negative asymptote is right
yes I have it written correctly above, guess I just had a brain fart when graphing
thank you brian
whats the use of 2?
thank you teacherr im already know cosx sinx tanx cotx because of you thank alot teacher
To find the period, dont you have to use 2pi/B?
No, that's only for sin and cosine. If it makes sense, the reason it's pi on the top is because you can only travel π around the unit circle before tan is undefined (π to 3π/2). Hope this makes sense
Missing a lot, you should do 1/4 of the period instead of 1/2, if you did that it would be very easy to explain what the Amplitude is doing in cotangent and tangent. If you a base cotx you know your start is at 0 and end is at pi. At pi/4 you have (0, 1), at pi/2 you have (0, 0), and at 3pi/4 you have (0, -1). If youre given 2cotx then your points at pi/4 and 3pi/4 would be (0,2) and (0, -2) respectively. So the amplitude (A) when it comes to cot and tan simply sets the y corsinate for each of those point equal to A.
This was a very helpful lecture :) thank you sir.
you are very welcome! happy to help
you had it right the first time. it was 5π/2 not 5π/4
Why wouldn't the x increments be pi/4
you could do it that way, I prefer to graph tan and cot in increments of 2 rather than 4
Wait, how did we find the asymptotes again? And since the start is at pi/2, why do we have to start at zero?
the initial period of cotangent has asymptotes at 0 and pi/2 and they continue +/- pi
In the beginning of the video he said the critical points were from diving the period by 2. The period was pi/2 so wouldn't the critical points thing be pi/4?
yes but there is a transformation of pi/2
wait why did he divide pi/2?
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