Magnetic Flux and Flux Linkage

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  • Опубликовано: 7 дек 2020
  • An introduction to magnetic flux and flux linkage

Комментарии • 17

  • @dominicestebanrice7460
    @dominicestebanrice7460 7 месяцев назад +1

    Concise yet comprehensive. Excellent. Thank you!

  • @Rishi-Singh_
    @Rishi-Singh_ Год назад

    Thank you Sir
    Love from India 🇮🇳

  • @DimuthuYapa
    @DimuthuYapa Год назад

    Thank you, sir.

  • @lopedomoiben5236
    @lopedomoiben5236 Год назад

    Thank you teacher

  • @imranhossain1124
    @imranhossain1124 2 года назад +2

    Do it for internal inductance of coaxial cable

  • @bard_x86
    @bard_x86 7 месяцев назад +1

    i didn't understand the term "flux linkage" now its crytal clear

  • @niezam07
    @niezam07 2 года назад +1

    @ 1:51 to calculate magnetic flux linkage is simply multiply magnetic flux with number or turn.
    my question is, does the bigger winding wire have a higher magnetic flux? eg. if we use bigger wire so we can reduced the number of turn?
    just like what we've seen in electric motor with a hairpin winding.

    • @harshdev9312
      @harshdev9312 2 года назад +1

      bigger windings then more flux so less no of windings needed

  • @chandranibharay416
    @chandranibharay416 3 года назад +3

    For magnetic field linkage the symbol is Psi (ψ).

    • @Brono25
      @Brono25 3 года назад +6

      In electrical engineering I've only seen it represented as lambda

    • @chandranibharay416
      @chandranibharay416 3 года назад +2

      @@Brono25 I have also studied Electrical Engineering.You can use both Lambda and Psi though. No issues

  • @gauthamworld
    @gauthamworld 3 года назад +1

    by your definition of flux linkage, the flux linkage of a coil with N number of turns will be the same irrespective of whether the turns are wound on a ferrmomagnetic solid core or around a hollow core.. .is that true? I guess if the core material is changing, then flux density will be different based on the core, and so flux linkage may be different?

    • @harshdev9312
      @harshdev9312 2 года назад +1

      yes precisely thats the answer to your question

  • @lifeasagamer7018
    @lifeasagamer7018 Год назад +2

    why did u divide the area by 4?

    • @nawfaljafri
      @nawfaljafri Год назад +1

      if im right, i think its because area = pi*r^2 but we have distance so area = pi*(d/2)^2 = [pi*(d^2)]/2^2 = [pi*(d^2)] /4
      if it seems confusing on text, just the numbers I wrote but without the awkward * and ^ and 'division but in one line' going on and it'll make sense

  • @mooodlemip4779
    @mooodlemip4779 6 месяцев назад

    My textbook uses sin instead of cos. How do I know which one to use and when?

    • @JosephBidenator
      @JosephBidenator 5 месяцев назад

      the cos is used when the area and the magnetic field lines are perpendicular to each other, and we take the normal to the area, and we compare the normal line of the area to the magnetic field lines.