@@coolwinder No, is not. The gain factor on a Jfet is its transconductance and it is dependent of the current in the drain. The gain of the first excercise explained is Vout = Vin*gm*R ... all this assuming it is not connected to any load in witch case the final expression will be Vout = Vin*gm*(R//Rl). One more thing, you might see gm as Yfs. Same thing, different name.
This was so much fun! Pls continue :)
The circuit on the left is source degenerated so the effective gm will be gm/(1+gmR). And the gain will be gm effective *ro
@pragz92 my answer is the same as You
sir make more questions like this
You're wrong! The small signal voltage gain of that circuit is not equal to zero.
It's not wrong, check this video: ruclips.net/video/P0OjpBJsLOE/видео.html
It is correct. Unless the model is different then the one showed. Pls grasp whats your model.
@@coolwinder Totally nonsense!
@@coolwinder No, is not. The gain factor on a Jfet is its transconductance and it is dependent of the current in the drain. The gain of the first excercise explained is Vout = Vin*gm*R ... all this assuming it is not connected to any load in witch case the final expression will be Vout = Vin*gm*(R//Rl). One more thing, you might see gm as Yfs. Same thing, different name.
I support ur channel.
Plz upload circuit design related videos for interviews
Hi Shanmukha, check us out for engineering interview related questions. We'd love to hear your feedback! ruclips.net/channel/UC7h3PROcX7Zgx00alQokJ-w
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I am New, thank you😊
vout2/vin=Av=GM*Rout=-gm1*ro...answer
vout1/vin=gm/1+gmRs..answer
vout/vin=GM*Rout=0..answer