This problem can also be solve by using formula of hydrolysis of salt of weak acid and strong base. Since CH3COONa is a salt of weak acid and strong base. Formula is PH=1/2 of Pkw +1/2 of Pka +1/2 of log C. Here all the data has been given. C is concentration of salt. Pka = - log(ka). Just put all data and get answer PH =9
Thank u a lot mam..... I tried to learn this concept many time , though I am unable to solve these questions..... After this seeing this video ,I could understand it very clearly mam. Thank u sooo much mam😊😊
@@sripoojithatallapelly6041 (H+)= ch= c(Kw/c. Kb)^1/2. Then take negative log for both sides then u will get pH= 1/2(pKw-pkb-log c). This is for strong acid and weak base
Mam Thank you so much....1st i used to feel somewhat confused but now concept has clear. Mam Once again THANK YOU. How to thank you I don't no. But in Telugu to say. Hrudayapoorvaka Vandanalu. .
thankyou....thanks a lot mam...U r amazing. really vry vry helpful video to me. I watched previous video of this whr u explained us complt topic . wish u could even teach physics to me...WITH LOTS OF LOVE FROM TELANGANA...
Hey mam how r u? Actually I want to ask you about how to reduce negative marks in neet test . I usually come up with 11-13 questions wrong in chemistry every time I give a mock test.plz guide.🤓🙏 I want to get good rank in neet
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Mam pls do a vedio on buffer solutions
This problem can also be solve by using formula of hydrolysis of salt of weak acid and strong base. Since CH3COONa is a salt of weak acid and strong base. Formula is
PH=1/2 of Pkw +1/2 of Pka +1/2 of log C. Here all the data has been given. C is concentration of salt. Pka = - log(ka). Just put all data and get answer PH =9
Thank you brother
But its coming as 8.20 then!
@@aakash_405no we will be getting 9
Such a Amazing way of teaching
Thanks mam for uploading everything in a correct time
Thank u a lot mam..... I tried to learn this concept many time , though I am unable to solve these questions..... After this seeing this video ,I could understand it very clearly mam. Thank u sooo much mam😊😊
Mam we can Also use ph formula for strong bases and weak Acids which is given by u in previous video and get the answer in short steps mam
Same doubt mam
Thanks ma'am for ur support... Really v help full
YOU ARE THE BEST CHEMISTRY TEACHER MAM!__THANKS A LOT__.💝
Mam for this question can we use pH=7+1/2Pka+1/2logc
Yes I did the same and I got 9 as the answer
Yes
Can u explain how u got tht ?
@@sripoojithatallapelly6041 (H+)= ch= c(Kw/c. Kb)^1/2. Then take negative log for both sides then u will get pH= 1/2(pKw-pkb-log c). This is for strong acid and weak base
Mam you cleared my confusion totally you really nailed it. Love you😍 mam I wish if I could meet you. You are amazing🤩 and I am lucky to have you.
Good explanation mam , chemistry expert
This topic is clear mam
happy republic day mam 🇮🇳
Really excellent mam...thank u soo much..
Thank u so much mam........ I understood clearly after seeing ur videos 😄😄😄😄😄💐💐💐💐💐💐
Teacher I liked your explanation ❤
Always great
Mam Thank you so much....1st i used to feel somewhat confused but now concept has clear. Mam Once again THANK YOU. How to thank you I don't no. But in Telugu to say. Hrudayapoorvaka Vandanalu. .
Mam please provide video on buffer...
Thanks mam u r the best ever 💞😘💞
Dear Komali Mam,
Infinite thanks could not explain my gratitude towards you....
Thank you so much for your support....
thankyou....thanks a lot mam...U r amazing. really vry vry helpful video to me. I watched previous video of this whr u explained us complt topic . wish u could even teach physics to me...WITH LOTS OF LOVE FROM TELANGANA...
Nyc video
Wow!
Awesome mam..
Thanks a lot for these lectures!!!
🙏🏻❤
Nice teaching....
U r great maam.
Thank you so much Mam for clearing all my doubts regarding this topic
Mam direct formula
PH =7+pKa+logC...🙏
Mam, can I use the ph formula for salt of weak acid and strong base (ph=7+1/2pka+1/2log C) for this question
S bro same answer will come
There how we have to calculate pka bro
Yeah u can
@@revanth..3711 pka= -log ka
Matha ki Jai..🇮🇳 bharath matha ki Jai🇮🇳 chemistry maatha ki Jai....😁💖 Happy republic day chemistry maatha...💕💕
I think students forget to give like bcoz they r so busy is watching faltu videos....
Again big thank u mam ♥
Ma'am thank you very much.
Thank you mam💓💖
Mam why can't we use 7+1/2ka +1/2logc
A lot of thanks mam
Hi
Mamdam plz send a video on how to find bond length
Mam can't we solve this question with the other formulae you gave for WA & SB?? I got 9.7 with that.
i too did tat in the same way ..i got 9.694 as ans....since there is no value near 10 choosing 9 is appropriate...i hope so
Thank u so much mam u helped me a lot 💐💐
Excellent
Thank you mam.....Plz make more videos
Thanks mam it really helped me!!
Thank u Mam.
My answer was correct 🤠
Mam ...this question is from acidic buffer.....isn't it? ..can we use direct formula to find pH reply.....
Tq you somuch mam🌞🌞🌞
Thnq mam. Wowed!!!
Mam, can we use the pH formula for salt of weak acid and strong base directly in this question??
thats what i wanted too know too..
Yeah.. me too.. In formula,
Ph= 7+1/2(pka+logc)..
I substituted, and got approximately 9.02... is it correct and time saving or wrong method?
@@tamilmathi1885 adhuvum crct dha nu nenaikaren :)
@@tamilmathi1885 how u got 9.02 ?? Igot only7.3
mam what formula should we take for Kh value in weak acid and weak base
Since it doesn't depend upon concentration it is equal to pkw +pka-pkb the whole by 2
Thank you very much mam
Tqqqqqqq mam u cleared my concept
Mam what is h in ch mam? What does it indicate?
Mam why can't we use formula directly.. Plz tell
I also have this doubt.??????
Can use
Thanks for this question
Hey mam how r u?
Actually I want to ask you about how to reduce negative marks in neet test . I usually come up with 11-13 questions wrong in chemistry every time I give a mock test.plz guide.🤓🙏 I want to get good rank in neet
Why in this qn not use that formula previous video
Please explain. How to find ph of 0.1N H2SO4
Thank you mam
Thank u so much mam
Mam tq u....
Tq so much mam
Why strong do not react??
Tq mam but in exams they will not give log value how to do
Orelse how much value i shld rmbr plz help me mam
1 to 10 are must but after this you can solve log by some formula like you are finding for log of 15 then log15=log(5×3)
log(5×3)=log5+log3~1.18
I got 9.449 as the answer. So, option 2.
Thanks mam but mam plz guide for viva of practical which is on 29 chemistry class 12
Thanks mam
What's the trick u have said here. 😊
Vera lvl
🙏🙏🙏🙏🙏
Need notes on diels alder reaction mam
Nice mam but please speak little bit in hindi because i am student of hindi medium because many student watch your video belong from hindi medium
Sorry, many of them watching video from many state . So being English better
I don't know Hindi. So I can't help 😊
Its ok mam
@@KomaliMam English is ok
@@Linges-dm8dw it's good don't worry of it u please keep upload videos for our better education
Answer is 9
Please give answer mam
It's taking too much of time mam
Teacher I liked your explanation ❤
Thank you so much mam