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And the problem is in the first step - x = u^(-1/n). Hope it will be find out in the next part of the video ;D 1:40
That’s just a typo, the rest is valid
How did you go from a positive 1/N to a negative 1/N during the t-substitution?
compare 2:48 to 3:17
Looks like Dr Peyam is back with his integrals!!
Yaaaay!!
And the problem is in the first step - x = u^(-1/n). Hope it will be find out in the next part of the video ;D 1:40
That’s just a typo, the rest is valid
How did you go from a positive 1/N to a negative 1/N during the t-substitution?
compare 2:48 to 3:17
Looks like Dr Peyam is back with his integrals!!
Yaaaay!!