Decibels Explained

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  • Опубликовано: 12 сен 2024

Комментарии • 39

  • @DarthCoco
    @DarthCoco 3 года назад +5

    This is one of those videos that explains things simply and shortly, as promised by the title and thumbnail. Thank you.

  • @JackMooney
    @JackMooney 3 года назад +2

    I watched a few other videos on this topic, including linustechtips and I was still so confused because those videos bombarded you with all this heavy information that makes it difficult to absorb and understand. But this tutorial broke it down simply, explained it slowly, and presented it perfectly and I now I finally understand the unit of decibels.
    Thank you for tutorials like this!

  • @lyanporto
    @lyanporto 3 года назад +2

    Best video on the topic I've seen yet.

  • @scienceblossom6197
    @scienceblossom6197 4 года назад +2

    Best explanation ever! You're such an amazing teacher! Thank you a lot ♥️ !

  • @Automan9
    @Automan9 3 года назад +4

    This is by FAR, the best concise explanation to the quirks of Decibels I've seen. Here I was wondering if I was retarded, not understanding while watching Techquickie's video. Either Linus doesn't understand it himself, or he's terrible at explaining.
    This was so perfect I got it almost immediately, thanks a lot.

    • @rodolforla
      @rodolforla 3 года назад +1

      Exactly! i felt the same thing haha It is interesting how a good approach make us learn really fast, and also the oppositive..

  • @katnisseverdeen4112
    @katnisseverdeen4112 3 года назад

    This is the only video that helped me understand anything about decibels, but I needed to know about db in relation with radiation, not sound 😭😭😭

  • @eunhyeokchoi6257
    @eunhyeokchoi6257 5 месяцев назад

    Hello, thank you for the video. But I have one question I would like to ask. In the pressure-time graph of the Dynamic Range of Sound, how can a pressure be negative? What is the unit used for this graph? thank you in advance.

  • @curtpiazza1688
    @curtpiazza1688 2 года назад +1

    Great quick lesson! Thanx!

  • @rickvia8435
    @rickvia8435 2 года назад

    So does that equate to 6 dB as a doubling of SPL? I know that in measuring electrical power levels an increase of 3 dB is doubling of power.

  • @donniexl1033
    @donniexl1033 3 года назад +1

    For sure the best explanation

    • @TechiTube
      @TechiTube  3 года назад

      Glad it was helpful!

  • @holdendp
    @holdendp 3 года назад +1

    Great explanation. Thank you.

    • @TechiTube
      @TechiTube  3 года назад

      Glad you enjoyed it!

  • @stephanhan.8390
    @stephanhan.8390 3 года назад +1

    Best explanation ever!

  • @yazan770
    @yazan770 3 года назад +1

    Thank you very much!

  • @muminjonurmanov9911
    @muminjonurmanov9911 3 года назад +1

    Thanks a lot

  • @David_four_twenty
    @David_four_twenty 4 года назад +1

    Wonderful work thank you.

  • @ksanaajith6276
    @ksanaajith6276 4 года назад +1

    Thank you...super video

  • @danielolivera2618
    @danielolivera2618 3 года назад

    senior at a university, barely learning what it actually is.

  • @markgreco1962
    @markgreco1962 3 года назад

    Thanks

  • @ardiakirana
    @ardiakirana 4 года назад +1

    Thanks brother

  • @marouanekenjix
    @marouanekenjix 3 года назад

    l3azz khouya

  • @andilegqwaru2854
    @andilegqwaru2854 4 года назад +1

    Doubling identical sound sources increase sound by 3dB not 6dB

    • @TechiTube
      @TechiTube  3 года назад +1

      Sorry, but that is not true
      The sound pressure level (dB SPL) is defined as: 20 log10 (s1/s0) where s1 is the measured sound pressure level of a given sound, and s0 is a reference value. I showed this in 2min:55sec. This means that doubling identical sound source increases sound by 6dB.
      20 log10 (2*p1/p0) = 20 log10 (p1/p0) + 6dB.
      The 3dB you mentioned will be true if the sound we are measuring is power in that case we would have used 10 log10 (p1/p0) but the sound pressure level is not power. It is an amplitude. The correct formula is then 20 log10 (s1/s0)

  • @tone8301
    @tone8301 3 года назад

    I wonder if Dr. Dre knows this

  • @MrTitusDenis
    @MrTitusDenis 3 года назад

    Whoa whoa… hold on… you say “sound with 40dB isn’t necessarily louder than sound with 20dB.” But in the next statement you ambiguously reinstate that “sound with 40dB is 10 times louder than 20dB.” Which statement is true now?

    • @TechiTube
      @TechiTube  3 года назад

      Yes I did say "Sound with 40dB is 10 times louder than 20dB." However I never said "sound with 40dB isn’t necessarily louder than sound with 20dB." Watch the video one more time 🙂.

    • @MrTitusDenis
      @MrTitusDenis 3 года назад

      @@TechiTube “necessarily?” Meaning 40dB sound is factually louder than 20dB but not noticeable. So I must say the word you are looking for is “noticeably”.