Calculus 1.4 The Limit of a Function
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- Опубликовано: 8 фев 2025
- The limit of a function (or its INTENDED height) is a very important concept in calculus. In this lesson I will make it very clear what left and right handed limits are, how to evaluate them and introduce the concept of continuity (more on that later in the chapter).
For those of you who would like to have a copy of the exercises that I work with at the end of the video here they are!
mshavrot.pbwork...
mshavrot.pbwork...
Hello Ms.Havrot thank you so much for everything I took advanced functions in grade 11 and my teacher wasn't the greatest but you helped me get over a 90. Now I'm taking calculus and you've been a great help so far, thank you so much.
Wonderful! You must be working hard to get such a good mark. Keep it up. Calculus is fun! 🤩 Thanks for watching my lessons 😊
Thanks mommy Havrot! I aced my test because of you!
I have often had students call me mom … but never mommy 😂
Helping us pass calculus amidst a pandemic. We love you so much! ❤️❤️❤️
Literally saving my life thankss
Tell all of your friends, cousins, neighbours! And get them to subscribe! : )
ily ms havrot
hi ms havrot im back at it again ive been so lost in calc this was sooo helpful
Don’t forget to watch every day. Sometimes you think it’s going well but you may have missed some key concepts. Calculus is not hard!
Great explanation Ms, thank you
You are welcome! Please make sure to subscribe, like and share to increase the channel's visibility.
Best math youtube channel thank you!
Happy that you are finding it helpful! 😊
Well explained
Hi Ms. Havrot, how do you define the Limit of a piecewise function if it is only composed of points? For example, Pg.38 #5 of the calculus and vectors textbook?
In this case you are given a piece wise function where as you approach 4 from both left and right the y value is 1 therefore the limit as x approaches 4 is 1. It doesn’t matter that the actual value when x = 4 is -1.
Thank you so much!
Greetings Miss Havort, I am watching this to get ready for my next semester class in calcalus, any tips or advice?
I would stay one class ahead of the teacher so you can follow along in class more easily. It’s possible that they may start with vectors as the two parts are independent of one another.
Thanks@@mshavrotscanadianuniversit6234
9x - 7i > 3(3x - 7u)
Can you solve the inequality in respect to i? Thanks, I've been stuck at this problem for so long
Expand first
9x-7i > 9x-21u the 9xs cancel out
-7i > -21u divide by -7 both sides and change the direction of the inequality
i < 21/7 u
i < 3u
Check the answer :D@@mshavrotscanadianuniversit6234
@@mshavrotscanadianuniversit6234 Are you sure that's right? Check the answer again :D Thanks for the videos Ms. Havrot for my entire mathematics career at high school! (excl Grade 9)
Did you have a different solution? Is this a textbook question? I don’t see anything wrong with my calculation.
It's "I
Is it possible to post a pdf of the handout you used later in the video for the examples? thank you
Thanks for asking for this. I have included them in the description of the video so that you can download them. I did an extra sheet as well.
mshavrot.pbworks.com/w/file/fetch/144084768/1.4%20Limits%20exercise.pdf
mshavrot.pbworks.com/w/file/fetch/144084771/IMG_0253.pdf
Thank You for this, but I have a question. My question is; when you are finding the limit for the x of a function, is it basically the y-value that we are finding for x?
It’s a bit more complicated than that but for polynomials it is exactly what you are saying.
Ms. Havrot, if it is possible can you please send the pdf version of this worksheet at 8:39 thank you
It came from this textbook … page 26/84 (or page 13 of the textbook)
prius60.com/usr/uploads/2018/09/1517672165.pdf
THANK YOUUUU
You are most welcome! Enjoy the videos. I’m here to help 😊
thanks a lot for your vids
That will be covered in 1.5, hopefully today!
Hi Ms Havrot, would you be able to do page 38 of the textbook question 5 please (it’s a bit hard to write out since it’s a piecewise function)? I just need a little bit of help on it since I got it for homework. This question is related to this topic so that why I asked here since I’m a bit stumped.
If you were to graph this function you would have the line at y = 1 EXCEPT when x=4 where there would be an open circle and a dot at (4, -1). That means that as x approaches 4 from the left the limit is one and when x approaches 4 from the right the limit is one. Therefore the limit exists and it is 1. Now f(4)=-1 so that means that the function is not continuous and in fact there is a hole when X =4
@@mshavrotscanadianuniversit6234 oh ok, thank you, sometimes the ones with discontinuity are a bit confusing.
Which textbook is this from???
Nelson ... if your school is using McGraw Hill you should find the sequence very similar. Both cover the Ontario curriculum requirements .
Helping us pass calculus amidst a pandemic. We love you so much! ❤️❤️❤️
Thanks for watching! I'm sure everything will be clear if you keep watching, listening to your teacher and doing your homework!