great! my lecturer would only explain it on the powerpoint slide and its hard to get you know. its math you have to show the workflow like you did! thanks!
John Martinez It's the inverse rule. He took the inverse of (-1/y) which is basically (1/-1/y) which you just swap the top and bottom and that becomes just -y then he had a do the exact same thing to the other side and multiply both sides my negative one to have it y= instead of -y=
Basically, if you have something on the denominator on one side and move it to the other side it will be in the numerator position. That leaves you with 1/y is equal to whatever. Because we want you to be the subject and not 1/y, you reciprocate both sides.
for a question on my homework it asks on which interval is the solution defined. My professor said it is the largest interval that contains the initial value on which the solution is continuous. ANd the he showed me an example that didn't make sense: 1/(x-3)^2, y(0)=5 is (-infty, 3), but 1/(x-3)^2, y(4)=2 is (3,infty). I don't understand. Can you show me how to find the interval on the example of this video? Or the example my professor gave me. Please help I'm screwed otherwise.
dy/y^2 can be rewritten as (1/y^2)dy and then as y^-2*dy. So integrate y^-2*dy and you have -y^-1 or -1/y
Thank you u r legend mate
Yes
You are correct
Thank you so much
Great! Best of luck with the AP exam. The phrasing of these questions can vary a bit as it depends on an author's writing style.
great! my lecturer would only explain it on the powerpoint slide and its hard to get you know. its math you have to show the workflow like you did! thanks!
This video alone made me understand IVP's. Thank you so much.
Dr. Chris T, you are another professor for all students. 👍
Finally! someone can explain it simple enough for me to understand
THANK YOU, you saved me one day before my calc test!!
saved me two hours before mine! i know to start study earlier next time..
Could you please put the time in the video that you are referring to?
Dude, I've been trying to figure out how to solve IVPs for a couple weeks and in four minutes everything made sense. H O W
Best maths talent Chris Tisdell!!
why do you only get a +C on one side if you intergrate both??
That is the worst capital E I have ever seen in my life.
I was looking without a sound and was thinking "what the heck is ODK?"
Thank goodness. It's your life.
I understood it pretty well.
Its like an E fucked a K and thats the abomination that came out. lol
@@chrisgraham5963 Hahahhahaha that's so true
how about that x
What is the 'ODE' (I think that's what you said) at 0:10? I haven't heard that term before.
Ordinary Differential Equation
It's like watching Doctor Who, but the Doctor actually takes the time to explain things in a meaningful and helpful way. Thank you!
can i knw where is the y sqrt 2 goes???
How did dh/y2 turn to -1/y
The ivp dy/dx=3y^(2/3) ,y(0)=0
Does the ivp has two solutions or infinitely many solutions?
Please reply
how did you go from 2:00 - 2:25? I'm confused.
John Martinez It's the inverse rule. He took the inverse of (-1/y) which is basically (1/-1/y) which you just swap the top and bottom and that becomes just -y then he had a do the exact same thing to the other side and multiply both sides my negative one to have it y= instead of -y=
+John Martinez
All he did was multiply "y" to both sides and then divided (x+(1/3)x^3+c) on both sides.
Basically, if you have something on the denominator on one side and move it to the other side it will be in the numerator position. That leaves you with 1/y is equal to whatever. Because we want you to be the subject and not 1/y, you reciprocate both sides.
I solved that question myself
I searched cause I didn't understood the concept but you taught so well
Hi - I can't understand your question. Could you rephrase it please?
for a question on my homework it asks on which interval is the solution defined. My professor said it is the largest interval that contains the initial value on which the solution is continuous. ANd the he showed me an example that didn't make sense: 1/(x-3)^2, y(0)=5 is (-infty, 3), but 1/(x-3)^2, y(4)=2 is (3,infty). I don't understand. Can you show me how to find the interval on the example of this video? Or the example my professor gave me. Please help I'm screwed otherwise.
how does the square root of Y become Y???
This guy has balls.
this video is the best
Thank you so much.
Talos bless you kind sir.
thank you very much. It is very useful for me.
what is ODk?
It’s ode ordinary differential equation
Thanks. Understand it completely.
Thank you so much sir!
beton yetmez abi
3 minute video that's equivalent to at least 2 lectures.
Thank you!
you absolute mad lad
wow great stuff thank you
I wish u were my diff prof
Thanks
1.17 to 1.56
Just here to learn what "Solve for IVP mean" because my professor didn't explain what it means. It just means solve for c
Great! Thanks!
Cx
Kindly solve this one--- y''-2y'+y=0 , y(0)=0, y'(0)=1
Thanks sir
Helped me solve a problem that had two variable! Thanks
beautiful
Who wants to do my homework for some money!!!
me...hahaha..loss of money
You really couldn't get the entire page in the screen. You had one job.
It's a balance between size of font and amount of text on the screen. If the font is too small then it's impossible to read on mobile devices.
Thank you so much.