Thank you, Professor! Even though the the aim of the video to explain how to code the map, you could also point out the Feigenbaum constant after plotting.
I set up my code so I could also look at -r values and the results are interesting. The doubling period begins at Xss = 0 for -r values rather than Xss = 0.6 for +r values. Things seem to go to infinity r4. Thank you for sharing!!
Matlab Code below is more understandable for this video. In the code, I just obtained steady-state portion. X matrice is composed of Nn rows samples and Nr rows for bifurcation parameters. Matlab Code: n = linspace(1,100); Nn = length(n); r = 0:0.005:4; Nr = length(r); x = zeros(Nn,Nr); x(1,:) = 0.5; count = 0; for r = 0:0.005:4.0-0.005 for n = 1:Nn-1 x(n+1,count+1) = r*x(n,count+1)*(1 - x(n,count+1)); end plot(r*ones(31,1),x(70:Nn,count+1), '.', 'markersize', 2); hold on; count = count+1; end title('Bifurcation diagram of the logistic map'); xlabel('r'); ylabel('x_n'); set(gca, 'xlim', [0 4.0]); hold off;
Sir once we convert the koopman model to bilinear form then how can we confirm that we had done right conversion from state space to bilinear using Koopman canonical transformation
Hard to follow along with his screen. When I tried on my end, I got "invalid espression." Obviously I need to input more information but it has been so long that I worked with MATLAB that I have forgotten how to use this program.
Hi thank you for your useful video. I'm starting to learn Programming. I have a doubt about ''.. cut out transient.. for i=1:2000...'' I'm not actually understand how it work. Any suggestions appreciated.
how to calculate the lyapunov exponent for 3 or 4 dimensions. for example: x(1) = 0.8109; y(1) = 0.3342; z(1) = 0.5734; lamda = 3.789; beta = 0.029;alpha = 0.0224; for i = 1:2000 x(i+1)=lamda*x(i)*(1-x(i))+beta*((y(i)).^2)*x(i)+alpha*((z(i)).^3); y(i+1)=lamda*y(i)*(1-y(i))+beta*((z(i)).^2)*y(i)+alpha*((x(i)).^3); z(i+1)=lamda*z(i)*(1-z(i))+beta*((z(i)).^2)*z(i)+alpha*((y(i)).^3); end Kindly help me for this. I am using this in my research work. I will be than full to you.
![Chino Pacas - Modo Capone (with Drake & Fuerza Regida) [Video Oficial]](http://i.ytimg.com/vi/zjv8TQ0gBkg/mqdefault.jpg)
One of the best tutorials I have ever seen. Thank you.
Smart way to store steady state Thankyou very much sir. I'm trying it right now.
Thanks!
Thank you, Professor!
Even though the the aim of the video to explain how to code the map, you could also point out the Feigenbaum constant after plotting.
I set up my code so I could also look at -r values and the results are interesting. The doubling period begins at Xss = 0 for -r values rather than Xss = 0.6 for +r values. Things seem to go to infinity r4. Thank you for sharing!!
Matlab Code below is more understandable for this video. In the code, I just obtained steady-state portion. X matrice is composed of Nn rows samples and Nr rows for bifurcation parameters.
Matlab Code:
n = linspace(1,100);
Nn = length(n);
r = 0:0.005:4;
Nr = length(r);
x = zeros(Nn,Nr);
x(1,:) = 0.5;
count = 0;
for r = 0:0.005:4.0-0.005
for n = 1:Nn-1
x(n+1,count+1) = r*x(n,count+1)*(1 - x(n,count+1));
end
plot(r*ones(31,1),x(70:Nn,count+1), '.', 'markersize', 2);
hold on;
count = count+1;
end
title('Bifurcation diagram of the logistic map');
xlabel('r'); ylabel('x_n');
set(gca, 'xlim', [0 4.0]);
hold off;
Thanks!! Really helpful for my thesis.
Thank you for this video ! But I don't understand why there are 2 loops for the computing of x(k)...
Sir once we convert the koopman model to bilinear form then how can we confirm that we had done right conversion from state space to bilinear using Koopman canonical transformation
Great video Steve. I would be glad if you could do a video on how to reduce 3D system using center manifold with Matlab or Mathematica.
Many thanks, very clear explanation :D
is there a reason for the first imbedded for loop?
Excellent video, thankyou!
Aside from the lessons, I also want to learn how the video was done --- I mean how could he project the image on his laptop onto the glass blackboard?
Hard to follow along with his screen. When I tried on my end, I got "invalid espression." Obviously I need to input more information but it has been so long that I worked with MATLAB that I have forgotten how to use this program.
are you using schemer for dark theme or something else?
Is there a way to extend this diagram beyond r=4? Seems like it goes to negative infinity after that.
Hi thank you for your useful video. I'm starting to learn Programming.
I have a doubt about ''.. cut out transient.. for i=1:2000...'' I'm not actually understand how it work.
Any suggestions appreciated.
now I understand, thank you so much
What a great video, thanks!
Do you have any video about Maximum Lyapunov Exponent? If you have give the link. Thank you.
Awsome video, very helpful.
You are outstanding
What an awesome video
What is the purpose of code lines 8 to 12?
You are God among humans
ha ha nice one
well, this is super cool!
Thanks!
Can you please share m.file of Lorenz attractor bifurcation plot...
love it
how to calculate the lyapunov exponent for 3 or 4 dimensions. for example:
x(1) = 0.8109; y(1) = 0.3342; z(1) = 0.5734;
lamda = 3.789; beta = 0.029;alpha = 0.0224;
for i = 1:2000
x(i+1)=lamda*x(i)*(1-x(i))+beta*((y(i)).^2)*x(i)+alpha*((z(i)).^3);
y(i+1)=lamda*y(i)*(1-y(i))+beta*((z(i)).^2)*y(i)+alpha*((x(i)).^3);
z(i+1)=lamda*z(i)*(1-z(i))+beta*((z(i)).^2)*z(i)+alpha*((y(i)).^3);
end
Kindly help me for this. I am using this in my research work. I will be than full to you.
great