Absolute max and min values Problem 1 (Multivariable Calculus)

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  • Опубликовано: 3 ноя 2022
  • This problem goes over how to find the absolute maximum and absolute minimum values of a function of two variables on a closed, bounded region. It's very similar to how this is done in calculus 1, where you check the values of the function at the critical points and endpoints of the interval. Now, the boundary of a region is a curve.
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Комментарии • 31

  • @magaplex6476

    I always thought finding the critical points of a circular region was the hardest thing ever, but this video has given me such a clear understanding of it, and for that I thank you!

  • @gretchenhe6726
    @gretchenhe6726 Год назад +2

    Thank you so much! This makes a lot more sense!

  • @zizobob1082
    @zizobob1082 Год назад +9

    Best prof. NO CAP 🧢

  • @Bedoroski

    Great video. This helped a lor

  • @eulzzzz7682

    Sir how did you check without inserting the boundary values on to the function is that possible to find the max and min value just by seeing the boundary value max and min?🙏

  • @SweetBonanza2001
    @SweetBonanza2001 Год назад +2

    love you man

  • @philippelevesque4801
    @philippelevesque4801 Год назад +1

    THANK YOU SO MUCH

  • @muffindestroyeritsmumblintime.

    why do we split the boundary as top and bottom and not left and right?

  • @azizkash286
    @azizkash286 Год назад +2

    Thank you sir

  • @Jarrodjohn2007
    @Jarrodjohn2007 Год назад +3

    Nice!

  • @QuocAnhHandsome

    -4 <= x <= 4, so x can be -4 or 4.

  • @rakibulhaque3444
    @rakibulhaque3444 Год назад +1

    thanks boss

  • @rogersssali9722

    Very complicated

  • @SweetBonanza2001
    @SweetBonanza2001 Год назад

    Why did you have to calculate the end points (4,0) & (-4, 0) for both curve functions. Is it possible for a point to have different values?

  • @brightknight0623

    Do Lagrange multipliers work for this?