Absolute max and min values Problem 1 (Multivariable Calculus)
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- Опубликовано: 3 ноя 2022
- This problem goes over how to find the absolute maximum and absolute minimum values of a function of two variables on a closed, bounded region. It's very similar to how this is done in calculus 1, where you check the values of the function at the critical points and endpoints of the interval. Now, the boundary of a region is a curve.
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I always thought finding the critical points of a circular region was the hardest thing ever, but this video has given me such a clear understanding of it, and for that I thank you!
Thank you so much! This makes a lot more sense!
Best prof. NO CAP 🧢
Great video. This helped a lor
Sir how did you check without inserting the boundary values on to the function is that possible to find the max and min value just by seeing the boundary value max and min?🙏
love you man
THANK YOU SO MUCH
why do we split the boundary as top and bottom and not left and right?
Thank you sir
Nice!
-4 <= x <= 4, so x can be -4 or 4.
thanks boss
Very complicated
Why did you have to calculate the end points (4,0) & (-4, 0) for both curve functions. Is it possible for a point to have different values?
Do Lagrange multipliers work for this?