Thanks bro, you are saving me from failing the AP exam, it’s only 7 hours away, I’m watching all of your reviews, they are the best I ave seen for physics 2
i'm not trying to sound like every other comment saying this; but your channel is actually one of the most life saving things for me ever. Although I have a good physics teacher, coming home and watching you explain this stuff helps me understand everything so much more.
Thanks for the video; very informative! At 16:20, can't we relate the buoyant force to the weight using the normal force? We know that the object must be in vertical static equilibrium, so when it sinks, we have Fnet = buoyant + normal - mg. Then, we see that normal = mg - buoyant. Is this true, or am I missing something?
Thank you so much! Just a little question, at the slide of 7:03 when do we ever use the formula P = pgh besides for Bernoulli’s equation? Is it a formula we can generally not use because we have to use P = P0 + pgh , or does it have it’s own use case?
The only reason the equation Po + pgh is used is because usually at the top of the fluid there is atmospheric pressure pushing down. If there is no atmospheric pressure then that term shouldn't be there. I think P = pgh would give you right pressure vs depth relationship if there were just a vacuum at the top, for example.
@@physicsbybowman Thanks for the explanation! Makes total sense now. If we had another kind of pressure, not equal to the atmospheric pressure, pressing from the top on the object, then the total pressure P on that object would be P = pgh + Panother , and in the case of a vacuum above the object Panother would equal 0.
Thanks bro, you are saving me from failing the AP exam, it’s only 7 hours away, I’m watching all of your reviews, they are the best I ave seen for physics 2
Viktor KC11 last minute preparation gang :,)
@truce artwork lmao I’m gonna fail but I at least tried to review :)
@@viktorkc1154 Well did you fail
@@dickt8657 lol no I got a 4
@@viktorkc1154 nice
i'm not trying to sound like every other comment saying this; but your channel is actually one of the most life saving things for me ever. Although I have a good physics teacher, coming home and watching you explain this stuff helps me understand everything so much more.
Thanks! helped a ton.
thanks homie
LIFE SAVER DAWG
Thanks for the video; very informative! At 16:20, can't we relate the buoyant force to the weight using the normal force? We know that the object must be in vertical static equilibrium, so when it sinks, we have Fnet = buoyant + normal - mg. Then, we see that normal = mg - buoyant. Is this true, or am I missing something?
As far as I understand, the bouyant force is the normal force in this case, so the equation would be fnet = bouyant - mg.
how does the height of a fluid in a tube affect its velocity?
v = sqrt(2gh), therefore as h increases, velocity increases. 24:30
Thank you so much! Just a little question, at the slide of 7:03 when do we ever use the formula P = pgh besides for Bernoulli’s equation? Is it a formula we can generally not use because we have to use P = P0 + pgh , or does it have it’s own use case?
The only reason the equation Po + pgh is used is because usually at the top of the fluid there is atmospheric pressure pushing down. If there is no atmospheric pressure then that term shouldn't be there. I think P = pgh would give you right pressure vs depth relationship if there were just a vacuum at the top, for example.
@@physicsbybowman Thanks for the explanation! Makes total sense now. If we had another kind of pressure, not equal to the atmospheric pressure, pressing from the top on the object, then the total pressure P on that object would be P = pgh + Panother , and in the case of a vacuum above the object Panother would equal 0.
@@anassm5565 I think you’re right here
@@anassm5565 Right but atmospheric pressure equals 1. If there is anything other than a vacuum outside of the manometer, then you will use P(0)
11:57 equal pressures
About to fail lmao
What did you end up getting?
Pee Naught