Static and kinetic friction example | Forces and Newton's laws of motion | Physics | Khan Academy

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  • Опубликовано: 20 ноя 2024

Комментарии • 241

  • @Psalm2Charity
    @Psalm2Charity 10 лет назад +253

    Thank you. Physics can be so scary when your teachers talk at you a little, hands you a book, and says, "Do this."

  • @MistuhCoolio
    @MistuhCoolio 11 лет назад +81

    I understood completely up until 1:12

  • @GenericCoder
    @GenericCoder 12 лет назад +31

    Man you made me seriously like physics your awesome teacher :).

  • @donaldtrump8315
    @donaldtrump8315 5 лет назад +39

    Love having to watch a RUclips video on physics because my teacher teaches us the most limited information needed to do basic problems then says "these ones are harder so dont take them lightly" and doesnt explain how to do them. Then she gets mad at us when we fail her tests

  • @Raisuru
    @Raisuru 11 лет назад +79

    khan you are a life saver

  • @jonathanlaliberte3175
    @jonathanlaliberte3175 4 года назад +6

    Love your Channel !
    In preparation of my last exam I used your videos for what I didn't fully understood, end result?
    I got 70% and the average of the class is 40%
    Next exam Monday and I'm definitely watching your videos prior to it !
    Thank you very much Khan Academy

  • @nikoh1599
    @nikoh1599 5 лет назад +10

    You are the sole reason i have an A in physics. Thank you so much

  • @josephjerome9740
    @josephjerome9740 11 лет назад +13

    That block is moving pretty fast. There should be a follow-up problem where it crashes into something.

  • @paritoshagarwal8840
    @paritoshagarwal8840 6 лет назад +2

    4:55 total =100 N, force needed to overcome F of static friction =29.4. Static friction

  • @debasissahu5261
    @debasissahu5261 10 лет назад +56

    Thanks. Sir you make the subject so easy to understand. You are incredible! !!!!!!! You are the GOD of studies. I am totally mesmerised by you.

    • @icevin
      @icevin 10 лет назад +7

      MiRaje8086 Who the fuck said Debasis Sahu was a guy?

    • @DogeFrom2014
      @DogeFrom2014 9 лет назад +3

      MiRaje8086 How about no? Immature fool.

    • @sukanyadutta4041
      @sukanyadutta4041 9 лет назад +1

      +Kevin Tang it's an indian name. debasis is a male.

    • @DogeFrom2014
      @DogeFrom2014 9 лет назад +1

      Sukanya Dutta Well still, if he's a guy then why does it matter to him? He's probably just a dumb 12 year old kid who wants attention.

  • @dulvinbandara7226
    @dulvinbandara7226 4 года назад +4

    Learning physics with this is a life-saver. Thanks so Much!!!!

  • @BloodAsp
    @BloodAsp 5 лет назад +5

    Having this, I was able to do a problem where there was a force at theta, and had to calculate for an adjusted F_n in order to find the blocks kinetic acceleration. A great help thank you!

  • @Dani98664
    @Dani98664 8 лет назад +23

    Have a test on this for my AP Physics class in a few hours. This video was great. Feel ready now.

    • @highhyena7198
      @highhyena7198 3 года назад

      soooo.... how did it go?

    • @Dani98664
      @Dani98664 3 года назад +1

      @@highhyena7198 In short...badly. Probably studied for like 1 hour total which was a huge mistake. 6-8 total hours would have been perfect.

    • @highhyena7198
      @highhyena7198 3 года назад +2

      @@Dani98664 I'm a little bit surprised that you replied to me after four years, but it was nice knowing

    • @Dani98664
      @Dani98664 3 года назад +1

      @@highhyena7198 I still use this account a lot to watch videos and got a notification from your msg

    • @thelegendofnene6935
      @thelegendofnene6935 3 года назад

      @@Dani98664 lmao I have test on this and I missed 2 weeks

  • @evylinda2045
    @evylinda2045 13 лет назад +4

    great lecture! my statics final is in 2 1/2 hours and I have officially been partially relieved of this confusion.

  • @rajikarthi3385
    @rajikarthi3385 4 года назад +2

    u r a legend

  • @debasissahu5261
    @debasissahu5261 10 лет назад +2

    Thanks. Sir the subject seems so easy after you explain. You are the GOD of studies . You are incredible!

  • @mrpredator-
    @mrpredator- 6 лет назад +1

    khan u truly are a khan!!

  • @eduardoterriquez4859
    @eduardoterriquez4859 10 лет назад +21

    Thanks :D I have a mid-term in an hour. Wish me luck!!!

    • @patrick7726
      @patrick7726 5 лет назад +14

      Hey, how did ya do? It was five years ago, but how are you doing now? Is life treating you well? I hope you did well on that test.

    • @gnilan1195
      @gnilan1195 4 года назад +2

      5 years in the future me in the same situation

    • @raymat4451
      @raymat4451 4 года назад

      @@patrick7726 lol

    • @anoshtaraporevala9926
      @anoshtaraporevala9926 4 года назад

      No joke have one tomorrow. 6 years and we are still doing the same thing.

    • @seaburni7225
      @seaburni7225 3 года назад

      @@anoshtaraporevala9926 how did it go?

  • @azyn1525
    @azyn1525 3 года назад +1

    Really can't believe this whole academy has a one-man-army narrator and (not sure) teacher.

  • @dejdej6769
    @dejdej6769 3 года назад +1

    It’s the night before the exam. I’m very stressed. I cant wait to look back on this comment and moment in time in a few years 🥲

  • @oluwasefunmioluyede2352
    @oluwasefunmioluyede2352 11 лет назад

    thanks for this opportunity to learn from the expert

  • @caomoletimoloi6565
    @caomoletimoloi6565 5 лет назад +1

    have an IB Physics test in 24 hours. Thanks for making me understand this concept!!!

  • @flordelphinta
    @flordelphinta 2 года назад

    5:23 "I could do that in my head, I shouldn't have to look at that."
    One of the cons of a calculator.
    Because we live in such an era:
    Thank you for the lecture!

  • @TheseHDGamers
    @TheseHDGamers 8 лет назад +5

    Thx for saving me eight weeks.

  • @rahulpdiggi9888
    @rahulpdiggi9888 11 лет назад

    Explained very well. Please explain about velocity triangles in turbines

  • @RockstarFisheye
    @RockstarFisheye 6 лет назад

    Thank you Mr. Khan you just clarified the way the different coefficients work! The static friction doesn't change the initial force when you go to calculate the Fnet concerning the kinetic friction (i.e. you subtract 26.95 from 100, not 70.6. I suppose one has to know if the force is constant, which most of the time it is for beginning physics problems.

  • @workish04
    @workish04 13 лет назад

    wow Sal is upgrading
    HD now!

  • @joshuasusanto6626
    @joshuasusanto6626 6 лет назад

    Thank you!!! Thank you!!!! Thank you!!!!! My teacher skipped the fundamentals and even the common equations and straight to the compound questions..... You are a great help!!

  • @thedogdogification
    @thedogdogification 3 года назад +1

    Sal, you have no idea what it feels like to have this fog of confusion (which started in high school) finally clearing after a couple decades. Thank you.

  • @daanmeere
    @daanmeere Год назад

    Great explanation, makes a lot of sense now!

  • @santhoshpk8491
    @santhoshpk8491 7 лет назад

    For those who don't understand why he is dividing it, F=M.A
    ie. A(acceleration)=
    F/M

  • @BentonioD
    @BentonioD 11 лет назад +1

    This was excellent! Thank you!

  • @Aristothink
    @Aristothink Год назад

    Great video making Physics seems natural and simple. Khan Academy saves so many students....🏆

  • @liwile
    @liwile 5 лет назад +1

    Hold on for Net force, don’t we deduct the force of friction and the force taken to overcome static friction from 100?

  • @originalmusic401
    @originalmusic401 11 лет назад +4

    watching this before my exam tmr, wish me luck!

  • @claudiarojas9994
    @claudiarojas9994 7 лет назад

    very clear! you are good at explaining

  • @nstar0203
    @nstar0203 10 лет назад +1

    VERY GOOD EXPLANATION ...THANK YOU!!

  • @Lily-zd6dx
    @Lily-zd6dx 6 лет назад

    thank you so much !! i had an assignement but didnt understant really well in order to do it ans as always khan academy is the super hero

  • @kouta4543
    @kouta4543 Год назад

    Thank u I have my paper TMR morning

  • @raske2204
    @raske2204 8 лет назад +4

    While this is a good, well explained example; it is fairly trivial in nature. To be fair, this example does give a great introduction to a very puzzling topic of physics, but from the comments below there is a mixture of responses as to who truly understands this topic, who is still confused, and who is still lost on this topic. If there was a way to tie the concepts presented in this video to a more complex problem or present them in more diverse situations to give those who are still struggling different views on how to interpret when to use the coefficient of static friction versus when to use the coefficient of kinetic friction, then I think this topic would be more understood by all.

  • @sammylee1895
    @sammylee1895 6 лет назад +3

    How did you find the coefficient ??

  • @The_Laughing_Cow
    @The_Laughing_Cow 11 лет назад

    no. static will always be larger. just think about the static friction coefficient as being the threshold, that must be overcome, then kinetic is easier to push, hence its lower coefficient.

  • @edduardoloredo
    @edduardoloredo 11 лет назад

    Thank you so much, you're better than my Physics teacher, I wish I had you rather than him. Greeting from Mexico, I'm at a bilingual school c:

  • @connorsmith6936
    @connorsmith6936 Год назад

    Is the "moment" your initial acceleration?

  • @DeMonYitOoO
    @DeMonYitOoO 12 лет назад

    I having a quiz tomorrow you save me, Dang Thank You! I was having trouble with this thing

  • @methasawijayasuriya6472
    @methasawijayasuriya6472 3 года назад

    why does the more collinear the force applied and the frictional force against it, the tendency for toppling an object is is less?

  • @frank1102844
    @frank1102844 11 лет назад

    Thank you, it helps a lot..

  • @None0fY0urConcern
    @None0fY0urConcern Год назад

    After seeing this I think I khan learn anything

  • @HOTDOG_CHAMP
    @HOTDOG_CHAMP 8 лет назад +1

    Very helpful.

  • @academiarelatedemails9769
    @academiarelatedemails9769 7 лет назад +1

    This is such a helpful video! Thank you so much :)

  • @newtube553
    @newtube553 4 года назад

    I hope I'd learn that . But somehow I've lots of idea with regard here. Thank you

  • @isabelvickery8068
    @isabelvickery8068 3 года назад

    This was so helpful!

  • @sirianfreyra9832
    @sirianfreyra9832 4 года назад

    Im a math major but physics is my first love. And first love never dies.

  • @caseygriswold8617
    @caseygriswold8617 10 лет назад

    That was great!!!! Thanks. Can you do a similar example where it asks "what is the speed of the block after it has moved 3m?"

    • @seaney11
      @seaney11 10 лет назад +1

      well if you have the acceleration you can work it out, use v = u + at to get final velocity half it (assuming it starts stationary) to get the average velocity and s = vt to get s = (at / 2)t use that to work out t then use that value of t in v = u + at

  • @HelloThere-dd4dt
    @HelloThere-dd4dt 8 лет назад

    WOW YOU GUYS
    FREEEE I CANT BELIEVE IT

  • @zeyrashid
    @zeyrashid 11 лет назад

    I know, I am taking it now in 11 U Physics. It sound hard but it is kinda easy when you try some

  • @xander55577
    @xander55577 12 лет назад

    Thank you, Sal...again and again. Do you realize the magnitude of your contributions to the developing of scientific thinking?

  • @mcheu777
    @mcheu777 7 лет назад

    Thank you so much. One question though. Car physics. If 100N (theoretically) was applied to another car, of 5kg and they stuck together, would the total acceleration be f=ma. 73.05 = mass of both cars/a ?

  • @abhishekshyleshnair3280
    @abhishekshyleshnair3280 4 года назад

    Sir, is running a machine a disadvantage or advantage of friction

  • @saminalafsarniloy3389
    @saminalafsarniloy3389 4 года назад

    well, that was AWESOME!!!!!!

  • @patrikatanasovski8848
    @patrikatanasovski8848 3 года назад +1

    Found this video in a Drum'n'bass playlist lol

  • @lifer7741
    @lifer7741 Месяц назад

    isn't Fb the budging force? so why is it used as the friction force? i thought it was like the minimum force needed to overcome the static friction INSTEAD of the force of static friction itself.

  • @oghenemoses8839
    @oghenemoses8839 4 года назад

    What a great video.. Thanks a bunch.
    But i think to accelerate the load from rest, we need to overcome both the static and Kinetic Friction at the same time. which means, Fnet =//F//-Fstatic- Fkinetic= Ma
    100-(29.4+26.95)=5a
    Please i need more explanation..

  • @anthonygaita
    @anthonygaita 7 лет назад

    Regarding living in nonliving bonds between two objects or more are the charges of the frequencies to strengthen this coefficient. Are there any other forces involved regarding communication between two objects?

  • @davidm.johnston8994
    @davidm.johnston8994 6 лет назад

    Great video, thanks.

  • @Klepto84734
    @Klepto84734 10 лет назад +1

    How would you work out how much time it takes for the force static friction to be overcome? You've calculated acceleration, but there's zero displacement. I feel like the answer is obvious but it's alluding me atm. :x

  • @556to762
    @556to762 11 лет назад

    I want to know what is coefficient of static and kentic friction !!! And why? I don't need to know how to use it.

  • @jackr8374
    @jackr8374 5 лет назад

    Thank you so much for this.

  • @MizanSClub57
    @MizanSClub57 2 года назад

    You're creating more than complications

  • @ogaisadiq
    @ogaisadiq 12 лет назад

    Thank you so much!

  • @rahulg.c4861
    @rahulg.c4861 3 года назад

    Awesome 👏

  • @chocolatevodka9226
    @chocolatevodka9226 11 лет назад

    Thanks, but how do you find kinetic when the object is on horizontal plane that is 14 degrees above the ground, and all you are given is the weight in Newtons?

  • @justinscheidler5938
    @justinscheidler5938 9 лет назад

    So how do we calculate the jerk from the moment the force is applied to when it moves? It looks like the change is from 14.1 to 14.6. So is it just simple simple subtraction?

  • @musicftw2145
    @musicftw2145 13 лет назад

    Dearest Sal,
    You saved my butt in chemistry, and it looks as though the story will repeat with physics.
    Thanks :)

  • @Feefoo-iq6ix
    @Feefoo-iq6ix 8 лет назад +49

    omg I don't get it physics is just confusing......

  • @bobosamathcee
    @bobosamathcee 4 года назад

    Thank you

  • @jasonodom7217
    @jasonodom7217 11 лет назад

    You're awesome man!

  • @freaks5973
    @freaks5973 3 года назад

    Hail Sal!!

  • @semhar1396
    @semhar1396 5 лет назад

    thank you alot sir

  • @VideoGuy879
    @VideoGuy879 12 лет назад

    thanks

  • @NKShahariar
    @NKShahariar 6 лет назад

    thank you so much. love from bangladesh

  • @mariofizz13
    @mariofizz13 12 лет назад

    thank you sir

  • @anoobgamerNG
    @anoobgamerNG 7 лет назад

    Hey sal thnx for amazing videos...
    Hey why dont you add animation and vfx subjects?? Here in india ppl so unaware nd thinks its childish

  • @gaiusmarius4112
    @gaiusmarius4112 9 лет назад

    Merci beaucoup monsieur :D

    • @Reforitor
      @Reforitor 5 лет назад

      Hey, I'm learning French on Duolingo and I suppose this means "Thank you very much, sir". I just hope I'm right

  • @cmrr3099
    @cmrr3099 6 лет назад

    thanks lot........

  • @chiefmiester3801
    @chiefmiester3801 9 лет назад

    Thanks mate

  • @JohnstasBACK
    @JohnstasBACK 5 лет назад

    but how LONG will it go to the right before it slows down??

  • @bermuzz
    @bermuzz 10 лет назад

    thanks dude, just video and i finally understood this :)

  • @RoshanKumar-fd9nh
    @RoshanKumar-fd9nh 8 лет назад +1

    Can someone tell me why does force of friction increases when surfaces in contact are extra smooth

    • @beatsta709
      @beatsta709 8 лет назад +3

      On extrasmooth surface .. All the surface molecules on the bodies are in contact ... Resulting in increased intermolecular attraction ... Which leads to more friction

    • @jellisawilliams3773
      @jellisawilliams3773 7 лет назад

      Beatsta thank so much for this information 😃😁

  • @shekhrussel6304
    @shekhrussel6304 6 лет назад

    thanks to helps us

  • @colenewer
    @colenewer 5 лет назад

    thank you very much. i finally understand this

  • @Fool_of_a_Toque
    @Fool_of_a_Toque 13 лет назад +5

    Panic For Physics Final Mode : Deactivated!

  • @BD638
    @BD638 8 лет назад

    So at the end, the force of friction acting on the object is 26.95 N????

  • @golyrics1286
    @golyrics1286 2 года назад

    Where is 9.8 kg that was multipled by 5kg from? Please explain more!🙏🏾

  • @Wolftacular
    @Wolftacular 11 лет назад

    Can the coefficient of kinetic friction ever be greater than that of static friction?

  • @tegan0110
    @tegan0110 9 лет назад

    You're awesome.

  • @bebamora4661
    @bebamora4661 6 лет назад +2

    When you discuss I get it
    When my teacher discuss
    I don't get it

  • @ShaharHarshuv
    @ShaharHarshuv 11 месяцев назад

    How long is "a moment"?

  • @samfrede6059
    @samfrede6059 5 лет назад

    I love you sal khan

  • @chugs6817
    @chugs6817 2 года назад

    Tryna find out how to solve uk and us. Ik the formula is uk=fk/fn and us=fs,max/fn. but idk how to plug numbers in them, typically fk and fs,max. And apparently us is supposed to be greater than uk