Thanks for this video. I just bought my first TI-84 PLUS CE PYTHON calculator. Outside of basic calculator stuff, I really have no idea how to operate it.
U can also place te B matrix next to the A. So you get a 3X4 with the last row being 2 0 2. Then go to Matrix - EDIT - B: rref( place matrix A after rref => rref([A] ENTER It wil give you the correct answers aswel :)
Thanks for the very clear explanation! One question though: if I happen to have a system that has infinitely many solutions or an inconsistent system which has no solution, I get the same error message. How can I distinguish between which answer I would have - zero or infinitely many solutions? Thanks!
rfebster - Sorry for the delayed response. I don't believe that the calculator will help us in distinguishing between these two situations. It is up to us to interpret what is going on. One quick method is to look at the rows of your matrices and identify any that are scalar multiples of another. That would indicate the infinite or many solution situation. If our coefficient matrix exhibits this quality but the resultant matrix does not, then we have a zero solution situation.
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Thanks for this video. I just bought my first TI-84 PLUS CE PYTHON calculator. Outside of basic calculator stuff, I really have no idea how to operate it.
U can also place te B matrix next to the A. So you get a 3X4 with the last row being 2 0 2. Then go to Matrix - EDIT - B: rref(
place matrix A after rref => rref([A] ENTER
It wil give you the correct answers aswel :)
Thanks for the very clear explanation! One question though: if I happen to have a system that has infinitely many solutions or an inconsistent system which has no solution, I get the same error message. How can I distinguish between which answer I would have - zero or infinitely many solutions? Thanks!
rfebster - Sorry for the delayed response. I don't believe that the calculator will help us in distinguishing between these two situations. It is up to us to interpret what is going on. One quick method is to look at the rows of your matrices and identify any that are scalar multiples of another. That would indicate the infinite or many solution situation. If our coefficient matrix exhibits this quality but the resultant matrix does not, then we have a zero solution situation.