csir net jrf previous year solved questions physical sciences | fourier series | fourier transform

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  • Опубликовано: 26 янв 2025

Комментарии • 12

  • @sudipregmi5652
    @sudipregmi5652 Месяц назад +1

    amazing , i would like to request you to make similar videos on classical mechanics.

  • @bhaaarat
    @bhaaarat 2 года назад +1

    please make a video on 2021 and 2022 too...for the upcoming exam

  • @hunkdaivik2872
    @hunkdaivik2872 2 года назад +1

    Mam please electrodynamics aur neuclear k previous year solve krwa dijiye na please 🙏 exam se pehle

  • @AminulIslam-as
    @AminulIslam-as 3 года назад +3

    Ma'am If you could make the videos in English it would be really helpful. Thank you.

    • @vyingphysics
      @vyingphysics  3 года назад +3

      Actually most of my subscribers are comfortable with Hindi, so currently I am going with it,,
      what I can do is- I will try to cover the important points in English as well.
      Hope that helps

  • @dreaming_aastha_phd
    @dreaming_aastha_phd 2 года назад

    Ma'am please gate k sare pyq karwa dijiye
    And also EMT ke

  • @physicslalitrathorepilani3733
    @physicslalitrathorepilani3733 2 года назад +1

    🙏🙏🙏keep it up maa'm.

  • @emptymind7
    @emptymind7 2 года назад +1

    mam jab definition me sqrt(2*pi) nhi tha to inverse me 1/2*pi kyu le rahe h

    • @vyingphysics
      @vyingphysics  2 года назад +1

      These are the formulas,,you can prove them by considering f(t) =1. If we find F.T. of this function using definition which do not include 1/2*pi. Or 1/sqrt(2*pi),, we get the result 2*pi*d.d(s).
      And if we take inverse F.T. of this result using formula that must include 1/(2*pi) to get the result f(t)=1.
      Hope you understand. If further doubts,,see the revision video of F.T

  • @karunapandey2308
    @karunapandey2308 3 года назад +1

    Mem 2014 december me tensor retated jo prblm tha, uska solution mem plzzz....

    • @vyingphysics
      @vyingphysics  3 года назад

      Share me that question on telegram channel,,, I'll try to provide solution.