Sum of Cubes IV (Nicomachus's Theorem)
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- Опубликовано: 4 окт 2024
- This is a short, animated (wordless) visual proof demonstrating the sum of the first n positive cubes by rearranging cubes into a flat square. #mathshorts #mathvideo #math #calculus #mtbos #manim #animation #theorem #pww #proofwithoutwords #visualproof #proof #iteachmath #finitesums #discretemath #calculus #sum #induction
Here are three other visual proofs of sum of cubes formulas:
• Visual Sum of Cubes II
• Sum Of Cubes I (visual...
• Visual Sum of Cubes III
This animation is based on independently discovered, separate visual proofs by J. Barry Love from the March 1977 issue of Mathematics Magazine (www.jstor.org/..., page 74, and Alan L. Fry from the January 1985 issue of Mathematics Magazine (www.jstor.org/...) , page 11.
To learn more about animating with manim, check out:
manim.community
This is my version of a classic visual proof. Here are other renditions:
• Nicomachus's theorem |... by @ThinkTwiceLtu
• Nicomachus's theorem |... by @Mathocube
Edit: and thanks to a viewer I learned that
@Mathologer posted a similar video a day ago : • Animating Nicomachus's...
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Music in this video:
Rain On The Window by Alex-Productions | onsound.eu/
Music promoted by www.free-stock...
Creative Commons Attribution 3.0 Unported License
creativecommon...
This is such a beautiful theorem, beautifully demonstrated and animated. Together with this well-chosen music track, I must confess that it moves me to tears every time I see it. Thank you so much for giving us this wonderful gift.
Glad you liked it. Thanks!
I could not put it better myself. I agree with every word! A big thank you from Australia.
I wanted to make this video as a follow up for my sum of squares video!
Well done, great job!
Do it anyway!
nice
Thanks :)
thank u so much for this incredible visual so helpful!!!!
Very good visualization of a wonderful formula!
Thanks!
Lovely
One comment: I wouldn't really call this a complete proof because it's not entirely obvious that this method of tiling can be done in general
Better take it up with the published versions :) kidding of course. Can you convince yourself that the even/odd steps will always work?
A quick proof:
To prove that each cube completes a square with side length equal to the next triangular number, we simply must prove that (1 + 2 + ... + n)^2 - (1 + 2 + [n-1])^2 = n^3. Expanding the LHS with difference of squares, it's n * (2(1 + 2 + ... + n) - n) - n = n * (n(n + 1) - n) = n * n^2 = n^3. :)
@@MathVisualProofs I can convince myself of many things, that doesn't mean I have proofs of them.
Fantastic
Thanks!
I have seen this on r/math before.
Yes. This is a famous one. I linked to two other animations that I like and I linked to the original two published proofs without words that the visualization is based on. I am just finally learning to do some more 3D animations so this one was high on my list to try 😀
Beautiful
Thanks!
Y don't kids need protractors today in schools???? I was required to have one