Most Expected Questions- Differential Equations || CSIR-NET 2024 ||

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[@kulsoomarashid4266]

Applied has always been challenging for me. It is perhaps for the first time that I am able to understand questions up to a large extent. Thanks a million 😊

[@pawankargwal984]

Thank you Mam…bhut ache se apne pdaya ..aesa ab Tak kisi ne nhi pdhaya…keep it up..

[@ThakursBoy]

Amazing session ❤

[@dikshajain5366]

Can you send detailed lecture on comparison theorem

[@pijushdutta3243]

Great congratulations . keep it up

[@MathsRevolution369]

A lot of Thanks mam❤❤❤...each and every concept clear...

[@aishwaryadharwal5585]

Ma'am aaap bahut achhe se explain krte ho 👏👏👏👏
Starting me jb mai preparation kr rhi thi mujhe bhi lgta tha koi shortcut mil jaye or qsn ho jaye but ab realise hota hai ki details of solution ko analysis krna kitna important hai 😊or vo aap bahut achhe se krate ho Thank you ma'am 😊 and keep it up👍

[@proashu6475]

Mam if y1

[@eshitachakraborty7955]

y1

[@rtn_sings]

41:24 maaam b kese true ho gya usme pi by 4 include hai to jb x ki value pi by 4 rakh denge to maam unbounded ban jayayga

[@eshitachakraborty7955]

it says 'in' the interval so we can find I subset of [0,π/4] where solution bounded

[@dikshashukla855]

Mam 13:34 pe vo solution exist ni krra h q ki root ki value negative ho rahi h isiliye na?

[@eshitachakraborty7955]

yes

[@mukeshlalit5152]

Mam jb hum lipschitz k liye derivative bounded ki baat krte h toh initial point Jo independent variable ka given hota h uski traf tend karke check krte h ya dependent variable ko tend krate h?

[@mukeshlalit5152]

At 1 hr.7 min pr jo question h usme aapne u ko zero ki traf tend kraya h but u toh solution h I think t jo independent variable given h usko zero ki side tend karna tha

[@mukeshlalit5152]

Next question me aapne t per check Kiya h

[@eshitachakraborty7955]

yaha initial point (x0,y0) ki nbd me check krna hai

[@mukeshlalit5152]

So initial point (0,0) hoga na?

[@mukeshlalit5152]

Jb (0,0) ko tend karenge toh t bhi toh zero per ja rha h

[@somamandal5239]

Mam in this question
dy/dx=x^2+y^2 ,y(0)=1 we get the option
1) Every solution is bounded in [0,π/4].
Mam how can we say that at x=π/4 it give finite value ?

[@eshitachakraborty7955]

it says 'in' the interval , so we can find I which is subset of [0,π/4] where solution bounded

[@somamandal5239]

Ok mam

[@Priya-ht6mx]

Jo hme y(0)=0 conditon di rhte hai or sath me hme ek or solution mil jata hai to hm infinite non linear k case m bolte h na....agr linear eq h to hme unique hi milega ??

[@eshitachakraborty7955]

Linear hai to unique hi milega but non linear me aisa jaruri nehi ki hamesha infinite ho

[@Priya-ht6mx]

@@eshitachakraborty7955 yes OK mam thanku🙂

[@dikshashukla855]

39:27 pe mam pi/4 pe unbounded solution hora h, infinity pe jara h, fir option 1,2 sahi kaise 🤔

[@eshitachakraborty7955]

there exists a solution bola hai and y is unbounded between pi/4 to 1 ... actually comparison th se y