3.6 Basic Theory of Radiative Transitions

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  • Опубликовано: 31 янв 2025

Комментарии • 9

  • @darrenho3655
    @darrenho3655 2 года назад +2

    Thank you so much for explaining this in a clear intuitive manner - super helpful for someone being introduced to the field of optics

  • @jacobvandijk6525
    @jacobvandijk6525 3 месяца назад +2

    @ 4:26 I don't see what the displacement of one electron has to do with a dipole. Yes, sometimes the charge is here, and sometimes it is there. But a dipole is a unit consisting of charges in two places at the same time! No displacement is needed to have a dipole. Just look at the HCl-molecule. So something isn't right here (no matter how nice these moving pictures from Wikipedia are, haha). By the way, an accelerating electron is a source of EM-radiation on its own. P.S. Again, your math is okay, Michael, but your physics isn't on the same level. That's why you became a chemist.

  • @j.kon1201
    @j.kon1201 Год назад

    Thank you for this video! Truly helpful.

  • @RonaldStrange-x1o
    @RonaldStrange-x1o 10 месяцев назад

    Thank you for the clear explanation. Could you explain how the oscillator strength can be obtained from vibrational peaks in the infrared? Is that similar and what about rotational satellites?

  • @lyuan1513
    @lyuan1513 3 года назад +1

    thank you for the video, was really helpful

  • @lincolnford2229
    @lincolnford2229 4 года назад

    Thanks for the lectures.

  • @renn4489
    @renn4489 3 года назад +1

    Great lecture
    Can you answer a question regarding it?

    • @mevansthechemist
      @mevansthechemist  3 года назад

      Certainly, fire away!

    • @renn4489
      @renn4489 3 года назад

      @@mevansthechemist as I read the intensity of a transition is equal to the matrix element of dipole moment(transition dipole moment) squared. And was wondering why it's so and how it's connected to the selection rule and the vector r you discussed
      Is that also true, that knowing transition dipole moment we can reconstruct the spectrum ?