A RIDICULOUSLY AWESOME LOG INTEGRAL: Integral of (ln(x))^2/(x^2+1) from zero to infinity

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  • Опубликовано: 19 ноя 2024

Комментарии • 30

  • @zunaidparker
    @zunaidparker Год назад +4

    Another nice one! Would like to see you tackle these problems with new techniques e.g. setting up integration in 2 and 3 variables (xy/xyz) and using polar and spherical coordinate transformations. Would be a good change and showcase even more techniques.

  • @holyshit922
    @holyshit922 Год назад +3

    Series for 1/(1+x^2) is convergent when |x|

  • @ThAlEdison
    @ThAlEdison Год назад +3

    Have you done this with starting with I(t)=Int_0^Inf((x^t)dx/(x^2+1)), differentiating twice and evaluating at 0?

  • @MovieMosaicc
    @MovieMosaicc Год назад +1

    Lol Sir , Your channel is growing faster then my hairs 😂😂😂😂

    • @maths_505
      @maths_505  Год назад +2

      I pray that your hair growth accelerates 😂

  • @JCPR-s6p
    @JCPR-s6p Год назад

    Cette intégrale mérite d'être calculée avec le théorème des résidus

  • @gamingwithteax9079
    @gamingwithteax9079 Год назад +1

    Amazing video

  • @JCPR-s6p
    @JCPR-s6p Год назад

    🗼This integral deserves to be calculated with the residue theorem

  • @usernameisamyth
    @usernameisamyth Год назад

    Awesome

  • @nicogehren6566
    @nicogehren6566 Год назад

    very nice solution, but in 3:10 min how did you know the sum isnt convergent?

    • @maths_505
      @maths_505  Год назад

      The series is convergent when abs(x) is less than 1. exp(2t) is always bigger than 1 when x is positive (the interval of integration)

    • @nicogehren6566
      @nicogehren6566 Год назад

      @@maths_505 thanks.

  • @robertsandy3794
    @robertsandy3794 Год назад

    You wrote that the absolute value of x was less than 1. However, the bounds of integration were from 0 to infinity. What have I missed here?

    • @maths_505
      @maths_505  Год назад

      e^(-x) is less than 1 on (0,infinity)

  • @carlosdavid7430
    @carlosdavid7430 Год назад

    yo bro can you solve the integral going from 0 to infinity of (lnx)²arctan(x) ×1/(x^2+1)?
    hope you enjoy this big boy!

    • @maths_505
      @maths_505  Год назад

      Just use a x->1/x transformation and you'll see why this makes a short rather than a full video

    • @carlosdavid7430
      @carlosdavid7430 Год назад

      @@richardheiville937 thats one way i solved it

  • @ManishKumar-ic6hg
    @ManishKumar-ic6hg 10 месяцев назад

    Bro solve this problem if the denominator is( x^2 + x + 1)

    • @uggupuggu
      @uggupuggu 9 месяцев назад

      rewrite it as
      (x+1/2)^2+3/4 and then use trig sub

  • @gamingwithteax9079
    @gamingwithteax9079 Год назад

    Sir I am Ameer Sadiq your student

  • @imafidonerisson5527
    @imafidonerisson5527 Год назад

    Pls prove the summation

  • @manstuckinabox3679
    @manstuckinabox3679 Год назад

    LOG? I'M HERE BOY DW just wanted to say thank you for introducing me to these really cool techniques to solving integrals! I'm quite disappointed that usual calc 1-2 classes usually skim past these methods...

  • @asriel522
    @asriel522 Год назад +1

    Actually the notation if ln²x is wrong,you're supposed to write (lnx)²