Bowling ball in vertical loop | Centripetal force and gravitation | Physics | Khan Academy

In this video David explains how to find the normal force on a bowling ball rolling in a vertical loop.
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[@danzackblack5829]

Dude you're amazing, around 8 classes were spent learning this in class and I come here to find out it's all not only in like 30 min(video 1,2,3 on centripetal problem solving), it's explained much better

[@zvxgamer7863]

"surfaces can't push", thats brilliant!

[@lopezmeli023]

Thank you, David! God bless! :)

[@mythslife8883]

Thanks for making my life more easier :) ♡

[@xpro-clashroyale2009]

This 9 minutes video is better than my 45 minutes physics lesson

[@zakusa9891]

no you can get more done in 45 minutes so no

[@ArielStar]

Beautiful! Thank you!

[@ishaansoni1645]

very helpfull! nice explanation.... : )

[@tealahaj8268]

thanks a lot

[@abderzakchebbi1339]

thank you for the efforts you made to explain with precision this concept that brought me back to my classes in the 90's in another country, i alwayes liked to solve these types of circular problems with pandulums etc, my classes were in frensh, anyway logic is the same whatever the language youuse to explain it; g=~9.81 everuwhere on earth i think!

[@-a5624]

god bless

[@legalizeme]

Isnt it true, that instead of just removing Fn in the second case when the ball is on "9 o`clock", you could just multiply it with cosinus of that angle what`s created between those forces? angle between those vectors is 90 degrees then and cos(90) is 0 and then it works for ball being on any place on loop?

[@Chinagirl]

Yeah right.. Bowling is hard enough already.

[@bolram6724]

Hi
I have two questions
1.if they ask the force acting on the object at the top of the loop should we calculate both Fn and mg or just Fn. Why?
2. You said the Fn force has a reaction force which acts upward but is there a reaction force for weight of the object?
Thank You

[@MegaRaja54321]

1. If they ask for all forces acting at the top of the loop then yes you would have to find Fn and Fg and those add up to become your centripetal force
2. There is no reaction force (I am guessing you're thinking of Normal Force) for the weight of the ball because there is no surface at the bottom. Since the force of gravity is weight there is no normal force because a normal force is a force that is perpendicular to the force acting towards a surface.

[@akeemgriffiths4459]

how can we solve loop diameter when we are given just the hight of the ramp and Mu k and gravity ?

[@booksbrains1249]

Who balances this mg in second case , otherwise ball should go in southeast direction

[@ossabellator13]

The normal force has increased enough to move in a circle. It increases or decreases dynamically depending on the other force vectors in the same plane.

[@bilincsizadam5957]

In min 4:07 should it be R is r cause we got only half of the radius

[@harshavardhan679]

wont d ball just fall off d surface cus theres literally no force acting in d direction of d surface at least in d diagram above

[@abdulrahmanmahmoudanter8829]

Hi sal how can I communicate with u ?