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Sir, in the off diagonal elements taken as +ve but diagonal elements taken as -ve .why we should take like that?
Hello, in what book can I find this explanation? thank you for the video.
for Zold = i [inverted matrix ] was written but , Z = inv(Y ) , means inverse of j also it is -j , so -j need to be multiplied na
very ussfull for me.thx sir.
Sir nice video but in the last step you changed the values of j and k At last that is why my problem took so much time
Solution will be same if take bus 3 first then bus 2 and add it to 1st bus in last step..??
Thanks
While calculating the admittance in starting why you have multiplied it with -1....and again while writing those admittance in matrix you multiplied it with -1.....you have multiplied it twices with -1
that is the procedure. For the exact reason please see parts 1 and 2.
I want to know how many cases in the Zbus building algorithm
Very helpful. Thanku so much sir.
Why you changed J and K value..earlier J= 2 and K= 3And later you took J=3 and K=2 ??Plz expain..
can you mention at what time in the video is your question?
At 19:56 J=2, K=3But at 23:52 J=3, K=2
please explain
nope never mind, interchanging j and k will get the same results
Daksha y12 = - j4 and y21 = + j4 but sir take it y12 = y21 = + j4 how it came pls tell me
Thanks🙏useful
Sir please show the substitution of the values of Zll
Love u boss 🇧🇩🇧🇩🇧🇩🇧🇩
❤
i didn't understand how to solve the calculations
Sir the system calculator confused me
I want addition of link to bus impendence matrix
Hey I think you've made a mistake at 16:26 , shouldn't it be j4.8 instead of j1.3
Z11+z13
Yes... you are right. thanks for correcting. It should be j4.8
Yes
Corrected it at 22.52
What is zll in 4th case Can u explain each element in zll
Nic video number dijiye
🔫🔫
Sir, in the off diagonal elements taken as +ve but diagonal elements taken as -ve .why we should take like that?
Hello, in what book can I find this explanation? thank you for the video.
for Zold = i [inverted matrix ] was written but , Z = inv(Y ) , means inverse of j also it is -j , so -j need to be multiplied na
very ussfull for me.thx sir.
Sir nice video but in the last step you changed the values of j and k
At last that is why my problem took so much time
Solution will be same if take bus 3 first then bus 2 and add it to 1st bus in last step..??
Thanks
While calculating the admittance in starting why you have multiplied it with -1....and again while writing those admittance in matrix you multiplied it with -1.....you have multiplied it twices with -1
that is the procedure. For the exact reason please see parts 1 and 2.
I want to know how many cases in the Zbus building algorithm
Very helpful. Thanku so much sir.
Why you changed J and K value..earlier J= 2 and K= 3
And later you took J=3 and K=2 ??
Plz expain..
can you mention at what time in the video is your question?
At 19:56 J=2, K=3
But at 23:52 J=3, K=2
please explain
nope never mind, interchanging j and k will get the same results
Daksha y12 = - j4 and y21 = + j4 but sir take it y12 = y21 = + j4 how it came pls tell me
Thanks🙏useful
Sir please show the substitution of the values of Zll
Love u boss 🇧🇩🇧🇩🇧🇩🇧🇩
❤
i didn't understand how to solve the calculations
Sir the system calculator confused me
I want addition of link to bus impendence matrix
Hey I think you've made a mistake at 16:26 , shouldn't it be j4.8 instead of j1.3
Z11+z13
Yes... you are right. thanks for correcting. It should be j4.8
Yes
Corrected it at 22.52
What is zll in 4th case
Can u explain each element in zll
Nic video number dijiye
🔫🔫