If you have a simple, 4-function calculator that lacks memory or parentheses, and you remember the basic log values, do this: x = 2 + log(10/2)/log(3) = 2 + (1 - log(2))/log(3) ≈ 2 + (1 - .30103)/.47712 ≈ 3.464977... This is fairly accurate! Infix: Press 1-.30103=/.47712=+2= Postfix: Press 1Enter.30103-.47712/2+
Good work 👍
kya bat ha sir g
Well done janb ....keep it up
It's easy way to solve problem ✨
2*3ˣ = 2*3²*5
3ˣ = 3²*5
x = 2 + log₃(5)
= 2 + log(5)/log(3)
≈ 3.4649735207179...
If you have a simple, 4-function calculator that lacks memory or parentheses, and you remember the basic log values, do this:
x = 2 + log(10/2)/log(3)
= 2 + (1 - log(2))/log(3)
≈ 2 + (1 - .30103)/.47712
≈ 3.464977...
This is fairly accurate!
Infix: Press 1-.30103=/.47712=+2=
Postfix: Press 1Enter.30103-.47712/2+