Thnx sir But can you explain the reason behind 'there is no path difference when it goes from denser to rarer and 180°change when rarer to denser' Is there any theory or mathematical proof?
To understand this you need to know Maxwell's equations. By solving Maxwell's Equations, with requirement that the electric and magnetic fields be continuous at the boundary this can be proved..
With ray diagram discuss the theory of thin films and the condition for constructive and destructive interference in the case of reflected system. I think this may be the perfect video for this question up to before last 4 min
An electromagnetic wave undergoes a phase change of 180 degress (i.e. path change of λ/2) when reflected from boundary leading to a denser medium. But no path change occurs when it is reflected from boundary leading to a rarer medium. These rules can be proved theoretically by applying boundary conditions on Maxwell's equation in electromagnetic theory. You can understand this in your master's studies in physics.. For our discussion we are just using these rules.
Hlo sir I have one query. In the derivation when we find the path difference between R1E and R2D then the equation formed is u(BC+DC)-u(BE) on what basis we did BC+DC-BE. Thank you sir would help a lot
Both rays are initially travelling as ray AB. So when you take path difference, that AB path will get cancelled. From point B the two rays travel different path. Both rays are going to infinity. Point E onwards and point D onwards, both rays travel same path. So it will not appear in difference. Now, extra path travelled by DR2 is BC+CD and by ray BR1 is BE. So path difference is BC+CD-BE. As path BC+CD is travelled in denser medium equivalent path traveled in air is μ(BC+CD) and so, the optical path difference is μ(BC+CD)-BE
@@EngineeringPhysicsbySanjiv I have the same question, if we put a screen/lens parallel to the film, wouldn't BR1 and DR2 be the same? why do we subtract BE? I've had this question for a long time, I would greatly appreciate an answer
In the condition if you count n from 0 we can write +lamda/2 and if you count n from 1 then -lamda/2. So both are applicable depending starting value of n..
Just check ∆BQC. In this BQ is perpendicular to QC and algle B = r. We want to find BC. So, We write cos(r)=BQ/BC = t/BC. So, BC = t/cos(r). Similarly, we find CD also from ∆DQ'C
Exactly what is supposed to be taught!
Thanks a lot sir✌️
You are welcome.. keep watching..
Thank u sir ur video is very useful to me. Panimalina channels ki support chese kanna talent unna RUclips teachers ni support chesthe baaguntundhi..
Most welcome and best luck 👍
finally i found the perfect video ..... extremely thank you
You are most welcome🙏
Thnx sir
But can you explain the reason behind 'there is no path difference when it goes from denser to rarer and 180°change when rarer to denser'
Is there any theory or mathematical proof?
To understand this you need to know Maxwell's equations. By solving Maxwell's Equations, with requirement that the electric and magnetic fields be continuous at the boundary this can be proved..
With ray diagram discuss the theory of thin films and the condition for constructive and
destructive interference in the case of reflected system. I think this may be the perfect video for this question up to before last 4 min
👍
🙂
Fabulous video sirr...Very well taught...keep it upp ❤❤❤
Thank you
Is maximum and minimum can be said as constructive and destructive interference?
Yes
your teaching is very well sir
Thanks and welcome
Sir why subtracting the BE in path difference that also a path sir
Plz explain to e
NYC explanation sir thank you much♥️
Most welcome..
At 14:41 I cannot understand why you are adding lamda\2🤔? Pls reply it... I cannot understand this part
An electromagnetic wave undergoes a phase change of 180 degress (i.e. path change of λ/2) when reflected from boundary leading to a denser medium. But no path change occurs when it is reflected from boundary leading to a rarer medium. These rules can be proved theoretically by applying boundary conditions on Maxwell's equation in electromagnetic theory. You can understand this in your master's studies in physics.. For our discussion we are just using these rules.
@@EngineeringPhysicsbySanjiv Ok sir thanks for you reply
Sir, in case of maximum, what will be the starting value of n in terms of +lemda/2 and -lemda/2?
For +, starting value of n is 0 and for - it is 1
@@EngineeringPhysicsbySanjiv thank you so much!!
Thankyou.....completely understood every step👍
Great👍👍 best luck
Sexy
why u taking +- lambda/2 but not only + lambda/2 ?
Kal exam h bsdk ratta mar
And why that lamda/2 is introduced
Very well explained 👏👍
Glad you liked it..
Sir video was awesome
Hlo sir I have one query.
In the derivation when we find the path difference between R1E and R2D then the equation formed is u(BC+DC)-u(BE) on what basis we did BC+DC-BE.
Thank you sir would help a lot
Both rays are initially travelling as ray AB. So when you take path difference, that AB path will get cancelled. From point B the two rays travel different path. Both rays are going to infinity. Point E onwards and point D onwards, both rays travel same path. So it will not appear in difference. Now, extra path travelled by DR2 is BC+CD and by ray BR1 is BE. So path difference is BC+CD-BE. As path BC+CD is travelled in denser medium equivalent path traveled in air is μ(BC+CD) and so, the optical path difference is μ(BC+CD)-BE
@@EngineeringPhysicsbySanjiv I have the same question, if we put a screen/lens parallel to the film, wouldn't BR1 and DR2 be the same? why do we subtract BE?
I've had this question for a long time, I would greatly appreciate an answer
Sir why are we using + - lamda/2
why not just +lamda/2 or - lamda/2
please reply......
In the condition if you count n from 0 we can write +lamda/2 and if you count n from 1 then -lamda/2.
So both are applicable depending starting value of n..
@@EngineeringPhysicsbySanjiv thank you very much Sir
Maxima and minima mein which one is dark and which one is bright
Maxima means constructive interference and it is bright.
Minima means destructive interference and it is dark..
@@EngineeringPhysicsbySanjiv thanku so much sir
Sir why we use cos in equation 2
Just check ∆BQC. In this BQ is perpendicular to QC and algle B = r. We want to find BC. So, We write cos(r)=BQ/BC = t/BC. So, BC = t/cos(r). Similarly, we find CD also from ∆DQ'C
Great job 👍
Thx sirrr
Tank you so much sir
Welcome.. and best luck
Sir answer to my question plz
interferance and difraction pattern
interference
Thank u sir
Welcome
The only thing you told in this video is just the screen script 👎🏻👎🏻
👍👍👍
🙏
Hindi me batao na 😢
Sir answer to my question plz