Chanakya - CA Wallah Enrollment Link : bit.ly/ChanakyaBatch_CA You can also watch these lectures in our App. Class notes will be provided Visit : 📲PW APP LINK - bit.ly/ChanakyaBatch_CA 🌐PW Website - www.pw.live
@@PushpanjaliTripathi-r9d 5 x 5 x 4 x 3......ye last mein 1,3,7 hi aa sakta hai isliye wahan 3 mein se koi ek aayega .....and at 1st place 5 kyuki zero nhi le sakte hain or ek place last fix hai so 5 aayega phir 2nd pe 5 kyuki 2 place fix hain 7-2 =5 phir 3rd pe 4 kyuki 3 place fix ho gaye 7-3 =4. After this you will got 5x5x4x3 = 300 Hope it will help you
You have made permutation and combination very easy,Earlier i was thinking to skip this Chapter but now i won't skip it and will try to gain as much marks as possible
1:24:21 sir in this que we can easily solve this as one head boy for ⁵P1 and for one head girl ³P1 and for school perrfect we have 6 students left as 2 are already posted so for that we use ⁶P1 and all is together so we use ⁵P1׳P1×⁶P1=90✅
@@sudhanshumishra1264 kyunki odd bnana h isiliye last m bss hum 1,3,7 consider kar sakte h and first place p 0 nhi ayega and ak number phale hi last place p ja chuka h so we left with 5 number and two places jo left h ab usme 5p2 follow ho g kyuki 2 number already filled ho chuka h first and last place p to ab 5 number hi bacha 2 seats k liye hope you understand ☺️.
Sir 2:52:45 me Q.62 ka counting sequence 5×5×4×3=300 hoga na because question ne puvha tha ki kitne odd no. ban sakte hai, naa ki kitne no. ban sake hai! BTW thankyou for teaching in such a easy way, sir!
@@PushpanjaliTripathi-r9d kyunki thousandth place pe 0 nahi aa sakta varna woh 3 digit no. ban jayega, toh khali 5 no. Ko daal sakte he udhar, now hundredth place pe 0 aa sakta hai, but joh ek no. Humne thousandth place pe daale the woh dubara nahi aa sakta, toh 5 no. Hi daal sakte hai, for tenth and unit place, 4 and 3 no. Respectively daalenge, joh remaining no. bache he woh daale
@@PushpanjaliTripathi-r9d here, "22225" is a odd no. But isme 2 no. Even hai tab par bhi last no. 5 hai joh ishe odd banata hai, toh iska matlab pehle char no. Kuch bhi ho, par last no. Odd hona chahiye, only then yeh odd no. Banega, tabhi maine 5×5×4×3 likha jisme last me 3 likha, kyunki utne hi odd no. Hai
Question 6th mein 5p4 hona chahiye na But sir ne to alag hi kr diya Aap batado ki jo sir ne kiya hai wo sahi hai ya nahi😂or agar sahi hai to kaise? Plz reply
Bhai ab soch hum maths Wale ki kaisi lagi rahahti hai 2 saal Tak maths padne me in 11th and 12th jabki tab ka maths ca foundation ke maths kaa baap maths hota hai
Question 6th mein 5p4 hona chahiye na But sir ne to alag hi kr diya Aap batado ki jo sir ne kiya hai wo sahi hai ya nahi😂or agar sahi hai to kaise? Plz reply
Pehle mujhe bhi yahi laga tha but this ques is different We can post a letter in any of the 4 letter box meaning for each letter we have 4 different ways We can put multiple letters in a single letter box also (like we do it in real life) Toh har letter ko post krne ke liye 4 ways hai toh ans 4 ki power 5
Chanakya - CA Wallah Enrollment Link : bit.ly/ChanakyaBatch_CA
You can also watch these lectures in our App.
Class notes will be provided
Visit :
📲PW APP LINK - bit.ly/ChanakyaBatch_CA
🌐PW Website - www.pw.live
Sir in question no.23 if only boy and a girl become perfect but no. Of holding position is 8, 5 boys and 3 girl .....
Confirm the ans sir
sir agar koi concept exam me samaj nahi aaye to tukka marna bhi sikhao sir
1:26:00 circular permutations
1:42:00 permutations with restrictions
2:05:00 combination
Thank you brother ..👍
Thanks
Thank you
Thanks bro
2:52:20 Q62. 5 x 5 x 4 x 3 = 300 (kyunki pehle last digit ko 3 option dekhna hoga because sirf odd number hi ban sakta hai)
👏
6×6×5×3 aayega
@@Shubham-gn6eu540 to option me hi nhi ha pagal
@@sharmajikakhoon iska sahi answer kaise or kyu aaya
@@PushpanjaliTripathi-r9d 5 x 5 x 4 x 3......ye last mein 1,3,7 hi aa sakta hai isliye wahan 3 mein se koi ek aayega .....and at 1st place 5 kyuki zero nhi le sakte hain or ek place last fix hai so 5 aayega phir 2nd pe 5 kyuki 2 place fix hain 7-2 =5 phir 3rd pe 4 kyuki 3 place fix ho gaye 7-3 =4.
After this you will got 5x5x4x3 = 300
Hope it will help you
Sir chanakya batch ki wajah se ca banne ka sapna pura hota nazar aa rha h thanks to ca wallah team for amazing efforts and support 😊❤
You have made permutation and combination very easy,Earlier i was thinking to skip this Chapter but now i won't skip it and will try to gain as much marks as possible
Hey can I go for this chapter as I didn't had maths in 11-12th
@@pr0digy261 Yaa Sure
Just make your Concepts Strong
@@pr0digy261 you should not skip this chapter
@@rahulbhutani_educator I have covered in maths- 1,2,4,6 and in stats- 13,14,17,18 and full LR
@@rahulbhutani_educator sir what should be the answer of Q31?? Please tell us
Sir you have made this chapter understandable.
Thanks Sir 🙏🙏
Watching this one day before june 2024 examination 🗿🗿
Us Bro 🤣
Paper kesa hua
@@ItzSneha18apka kaisa gaya, me September me Dene wala hu batayiye
Thik thak tha @@BSh-zq5sv
Result kya aayA
Sir i am watching today lecture. Very hopefully video tqq sir. June 24
let's crack it ❤💯💯💯💯💯
Most helpful video for revision thank you sir❤❤
Q42.when C.A needs 2 accountants and 7 men apply. Then the ways the selection can be done? Answer 21
ans is 56 (7C2)
In q 32 , answer is 5!×2!=240
How bro
R A J S (AE)
⁴p2 = 4!×2! =
25:09 sir ye question to 11th ke ncert me v he 👀
Best video for permutation and combination ❤
Who is preparing for june 2024
Me
me
thank you sir for amazing teaching
Awesome sir.....I have understood very well
Q,8(A)= 40320, yes we are piro of poc 😀 , thanku so much sir for such a great lecture.......
🌟🌟🌟
1:24:21 sir in this que we can easily solve this as one head boy for ⁵P1 and for one head girl ³P1 and for school perrfect we have 6 students left as 2 are already posted so for that we use ⁶P1 and all is together so we use
⁵P1׳P1×⁶P1=90✅
Bhai tumne pura lecture dekha?😢
Mene chod dia h bhai ye chapter agar koi simple que aa gya to thik nhi to chod k aaunga
He is God of Permutation and Combination !
Let's see
In Q 62 , ANS is 300 ( 5*5*4*3)
Kaise ayega
@@sudhanshumishra1264 kyunki odd bnana h isiliye last m bss hum 1,3,7 consider kar sakte h and first place p 0 nhi ayega and ak number phale hi last place p ja chuka h so we left with 5 number and two places jo left h ab usme 5p2 follow ho g kyuki 2 number already filled ho chuka h first and last place p to ab 5 number hi bacha 2 seats k liye hope you understand ☺️.
Mera bhi yahi aaya tha
@@Barbie01829😅
thanks bhai @@Barbie01829
Can i watch this lecture not for the purpose of revision but for the first time purpose will it be helpful
Question 66 answer 441 and question 67 answer 7 ❤ thanks me later
Sir you are great
Thanku thanku thanku so much sir ..etni detail m maine regular classes m bhi NH kiya 🙏
Q62 I think it should be 6*6*5*3
Because it requires only odd numbers
No bro its 5*5*4*3 question is asking for odd number condition ko first priority denge
@@vancedaccount8783 but as per the hint given by sir it's 6*6*5*4
Please Check 02:52:46
@@sabimahaseth625 sir se bhi kabhi kabhi bhool chuk hoo jati hai bro
@@vancedaccount8783 okay...thanks
Plz explain Kro koi 5 kaise hoga odd number toh 4hi hai
Q,34= first part answer is 1470
Hello bapes
How u doin?
Kaise
Q62 wrong hai
Correct ans is 5*5*4*3=300
Most difficult lesson😔
Practise krte rho bro , hojayega yr
Integration 😮
Revision done sir thankyou 😊
pura lecture dekha kya bhai apne 😢
@@Soulmotivater16 hmm
2:29:22 - special applications
Very easy🎉
Sir only because of you now I am atleast able to solve some😭🙏🛐
Wait for it
2:59:14 Q 66 ans (d) 441
Sir 2:52:45 me Q.62 ka counting sequence 5×5×4×3=300 hoga na because question ne puvha tha ki kitne odd no. ban sakte hai, naa ki kitne no. ban sake hai!
BTW thankyou for teaching in such a easy way, sir!
Why u have taken 5 please explain
@@PushpanjaliTripathi-r9d kyunki thousandth place pe 0 nahi aa sakta varna woh 3 digit no. ban jayega, toh khali 5 no. Ko daal sakte he udhar, now hundredth place pe 0 aa sakta hai, but joh ek no. Humne thousandth place pe daale the woh dubara nahi aa sakta, toh 5 no. Hi daal sakte hai, for tenth and unit place, 4 and 3 no. Respectively daalenge, joh remaining no. bache he woh daale
@@Supreme_Reader but usme odd bola hai or add to 3 numbers hi given hai
@@PushpanjaliTripathi-r9d here, "22225" is a odd no. But isme 2 no. Even hai tab par bhi last no. 5 hai joh ishe odd banata hai, toh iska matlab pehle char no. Kuch bhi ho, par last no. Odd hona chahiye, only then yeh odd no. Banega, tabhi maine 5×5×4×3 likha jisme last me 3 likha, kyunki utne hi odd no. Hai
@@Supreme_Reader thank you brother 🙏 ab smjh aagya
Ans. Of Q.35=1470,840
Beautiful Lecture ❤❤❤❤
42) 21 Ans
1:17:58 idher dimag ka dahi ho gya sir kh rhe h simple 🥲
guys question no 62 is wrong and the correct answer is 300.
6×6×5×3 kyun nhi hoga???
sir , in question no 29 is arrangement needed or we can apply combination?
Q.6 :
Ans.1024
Thank you so much sir for make easy this chapter with easy method 🥹
Q.62
5×5×4×3=300
Q66-Ans 441
Question 6th mein 5p4 hona chahiye na
But sir ne to alag hi kr diya
Aap batado ki jo sir ne kiya hai wo sahi hai ya nahi😂or agar sahi hai to kaise?
Plz reply
Jisko smjh nhi aaya vo Dear sir ki permutations and combinations dekho ek baar sb smjh aayega 👍
I had a doubt in a probability question...
I watched this lecture for revision and my doubt is solved (of probability)
🫣❤️❤️
❤️
Bhai ab soch hum maths Wale ki kaisi lagi rahahti hai 2 saal Tak maths padne me in 11th and 12th jabki tab ka maths ca foundation ke maths kaa baap maths hota hai
Q.62 answer is 720. But there is no option for this answer
Ans. Of 32Q.=120
How my is 240
Question 62 hoga odd no. Formed kerna hai so 5 *5*4*3 = 300 b option right
Thank You Sir 🤍
13:26 Sir ji ko to pura menu Yaad h ❤🔥
THANK YOU SO MUCH SIR AAPKI WJH SE SB SAHI SE SMJH AARA H 💗💓
sir 34 ka answer kay hay?
Sir concept to clear h lekin sum solve nahi ho rhe
Thank you so much sir❤
Have you cleared then?
604800 is the ans of q13 d
45:58 Sir n(n-1!) hoga..
Q.69= b( option )
Sir gap rule aur dictionary rule samjha do
Question 8 A answer is 8!= 40320
thanks sir all teacher concepts clear except economics very fast lectures not cleared dout
2:43:55 PYQ
1:54:03 sir waha T nai E lagana tha 😂
1:23:58 Me Sir Aap Permutation kyu lga rhe ho jb wha pr Question me Choose krne ko kha h to
Wha pr Combination kyu nhi lgega ?
Studying permutation❌️ Studying rajma and chole ✅️
1:58:08 Q37 Why did you divide 5!.3! sir. as per example8 in study material(same model question), didn't divide. could you please explain sir☺
Thank u sir🙏
Q26 mein end mein 1 lady bachegi toh 2 kyu Li total 3 heee toh hai bas
Sir que.43 me aapne divide me n-r! Nhi liya only 2! Se divide krvaya hai. PLZZ confirm the answer
8 factorial is 40320
2:52:42 300
2:52:46 ans 300
Sir in question no 62 apne odd number nhi pdha ❤
n^r = 4^5
pro of accounting
Sir y last year exam k questions kaha milenge❓❓
Scanner kharid le Bhai
@@jaydevjagtap8528 already purchased bhai i thought sir icai ki website se kuch bta rhe hai 😅
Thanks sir Apki Wajah sh kayi Dino ka chapters 2din Mai hogya hai, love you sir 😍😍
Very nine lecture sir
nice teaching sir
Q.31=(n-1)!(n-2)..
How?
N! Ko expand krke n(n-1)! Ho jayega fir common le li @@VCeditss
Very difficult chapter
thank u sir😍
Sir your "COMPUTER" question...answer is wrong it's coming 40319 in the ICAI book
Yes wrong icai books
Jai jai shree radhe
Whenever I try to solve the questions of this chapter, everytime I failed to interpret the question 😢
2:52:40 Sir Que.62 M Kuch Or Hi Answer Aa Rha Hai?
300 ho g
Ha bhi answer nahi match ho raha hai❤
Odd number puccha hai😮
3:01:05 Ka 7 Answer Ayega Maine Sir Go By Formula Se Kr K Dekha Hai Kya Vo Shi hai
1:25:46
Phase 1 mae kon kon sae chapter btaya Sir nae ??
Sir i can't find a batch in app
Sar q31 ka answer kese ayega
2:47:20 me doubt h sir
Question 23 mein yea bhi tho likha hai school perfect ke leye dono eligible hain
Question 6th mein 5p4 hona chahiye na
But sir ne to alag hi kr diya
Aap batado ki jo sir ne kiya hai wo sahi hai ya nahi😂or agar sahi hai to kaise?
Plz reply
Pehle mujhe bhi yahi laga tha but this ques is different
We can post a letter in any of the 4 letter box meaning for each letter we have 4 different ways
We can put multiple letters in a single letter box also (like we do it in real life)
Toh har letter ko post krne ke liye 4 ways hai toh ans 4 ki power 5
Question no.31 Answer?
(n-1)!(n-2).
Q31 Ans:- (n-2)(n-1)!
Bhai bta de kaise aaya
Sir q20 mai aapne 8 paper +1paper kyu kiya total to 10 hai na 1:17:15
@Rahul Bhutani
Sir what should be the answer of Q31? Please tell us
(n-1)![n-2]
Is this correct ??
@@divyanijha yes it is correct balak
@@rahulbhutani_educator okk sir😌😊
Sir Q62 ka answer 720 aa raha hai pr wo option me nhi hai
Wese question me odd no of four digit hai to number ending with odd digit consider nhi krenge kya?