Only the resistors dissipate heat and it is equal to the power consumer: P = I^2 R So for the top resistor: P = I^2 R = ( 2 A)^2 (6 ohms) = 24 W (24 J / sec)
Sir,, may I know why is there no current flow across the bar wire,, a bit confusing there,, also,, I would like to make a reconfirmation regarding the current flow: the current at first flows through the capacitor but once the capacitor is full it will just move directly through the resistor as in we imagine there is no capacitor at all is it ? ,,
After steady state is reached (after the switch is closed), no current will flow through the capacitors, since they will then be fully charged. (That is not the case in the transient period when they are charging). Since no current can flow through the capacitors , there is no place for the current to go and therefore there is no current through the switch.
@@MichelvanBiezen I see,, well the capacitor is connected to the positive terminal (current flow) as there is no current flow through it ,how come the resistor still has current flow through it...
Current is always able to flow through a resistor. In this example the resistors offer a separate path for the current. The current can still flow from top to bottom by going through the resistors and no current will flow through the capacitors after they fill up with charge.
The concept of the RC circuit typically applies to a circuit where the voltage applied changes as a function of time, (by closing a switch or by applying a time varying voltage).
Good teacher from UGANDA
Thank you. Welcome to the channel.
Sir !
at the part of the charge through switch, why don't we subtract 36 from 18 ? as 36 is a negative charge and (18) is a positive charge.
Best teacher love from india
Thank you and welcome to the channel!
U r great. Really very well explained. Thank you sir
You are awesome if they asked heat loss after switch closed how should we do it
Only the resistors dissipate heat and it is equal to the power consumer: P = I^2 R So for the top resistor: P = I^2 R = ( 2 A)^2 (6 ohms) = 24 W (24 J / sec)
@@MichelvanBiezen literally amazed by ur instant reply I wish u best of best sir u cleared lot of confusions
Thankyou !!!
ohhh, i was so confused about what to do when the switch closed- about the voltage across. it was so simple.
Sir,, may I know why is there no current flow across the bar wire,, a bit confusing there,, also,, I would like to make a reconfirmation regarding the current flow: the current at first flows through the capacitor but once the capacitor is full it will just move directly through the resistor as in we imagine there is no capacitor at all is it ? ,,
After steady state is reached (after the switch is closed), no current will flow through the capacitors, since they will then be fully charged. (That is not the case in the transient period when they are charging). Since no current can flow through the capacitors , there is no place for the current to go and therefore there is no current through the switch.
@@MichelvanBiezen I see,, well the capacitor is connected to the positive terminal (current flow) as there is no current flow through it ,how come the resistor still has current flow through it...
@@MichelvanBiezen sorry for my frequent question...
Current is always able to flow through a resistor. In this example the resistors offer a separate path for the current. The current can still flow from top to bottom by going through the resistors and no current will flow through the capacitors after they fill up with charge.
@@MichelvanBiezen oriteee,, thanks a lot,, sir,,
So clear..thank you
Amazing sir
Wouldn't this be considered an RC circuit as there are both resistors and capacitors in the same problem? thanks
The concept of the RC circuit typically applies to a circuit where the voltage applied changes as a function of time, (by closing a switch or by applying a time varying voltage).
thank you very much sir
great!!
Crappy teacher.. so sad.
no one's forcing you to watch this