When the switch is open there cannot be any current, since the capacitors block the current. If there is no current, then there cannot be a voltage drop across the resistors. V = I * R
And what happens if we decide for instance to remove one capacitor from the circuit but AFTER it has been filled up with charge? Would the voltage across the part where the capacitor was located before we removed it (between the two points) still remain the same as if the capacitor was still there?
+Ida Faullend Heferer There is a lot of "that depends" with such a question. The best thing to do is to re-analyze the circuit to see how the removal of the component affects it.
Thank you very much for this video. Your clarity makes this problem simple, and it is extremely satisfying.
You are the James Bond
Sir as u are saying voltage at a = f on closing switch , then would current flow. Am I understanding wrong
Once the switch is closed, then there will be a current path through the two resistors and the current will be = V/R = 18V / 9 ohms = 2A
professor in switch open and switch closed you wrote C1 and C2 instead of Q1 and Q2 and great video btw thanks a lot !
+nikhil monarch
Thanks for pointing that out. It is appreciated.
why are the resistors 0V when the switch is open?
When the switch is open there cannot be any current, since the capacitors block the current. If there is no current, then there cannot be a voltage drop across the resistors. V = I * R
Michel van Biezen thank you prof
And what happens if we decide for instance to remove one capacitor from the circuit but AFTER it has been filled up with charge? Would the voltage across the part where the capacitor was located before we removed it (between the two points) still remain the same as if the capacitor was still there?
+Ida Faullend Heferer
There is a lot of "that depends" with such a question.
The best thing to do is to re-analyze the circuit to see how the removal of the component affects it.
Why voltage at b is 0 volt when switch is open plz answer me sir
When the switch is open, there is no current flowing through the resistor and therefore the voltage drop across the resistor must be zero.
@@MichelvanBiezen thank you sir