It is the first time that I feel proud on you when I watch this video sir...I properly understood whatever you teach you in this video... thankyou so much sir ....
You are confusing this with an alternative parameterization. You most often see X ~ Gamma(alpha, beta) But sometimes you see X ~ Gamma(r, lambda) where r = alpha and lambda = 1/beta
It is the first time that I feel proud on you when I watch this video sir...I properly understood whatever you teach you in this video... thankyou so much sir ....
Thank you, I was really struggling with the proof of the m.g.f of this distribution.
Thanks for the explanation, I understand
I'm from Indonesia 🙏❤️
Thank you, you helped me a lot
Nicely done, very helpful.
My boost I dey feel you
Very help, thank you!!
Thank you 😊
When u prove mean how do u make dx= Bdt and there is a rule in the integration said that dx must not be interpreted as a product of d and x
dx is just taken as 1.dx since differentiating both sides causes x to become 1. and Beta t to become Beta dt
thank you
Thanks!
well explained
I'm pretty confident this is wrong, because the expectation should be alpha/beta not alpha*beta?
You are confusing this with an alternative parameterization.
You most often see X ~ Gamma(alpha, beta)
But sometimes you see X ~ Gamma(r, lambda) where r = alpha and lambda = 1/beta
@@chrisgumb8986 Thanks