Couldn’t explain it clearer, great job on demonstrating these examples, I was able to understand on mute due to my location at the time I couldn’t turn up the volume
Thank you so much for showing this example of asymptotes. It made learning so much clearer. I am now looking to solve Oblique asymptotes, but cannot find your video for that? Do you have one? Also, I am so thankful you have the Vertex and other functions in your teaching videos. Your videos will get me through this college algebra!! Thank you again.
Yeah it's my summative exam tom and this is the Coverage for summative assessment. Gen. Math: asymptote problem solving involving rational equation(motion and number problem), exponential equation, exponential inequality, exponential function, logarithms and logarithmic properties. Pre cal: Systems of Non linear equation Series and sequence Sigma notation Fundamental identities
05:41 Actually, there's one more asymptote in this example: y = x² + x + 1. If you add it to your graph, you will see that the branches of the curve approach this parabola as `x` increases/decreases without bounds. 06:18 Well, at least not in the plane of the graph ;>
@@AadityaChawla-bc4ic Start with the rational function from the video: `y = (x³+2) / (x-1)`. Divide out the numerator `x³+2` through the denominator `x-1` (e.g. using polynomial long division) to get the polynomial part `x² + x + 1` and the remainder (which is still rational) part `3/(x-1)`. In other words, you get the following decomposition: y = (x³+2) / (x-1) = x² + x + 1 + 3/(x-1) Now observe what happens when `x` increases (or, for that matter, decreases) without bound: the denominator `x-1` in the last term (which is still rational) gets bigger and bigger, which means that you divide the numerator `3` into more and more parts, so each such part gets smaller and smaller, i.e. the entire fraction shrinks to 0, leaving just the polynomial part `y = x² + x + 1`, which is a formula of a parabola. This means that as `x` gets bigger and bigger (either positive or negative), the graph of this function starts looking more and more like a parabola `y = x² + x + 1`. Here's a graph that demonstrates it: www.desmos.com/calculator/kjs0e3ivya Notice how the blue curve approaches the red parabola as `x` gets more and more negative. But when `x` becomes more and more positive, approaching `x=1`, the curve gets farther from the parabola and starts approaching the vertical asymptote (which is a straight line) instead, `y` going towards `-∞`. Then it returns on the other side from `+∞` and starts diverging from the vertical asymptote and getting closer and closer to the parabola again as `x` increases even further (as well as `y`, going towards `+∞` again). You can also turn the green graph on or off to verify that these two formulas, `y = (x³+2) / (x-1)`, and `y = x² + x + 1 + 3/(x-1)`, are indeed the same function. Also try zooming the graph in/out with your mouse wheel to observe how the graph approaches the straight vertical line as well as the parabola as `x` gets bigger (disregarding its sign) without bounds.
Hi! can i attach the youtube link of your video to the self-learning modules of our department in order for the students to learn more from the contents of this video aside from the modules that will be distributed to them? Thanks a lot.
Thank you for your question. In that example, the numerator is prime and will not factor; thus no terms will cancel out. But you are right, if it did cancel, there would be a hole instead of an asymptote. Also, you can take a look at the graph for confirmation.
Ohh.....I see it now! There would be a middle term if the numerator were to be factored into (x+2)(x+2) I was not looking carefully XD Thanks for replying.
i don''t understand one thing, my professor uses limits to find them and no matter how many videos i look up they all use this method, am i missing something?
The numerator (3x^2+17x+10) will factor as (3x+2)(x+5). The denominator (x^2+7x+10) will factor as (x+2)(x+5). The (x+5) factors will cancel between the numerator and denominator. However, the denominator still has the (x+2) factor. So there will be a vertical asymptote at x=-2 (x=-2 causes the denominator to be zero), and a hole in the graph at x=-5 because those factors canceled. Hope that helps!
![I.N "HALLUCINATION" | [Stray Kids : SKZ-PLAYER]](http://i.ytimg.com/vi/n5B5q1Hwt_U/mqdefault.jpg)
I HAD NEVER UNDERSTOOD THIS EVER UNTIL NOW. THANK YOU.
Hahahahhaha me too 😂😂
OUR EXAM'S ARE TOMORROW. ITS 3AM AND I LOVE U
Same
I have a test tomorrow 😳
I like you because your question,s is so easy
Mine is in 30 minutes lol
good thing it wasn't an english exam
Dude you are amazing i didn't get it till i saw this. God Bless You sir.
Thank you. Every other source was explaining this so poorly. You nailed it.
u just explained that better than anyone on the internet and i love u for that
dude i love you for this no place has vertical and horizontal together thanks a lot
YOU ARE ABSOLUTELY AMAZING!!!!!! after searching for hours I come across this masterpiece and it literally saved my life. I cannot thank you enough..
You're the best! I've watched too many tutorials on this, they're all confusing af
Best explaination out of 100 vids
i am watching this video after 8 years and you explain everything in a perfect way that we can solve any similar problem thank you man
Woah 8 days ago
U have no clue how easy you made life for me. THANKYOUUU.
I'm glad I could help!! :-)
Just to add, I also enjoy your guitar picking and the songs in your videos!! Thank you!
Dang he should earn 1m subscribers than 1k something. This dude teaches greaterthan my professor!
thnk you im gonna cry
Honest mood
Thank you so much! Best tutorial on this topic I've found yet on youtube :)
thank u!! Finally someone covered all the examples!
Glad it was helpful!
Couldn’t explain it clearer, great job on demonstrating these examples, I was able to understand on mute due to my location at the time I couldn’t turn up the volume
Thank you! James This will help me to get quickly V.A and H.A in MCQ without wasting time on differentiating....
You are my savior, thank you!!!
Thanks ... you taught this topic very well 👌
Thank you man. You save my life.
Very clear explanation. Many thanks sir
Thank you for teaching this clearly!
Really understood it better! 😊
It became too easy now really Thank you soooooooooooooo much ❤️❤️
Best video ever may you stay blessed bro✌🏻
Dude after so long I got a high score in my math worksheets thanks to youuu
Awesome! I'm glad I could help!
my man saving my points at school.
amazing video! super clear and easy to follow
This video is simply very helpful for my homework
Thank you so much for showing this example of asymptotes. It made learning so much clearer. I am now looking to solve Oblique asymptotes, but cannot find your video for that? Do you have one? Also, I am so thankful you have the Vertex and other functions in your teaching videos. Your videos will get me through this college algebra!! Thank you again.
wow the only video i understood. thank you
DUDE YOU ARE AMAZING YOU JUST SAVED ME!
Easy, well explained and a nice variety, thanks man!
Thank you, James!
Thank you soo much for this video dude. Really helpful
thanks for wonderful explaination buddy♥️ easily i understand it, i love it bro
Thank you so much! Much more helpful.
thanks so much.
That was very helpful. ✌
thank you this helped me a lot in my calculus
Amazing explanation
Great explanation!!!!!
Thanks I’m so grateful!!
Thanks so much for the video! Have my Maths exam in 2 days and I didn't understand this until now!
Thank you James!
Thanks, I finally got it, thank you sooooo much!!!
Thanks, this actually HELP a lot
Thanks for you video! Great explanation ! I understood everything thanks to you!🙏
Excellent video. So helpful and succinct!
Thanks man!!Finally got it
THIS VIDEO SAVED ME
Not me getting ready for my.exam on the bus
Well explained 👍👍
I'm glad it was helpful! :-)
@@hsmathsolutions sir I just checked most of your video all are very well explained.❤️❤️
Love you Sir from India ❤️
I'm glad you are watching my videos and finding them helpful! Be sure to share them with your classmates!!
Yeah it's my summative exam tom and this is the Coverage for summative assessment.
Gen. Math:
asymptote
problem solving involving rational equation(motion and number problem),
exponential equation, exponential inequality, exponential function, logarithms and logarithmic properties.
Pre cal:
Systems of Non linear equation
Series and sequence
Sigma notation
Fundamental identities
For your non-linear systems needs... ruclips.net/video/ghKDGIHupYU/видео.html
Very helpful, appreciate it.
I mean in 1:55 why is the curve on the Quadrant 1 and not on Q2? Then the curve on Q3 not on Q4??????
Thank you for this sir!
Thank youu soo much ♥️♥️
Thanks alot, brother!
You're welcome. Glad it helped!
Thanks! U are the best
On 1:55 why is the curve on the upper right corner? Cant it be facing the left? And the other one to its right???
lexine potter 🗿
You're the best
Very helpfull sir
May god bless you... Amen!!!
Thank you so much!
Please Tell How to Plot this on Graph
But why is that rule please explain properly
Fyi x^2+1 can be factored, but it's factors are not on a real number graph.
We give values to hole equation or only x-3 for graph
thanks so much sir
Thanks ❤️
05:41 Actually, there's one more asymptote in this example: y = x² + x + 1. If you add it to your graph, you will see that the branches of the curve approach this parabola as `x` increases/decreases without bounds.
06:18 Well, at least not in the plane of the graph ;>
I don’t understand can you please elaborate.
@@AadityaChawla-bc4ic Start with the rational function from the video: `y = (x³+2) / (x-1)`. Divide out the numerator `x³+2` through the denominator `x-1` (e.g. using polynomial long division) to get the polynomial part `x² + x + 1` and the remainder (which is still rational) part `3/(x-1)`. In other words, you get the following decomposition:
y = (x³+2) / (x-1) = x² + x + 1 + 3/(x-1)
Now observe what happens when `x` increases (or, for that matter, decreases) without bound: the denominator `x-1` in the last term (which is still rational) gets bigger and bigger, which means that you divide the numerator `3` into more and more parts, so each such part gets smaller and smaller, i.e. the entire fraction shrinks to 0, leaving just the polynomial part `y = x² + x + 1`, which is a formula of a parabola. This means that as `x` gets bigger and bigger (either positive or negative), the graph of this function starts looking more and more like a parabola `y = x² + x + 1`.
Here's a graph that demonstrates it:
www.desmos.com/calculator/kjs0e3ivya
Notice how the blue curve approaches the red parabola as `x` gets more and more negative. But when `x` becomes more and more positive, approaching `x=1`, the curve gets farther from the parabola and starts approaching the vertical asymptote (which is a straight line) instead, `y` going towards `-∞`. Then it returns on the other side from `+∞` and starts diverging from the vertical asymptote and getting closer and closer to the parabola again as `x` increases even further (as well as `y`, going towards `+∞` again).
You can also turn the green graph on or off to verify that these two formulas, `y = (x³+2) / (x-1)`, and `y = x² + x + 1 + 3/(x-1)`, are indeed the same function.
Also try zooming the graph in/out with your mouse wheel to observe how the graph approaches the straight vertical line as well as the parabola as `x` gets bigger (disregarding its sign) without bounds.
You like mlp you don’t know math
@@himlolo Oh yeah? Then try me.
love u helped alot
i hope u r our math teacher, cos we just finished midterm exam, and no one passed the examination ☹️
Professor, good morning. You no longer posted math classes. I haven't received notice of his posts in a long time. (Brazil-RJ)
thanks a lot sir
How do you know how to graph these lines (functions) within the multiple vertical an horizontal asymptotes?
Outstanding
what makes the fraction rational?
Thank you so much
Thank you so much sir!!!!
Hi! can i attach the
youtube link of your video to the self-learning modules of our department in
order for the students to learn more from the contents of this video aside from
the modules that will be distributed to them? Thanks a lot.
Lemuel Castillano Yes. Sounds good.
Why did you equate the denominator to zero in case of vertical asymptot?
4:48 I have a question, if shouldn't you factor out the numerator and the denominator first and cancel out (x+2), which would be a hole?
Thank you for your question. In that example, the numerator is prime and will not factor; thus no terms will cancel out. But you are right, if it did cancel, there would be a hole instead of an asymptote. Also, you can take a look at the graph for confirmation.
Ohh.....I see it now! There would be a middle term if the numerator were to be factored into (x+2)(x+2) I was not looking carefully XD Thanks for replying.
Thank you I was so lost
Thanks xx thanks thank you X
Nice video
THANK YOU
Thank u sir
I LOVE YOU.
i don''t understand one thing, my professor uses limits to find them and no matter how many videos i look up they all use this method, am i missing something?
nice work
Thank youuuuu ♥️
thank you! I have a question like this 3x^2 + 17x + 10 / x^2 + 7x +10
The numerator (3x^2+17x+10) will factor as (3x+2)(x+5). The denominator (x^2+7x+10) will factor as (x+2)(x+5). The (x+5) factors will cancel between the numerator and denominator. However, the denominator still has the (x+2) factor. So there will be a vertical asymptote at x=-2 (x=-2 causes the denominator to be zero), and a hole in the graph at x=-5 because those factors canceled. Hope that helps!
Anyone watching from 2024
Thanks from pakistan
Thank you
What about vertical and horizontal shifts
We just not gonna talk about how he's doing all his math in pen?
what is the factor of x squared -2x? hope u can help me thank u
x squared -2x?
x^2-2x=x(x-2)
thank you so much
this is brillliant