How to Find the Standard Matrix of a Transformation: Transformations (3/4) [Passing Linear Algebra]

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  • Опубликовано: 1 ноя 2024

Комментарии • 22

  • @dman5678
    @dman5678 2 года назад +24

    Thank you for not explaining the spooky magic haha. The jargon and notation loses me when my professor does general proofs and stuff. Having a clear and concise example will helps me to understand the spooky magic of his lectures!

  • @aryangoyal9556
    @aryangoyal9556 3 года назад +11

    Now I get it
    Every other professor and youtuber is trying to prove the "spooky magic" which makes students lose interest in the video and sometimes the topic itself.
    Thank for too the point explanation.

  • @krukowstudios3686
    @krukowstudios3686 2 года назад +5

    You get straight to the point and explain it really well. Thanks!

  • @celeryystick
    @celeryystick 4 года назад +17

    Haha “spooky magic” I find your videos very helpful man and I like how explain things (casually fun and informative). Keep the good work up mannnn I hope you reach one million subs one day!

  • @andresvelacarriazo4962
    @andresvelacarriazo4962 3 года назад +2

    Thank you very much you´re really helpful to me!! I´ll really recommend your channel to my classmates who are as lost as I was

  • @mason33838
    @mason33838 4 месяца назад

    Straight to the point. Wow. Thank you.

  • @howardtafa6313
    @howardtafa6313 3 года назад +1

    thank you for that powerful explanation keep it burning

  • @アブダラファトマ
    @アブダラファトマ 2 года назад +3

    but you said in the previous video that if the transformation is 1 to 1, it has a pivot in each column, not row. which one is correct?

    • @souravchakraborty6766
      @souravchakraborty6766 Год назад +3

      Yes, for a 1-1 transformation the columns must be linearly independent which means that there must be a pivot in every column. Having a piviot in every row meant that the transformation is onto.

  • @osebmerkon2145
    @osebmerkon2145 Год назад +1

    Hi, I assume that this is the same as a representation matrix?

  • @leoye1790
    @leoye1790 2 года назад

    Damn I worked it out myself:
    for a transformation T(x) = Ax,
    the jth column of A = A*ej, as defined by matrix multiplication;
    A*ej = T(ej) as defined by T(x);
    Done.

  • @mattg9601
    @mattg9601 3 года назад +1

    Isnt the spooky magic just the fact that your multiplying the transformation (which is just a matrix) by the identity column by column. Which is the identity property A*In = A. Thats at least how I think about it.

  • @玉婷刘
    @玉婷刘 3 года назад

    thank you sooooooo much for this great video!!!!

  • @MichaelSalton
    @MichaelSalton 3 года назад +2

    that's some spooky magic

  • @lunna325demsp6
    @lunna325demsp6 2 года назад

    Thank you! It was very helpful:)

  • @evrrsince
    @evrrsince 10 дней назад

    the goat

  • @aaronlinneman4840
    @aaronlinneman4840 9 месяцев назад +1

    "but I'm not a math major, so I don't really care"

  • @elliotehn9038
    @elliotehn9038 2 года назад

    I love u

  • @richardzhouren8665
    @richardzhouren8665 4 года назад

    nice

  • @patrickting4445
    @patrickting4445 5 лет назад

    great