pH calculation for a polyprotic acid

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  • Опубликовано: 9 сен 2024
  • 7-6 This video describes how to calculate the pH for a general polyprotic acid, and carries out a numerical example for a 0.1 M solution of carbonic acid.

Комментарии • 36

  • @keggeria7249
    @keggeria7249 5 лет назад +5

    I have a final tomorrow and this greatly clears up titrations of polyprotic acids. I was always confused when to use Ka1 or Ka2 and you do a great job telling which one to use.

  • @ariamodir4750
    @ariamodir4750 3 года назад +1

    Helped me understand the material very well for my final tomorrow. Thank you.

  • @guillermojarne2803
    @guillermojarne2803 3 года назад +2

    You are really good at explaining!

  • @malshakakodikara4681
    @malshakakodikara4681 2 года назад +1

    You're a great teacher. Thank you

  • @weeb_slayr_6948
    @weeb_slayr_6948 4 года назад +1

    This was an amazingly helpful and clear video. Thank you!

  • @kub8675
    @kub8675 5 месяцев назад

    Great explication, thank you

  • @pancaker1793
    @pancaker1793 Год назад

    Youre a godsend! Love your videos!

  • @MariaFernanda-yv8tw
    @MariaFernanda-yv8tw 4 года назад +1

    Thank you very much! Such a great explanation!

  • @muhammadzeeshan5335
    @muhammadzeeshan5335 4 года назад +2

    extremely helpful lecture. Thanks

  • @Noobskism
    @Noobskism 3 года назад

    Great Video, this helped me a lot! Thanks!

  • @Selorm__
    @Selorm__ Год назад

    Herh Chale thank you wai 🎉😂😂😂

  • @chaera-vr5wv
    @chaera-vr5wv 5 месяцев назад

    Thank you!

  • @techno-sorcery9852
    @techno-sorcery9852 4 года назад

    Very helpful video. Thanks!

  • @adelinepangilinan2979
    @adelinepangilinan2979 4 года назад +1

    very helpful. fyi is the ka1 written incorrectly?

  • @hamedbarzinmehr
    @hamedbarzinmehr Год назад

    This method of yours may be useful. But one should keep in mind that equilibrium concentrations never change . In the second equation the equilibrium concentration of hydronium is greater than that in the first and that's wrong . The true way of solving this problem is by writing proton balance and mass balance equations and then use approximations

  • @ranasamir9462
    @ranasamir9462 3 года назад

    great explanation. thank you!

  • @Ankita-vu5fk
    @Ankita-vu5fk 4 года назад +1

    extremely helpful

  • @ryankorman8258
    @ryankorman8258 4 года назад

    Great video, thank you!

  • @amandaalfonso8330
    @amandaalfonso8330 6 лет назад

    Thank you so much! Help so much!!

  • @estiakahmed804
    @estiakahmed804 2 года назад

    Thanks

  • @shaqsquacks3886
    @shaqsquacks3886 4 года назад

    this video rocks!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!

  • @DeniseP
    @DeniseP 4 года назад

    very helpful Thank you

  • @nicoletsang8884
    @nicoletsang8884 4 года назад

    when writing a diprotic acid reaction of sulfuric acid, H2SO4 + H2O --> SO4 + H3O, there's a missing hydrogen on the product side, so how do you write the correct equation?

  • @cavelinguam6444
    @cavelinguam6444 5 лет назад

    Nice. Thank you.

  • @nucleophile
    @nucleophile Год назад

    Why you do t change H2CO3 conc. after HCO3- disociated, why it's not [H2CO3]=0,1-2,1*10^-4 - y

  • @abhi_sndhu
    @abhi_sndhu 2 года назад

    Thanks Sir.

  • @thewisefromwest6941
    @thewisefromwest6941 2 года назад

    Thank you sir

  • @lesliegeorge8050
    @lesliegeorge8050 5 лет назад

    Nice!

  • @princetonokwuoha7826
    @princetonokwuoha7826 4 года назад

    hello how can i reach you please? i need an analytical chem tutor

  • @maimohamed439
    @maimohamed439 3 года назад

    الله يسترك يا حاج والله

  • @chathunikulathunga3039
    @chathunikulathunga3039 2 года назад

    It’s true when they say bald men are good at everything;))

  • @user-uy6uu8cz7n
    @user-uy6uu8cz7n 3 года назад

    عراقي وافتهمتلك

  • @ramavittal3494
    @ramavittal3494 5 лет назад

    How do you got pH =3.89

    • @ramavittal3494
      @ramavittal3494 5 лет назад

      PH =3.68

    • @maanavsingh1914
      @maanavsingh1914 5 лет назад

      @@ramavittal3494 You take the negative log of H+ Ion Concentration. -log[H+] = -log[2.1X10^-4] ~= 3.68 ; pH = 3.68

  • @mjones7356
    @mjones7356 4 года назад

    Thank you!