I still don't get how you got 28 on the sum of abs value. Could you teach us how to plug in those numbers on our calculator because for some reason I got a 320 but if I plug it directly to the table I do get 28
Hm, that's odd. Did you: 1. in Y1, enter Y1 = x^3-6x^2+9x; 2. Go to home screen (2nd quit) and type abs(Y1(1)-Y1(0)) + abs(Y1(3)-Y1(1)) + abs(Y1(5)-Y1(3))? That should get you the right answer!
I prefer to compare the velocity and acceleration graphs. If velocity is above y=0 and acceleration is below y=0 then the object is slowing. This method doesn't really flex the second derivative's relationship to the first. Primary take away and probable lightbulb moment for many is when s''(t) =0 s'(t) hits local minima and decelerate back to s'(t)=0 now s'(t) and s''(t) >0 thus acceleration. Your lessons have been great by the way.
Thanks for the note! I think we just approach the conversation in class differently; I intro the concept through video & then we break down the connections in class. It looks like we are hitting the same key points, huge moment to talk about the relationship between f, f’, and f’’ for sure! I love this application and we come back to it at several moments throughout the course / these videos. Thanks again, and hope your year is going well!!
our goal is to make a sign chart based on the velocity equation. so... * interval 1 (less than 1): pick a number less than 1, say 0. put that into the velocity equation. we get 3(0-3)(0-1) which is a positive number. so we put a plus on the sign chart. * interval 2 (between 1 and 3): pick a number between 1&3, say 2. put that into the velocity equation. we get 3(2-3)(2-1) which is a negative number. so we put a minus on the sign chart. * interval 3 (greater than 3): pick a number greater than 3, say 5. put that into the velocity equation. we get 3(5-3)(5-1) which is a positive number. so we put a plus on the sign chart. hope that helps!
I'm not sure what you did wrong, but the answer to part (e) should be 28m (I just redid the problem to double check). |s(1) - s(0)| + |s(3) - s(1)| + |s(5) - s(3)| = |4| +|-4| + 20 = 4+4+20 = 28m
thank you so much! you've explained this so much better than my textbook AND my teacher!!
Adrian Aguila so happy to hear this video helped!! Good luck in your class :)
Thank you for this video it helped me greatly. Hopefully you have Calculus BC videos in the future
Really great method of teaching
Thank you!!
@@StaceyRoshan thanks to you mam for replying me
I still don't get how you got 28 on the sum of abs value. Could you teach us how to plug in those numbers on our calculator because for some reason I got a 320 but if I plug it directly to the table I do get 28
Hm, that's odd. Did you: 1. in Y1, enter Y1 = x^3-6x^2+9x; 2. Go to home screen (2nd quit) and type abs(Y1(1)-Y1(0)) + abs(Y1(3)-Y1(1)) + abs(Y1(5)-Y1(3))? That should get you the right answer!
I prefer to compare the velocity and acceleration graphs.
If velocity is above y=0 and acceleration is below y=0 then the object is slowing. This method doesn't really flex the second derivative's relationship to the first.
Primary take away and probable lightbulb moment for many is when s''(t) =0 s'(t) hits local minima and decelerate back to s'(t)=0 now s'(t) and s''(t) >0 thus acceleration.
Your lessons have been great by the way.
Thanks for the note! I think we just approach the conversation in class differently; I intro the concept through video & then we break down the connections in class. It looks like we are hitting the same key points, huge moment to talk about the relationship between f, f’, and f’’ for sure! I love this application and we come back to it at several moments throughout the course / these videos. Thanks again, and hope your year is going well!!
I still dont get (d) like how u got pos/neg 😅😅
our goal is to make a sign chart based on the velocity equation. so...
* interval 1 (less than 1): pick a number less than 1, say 0. put that into the velocity equation. we get 3(0-3)(0-1) which is a positive number. so we put a plus on the sign chart.
* interval 2 (between 1 and 3): pick a number between 1&3, say 2. put that into the velocity equation. we get 3(2-3)(2-1) which is a negative number. so we put a minus on the sign chart.
* interval 3 (greater than 3): pick a number greater than 3, say 5. put that into the velocity equation. we get 3(5-3)(5-1) which is a positive number. so we put a plus on the sign chart.
hope that helps!
Omg u have such a great voice
12:25 I get 25.
I'm not sure what you did wrong, but the answer to part (e) should be 28m (I just redid the problem to double check). |s(1) - s(0)| + |s(3) - s(1)| + |s(5) - s(3)| = |4| +|-4| + 20 = 4+4+20 = 28m
+Stacey Roshan thanks
I swear you've helped me so many times!!! Thank you!! ^_^
+EGM Thanks so much for the comment! Working on getting the rest of the AP Calculus curriculum up as soon as possible :)