Brilliant. I wish I could get all the time, money, and shells back that I spent with the “you’ll just feel when the lead is right, don’t see the barrel” instructors.
Perfect lesson, Ban!!! Qestion: how do you measure 18 inch, is it at the berrel or at the target? Or how much space you see at the berrel to figure it out that it is 18 inch at the target? ☝️☝️☝️👍👍👍
Watching this for another round. I understand the components of lead. My missing part is determining angle.90° and small angles I get. A as novice, can you begin with 0, 45 and 90 degrees? Or must you split it again? Trying to get a broad base to train before getting into finer details if possible? Like 5 Stand a trapshot at stand 1 is different at stand 5 (trap near stand 1)
Hello Ben, would you say a 42yard speed 5 would be 54” or 72”. 54” being 3 x 18”or 72” being double 18” for distance and then double again for speed? (2 x 18=36 x 2 = 72)
Brilliant. I wish I could get all the time, money, and shells back that I spent with the “you’ll just feel when the lead is right, don’t see the barrel” instructors.
Awesome, that simplifies things immensely.
Thanks for sharing 👍
Easy and simple. Great information 👍
Perfect lesson, Ban!!! Qestion: how do you measure 18 inch, is it at the berrel or at the target? Or how much space you see at the berrel to figure it out that it is 18 inch at the target? ☝️☝️☝️👍👍👍
18 inch at the barrel would give a lead of more than 20 yards...
Thank You.
Watching this for another round. I understand the components of lead. My missing part is determining angle.90° and small angles I get. A as novice, can you begin with 0, 45 and 90 degrees? Or must you split it again? Trying to get a broad base to train before getting into finer details if possible? Like 5 Stand a trapshot at stand 1 is different at stand 5 (trap near stand 1)
Hello Ben, would you say a 42yard speed 5 would be 54” or 72”. 54” being 3 x 18”or 72” being double 18” for distance and then double again for speed? (2 x 18=36 x 2 = 72)
Forgot to say bird is 90 degrees
Is this a way to train your brain to understand lead or something to be calculated on each stand every time?
B Hampshire every stand it’s target relevant
Brilliant recommendation.... DSAL
What happens at peg 6, angle is now higher than 90 deg, does that also Multiply so 135 deg is half again of the Lead for 90 deg?
The target changes completely because at peg 6 it is now an incoming target and lead would be 10" in my sight picture
Ben what speed was the speed 5 at
Watch this ruclips.net/video/BCy7FeByno0/видео.html and question will be answered.
😀😀😀😊👍🏼
Have you based the 18" lead around a pull away method Ben?
James Hardy correct