Exploring Flow & Time Constants in the mode of Pressure Control

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  • Опубликовано: 20 окт 2024

Комментарии • 9

  • @dougchism5085
    @dougchism5085 3 года назад

    Mr. Prost, I enjoyed this very much! Nicely done!

  • @christams8863
    @christams8863 2 года назад +2

    With a size 6.0 ETT, you obviously have higher resistance and, consequently, more turbulent flow through the ETT tube. Therefore, P(lung) of the lungs would reach P(mouth) much later, with a size 6.0 ETT. P(lung ) would reach P(mouth) faster with a 8.0 ETT. You can see the inspiratory pause for a size 6.0 ETT is shorter than the inspiratory pause for a size 8.0 ETT. The lungs spend more time at P(mouth pressure) with an 8.0 ETT than that of a 6.0 ETT: therefore, a smaller tidal volume for a 6.0 ETT and a larger tidal volume for a 8.0 ETT.

  • @rajasekharthottadi5151
    @rajasekharthottadi5151 6 лет назад +1

    Nice presentation..Very simplified , thankyou

  • @sinclair657
    @sinclair657 Год назад

    Thank you

  • @marcopolo2028
    @marcopolo2028 5 лет назад +1

    i dont understand how you're getting the resitance to calculate flow. To calculate flow we got the change in pressure by subtracting Pmouth and Plung but what value are we using to calculate the resistance to divide.

  • @Suzi_P
    @Suzi_P 5 лет назад +1

    Thanks so much

  • @paediatriciandoctorzahidhu8360
    @paediatriciandoctorzahidhu8360 4 года назад

    Hi dear, in Simv mode if set RR is 12 and patients takes 14 breathes of his own... than how many breathes will receive the set vt?

  • @ДенисЮденков-ь5ж
    @ДенисЮденков-ь5ж 6 лет назад +1

    Please, make video about forced oscillation technique in ventilation

  • @venkybly
    @venkybly 3 года назад

    Tq