It’s playing of sooo much importance for today’s demand of “Carona infection” Well, good work always remain much worthy and long lasting..!!! Thanks for the description..
Hi sir,I have a question regarding the tidal volume of one of your examples using the test lung with compliance of 80ml/cmH2O and Resistance of 5,with enough Ti (meaning 5 time constant,in this case will be 0.4x5=2s ) and using the equation of change in volume =compliance x change in pressure ,with that equation ,the tidal volume will be 80x(25-5)=1600ml and not 1026ml as in the example of yours.may I know what’s the reason of causing the difference in Vt?
What a great video!
Thank you from the bottom of my heart.
Loved this, thank you so much! Great video.
Awesome video. Very thorough. I get it finally.
Thank you very much
Excellent explanation!
This is very helpful. Thank you
It’s playing of sooo much importance for today’s demand of “Carona infection”
Well, good work always remain much worthy and long lasting..!!!
Thanks for the description..
you are the best!!
wonderful, thank u sooo much..
Very helpful video. Thank you
Thanks a lot for the video. It helped a lot.
with what program did you do this video?
Hi sir,I have a question regarding the tidal volume of one of your examples using the test lung with compliance of 80ml/cmH2O and Resistance of 5,with enough Ti (meaning 5 time constant,in this case will be 0.4x5=2s ) and using the equation of change in volume =compliance x change in pressure ,with that equation ,the tidal volume will be 80x(25-5)=1600ml and not 1026ml as in the example of yours.may I know what’s the reason of causing the difference in Vt?
Please explain us Adaptive support ventillation too sir plzzzz⚓️