Hijacking this top comment to say that I have commented a detailed explaination in my comment on 4th Feb 2024. If you find that you will understand the concept
Number of parity bits in the final code: lowest possible value of n that satisfies [ 2^n >= no. of bits in codeword ] Parity bits location in codeword = 2^n where n starts from 0 (go until the position value exceeds the number of bits in codeword) Finding the value of parity bits works in this way: - Take the position number of the parity bit, for example 2 as p1's position is 2. - We will write down the identifiers of 2 bits and then skip two bits and write down the id of the next 2 bits. In our example we will write down p1 & d0 then skip over 2 ids which are p2 & d1 then we write down next 2 which are d2 and d3. (For position number n will accept n skip n accept n skip n and so forth till the end, including the postion of the parity bits of course.) We now have the following identifiers with us now: p1 d0 d2 and d3 - We now remove the parity bit ids and xor the remaining data bits, in our case those are: d0, d2, d3. Hence p1 = d0 XOR d2 XOR d3 - If we were to calculate for p2 which is at position 4, we will accept 4 skip 4 accept 4 skip 4 and so forth till the end. In that case we will have the following ids: p2 d1 d2 and d3 - Now we remove parity bit ids and xor the remaining. Hence, p2 = d1 XOR d2 XOR d3
For those who failed to understand how Parity value was being extracted and set. Each redundant bit, ri, is calculated as the parity, generally even parity, based upon its bit position. It covers all bit positions whose binary representation includes a 1 in the ith position except the position of ri. Thus − ---r1 is the parity bit for all data bits in positions whose binary representation includes a 1 in the least significant position excluding 1 (3, 5, 7, 9, 11 and so on) ---r2 is the parity bit for all data bits in positions whose binary representation includes a 1 in the position 2 from right except 2 (3, 6, 7, 10, 11 and so on) ---r3 is the parity bit for all data bits in positions whose binary representation includes a 1 in the position 3 from right except 4 (5-7, 12-15, 20-23 and so on)
Sir, please teach us only on board,we are finding difficult to understand while your are teaching by this digital method🥺.Anyway we love your teaching❤️😌
I'm loving the series. This is the first video where I failed to understand how Parity value was being extracted. Hoping, someone can share some clarity in a reply.
its because of the 1 present in corresponding binary value of the position numbers. may be you didn't get it. you would understand if I could upload a photo in comment section.
I am continue with his channel for last 4-5 days because my are coming after a week few minutes ago I was watching COA playlist and this notification comes your explanation is amazing it helps me alot to understand these terms very easily.
VERY NICE, ITS WOULD BE AWESOME IF YOU COULD UPLOAD A PLAYLIST ON C++ PROGRAMMING (theoretical and practical with A-z compiler demo ). YOUR TEACHING METHOD IS AWESOME.
I think you made a mistake near the end there? What you said didn't make sense, could you explain that please? You recalculated the XOR of the error induced output, then you realized that it still came 1 even with the error then without acknowledging that you said the error is there because the number of 1s is odd, but you also said that the receiver calculates the XORs again to check for errors, then why must the receiver calculate the XOR if all it needs to see is whether the 1s are odd or even? And if it does calculate it again, the answer comes out as 1 anyway, so how does it know it's an error? Something went wrong there as it doesn't make sense. Would be very kind of you if you could explain it in a comment or a video. Thank you.
I am following this course. all your lectures are amazing but everything you taught on the digital screen is kinda confusing. for me, it's hard to understand. when you use a marker and whiteboard we can see your hands moving. but on this screen, we can't see that. that's why it's hard to understand.
Thank you sir for your hard work all your videos are good your whiteboard explanation is awesome. I really wanna request you to explain this topic on white board thank you s for reading 😊👏🤩👨🏫
Agar kisiko samjh ne problem hui to chalo chota trick bata deta hu! Jis vi position ki parity calculate horahi he! Us bit ka jo vi number he suppose 2 To hum 2 bit lenge then 2 bit skip karenge then repeat! For 4th position we take 4567 then skip 891011
Each parity bit controls specific bits in the data according to their position. The rules are simple: P1 checks bits 1, 3, 5, 7, ... (all bits where the binary position has a 1 in the least significant bit). P2 checks bits 2, 3, 6, 7, ... (all bits where the binary position has a 1 in the second least significant bit). P4 checks bits 4, 5, 6, 7, ... (all bits where the binary position has a 1 in the third least significant bit).
Sir apne 11 bit wale mei thode se confuse ho gaye, while calculating or checking if the parity bit is valid or not, we must take the XOR of the data bits but aap first 1 ko bhi le rahe the, which is the parity bit we are calculating. Hope this solves some confusion. Otherwise really good video sir.
@@suman8336 1st bit is the parity bit so don't take it and calculate XOR of the data bits. you will get wrong answer when you change the original 9th bit.✌️
Sir this is the first video of yours I didn’t get is seriously
Sir, please redo this on white board.
Must neded sir....🙏
++
Exactly
Yes
+1
Please teach on white board it will extremely helpful and you explained more clear than on digital board🙏🙏🙏
bhaiii aisa lag rah hai sir nasha karke padha the hain , jaha detect karai waha correct bol diya jaha coreection batana tha waha detect bol diya 6:02
@@Shivaay.productions0777hmmm galat padhaya orr sabko galat raste me bula rahe he
Hijacking this top comment to say that I have commented a detailed explaination in my comment on 4th Feb 2024. If you find that you will understand the concept
The problem is that it's not even a "board"
Number of parity bits in the final code: lowest possible value of n that satisfies [ 2^n >= no. of bits in codeword ]
Parity bits location in codeword = 2^n where n starts from 0 (go until the position value exceeds the number of bits in codeword)
Finding the value of parity bits works in this way:
- Take the position number of the parity bit, for example 2 as p1's position is 2.
- We will write down the identifiers of 2 bits and then skip two bits and write down the id of the next 2 bits. In our example we will write down p1 & d0 then skip over 2 ids which are p2 & d1 then we write down next 2 which are d2 and d3. (For position number n will accept n skip n accept n skip n and so forth till the end, including the postion of the parity bits of course.)
We now have the following identifiers with us now: p1 d0 d2 and d3
- We now remove the parity bit ids and xor the remaining data bits, in our case those are: d0, d2, d3. Hence p1 = d0 XOR d2 XOR d3
- If we were to calculate for p2 which is at position 4, we will accept 4 skip 4 accept 4 skip 4 and so forth till the end. In that case we will have the following ids: p2 d1 d2 and d3
- Now we remove parity bit ids and xor the remaining. Hence, p2 = d1 XOR d2 XOR d3
For those who failed to understand how Parity value was being extracted and set.
Each redundant bit, ri, is calculated as the parity, generally even parity, based upon its bit position. It covers all bit positions whose binary representation includes a 1 in the ith position except the position of ri. Thus −
---r1 is the parity bit for all data bits in positions whose binary representation includes a 1 in the least significant position excluding 1 (3, 5, 7, 9, 11 and so on)
---r2 is the parity bit for all data bits in positions whose binary representation includes a 1 in the position 2 from right except 2 (3, 6, 7, 10, 11 and so on)
---r3 is the parity bit for all data bits in positions whose binary representation includes a 1 in the position 3 from right except 4 (5-7, 12-15, 20-23 and so on)
Thanks a lot broooo
bro r8 ki samjh ni i bus
Samajh ni aaya
Thanks bro
long live this comment
Sir, please teach us only on board,we are finding difficult to understand while your are teaching by this digital method🥺.Anyway we love your teaching❤️😌
I'm loving the series. This is the first video where I failed to understand how Parity value was being extracted. Hoping, someone can share some clarity in a reply.
its because of the 1 present in corresponding binary value of the position numbers. may be you didn't get it. you would understand if I could upload a photo in comment section.
watch this
ruclips.net/video/V3N6PkmZ5Ok/видео.html
U r ginius sir!!! Hand's off
Sir Jo lecture ap deliver krtay hey bht hi helpful thanks a lot for your time and effort # love from Pakistan
I am continue with his channel for last 4-5 days because my are coming after a week
few minutes ago I was watching COA playlist and this notification comes
your explanation is amazing it helps me alot to understand these terms very easily.
Very well explained, but it would be good if explained with white board
VERY NICE, ITS WOULD BE AWESOME IF YOU COULD UPLOAD A PLAYLIST ON C++ PROGRAMMING (theoretical and practical with A-z compiler demo ). YOUR TEACHING METHOD IS AWESOME.
Buddy! I love your way of teaching. Best teacher ever.❤ I wish I could send you a gift.
this is the one of your lecture which is difficult to undersand for me.
Yes ...plz reupload this video on white board....otherwise your teaching technique is awesome.
I think you made a mistake near the end there? What you said didn't make sense, could you explain that please? You recalculated the XOR of the error induced output, then you realized that it still came 1 even with the error then without acknowledging that you said the error is there because the number of 1s is odd, but you also said that the receiver calculates the XORs again to check for errors, then why must the receiver calculate the XOR if all it needs to see is whether the 1s are odd or even? And if it does calculate it again, the answer comes out as 1 anyway, so how does it know it's an error? Something went wrong there as it doesn't make sense. Would be very kind of you if you could explain it in a comment or a video. Thank you.
Sir please start giving notes, your channel will become the best channel
sir, i think your first video that I couldn't understand this concept.
I am following this course. all your lectures are amazing but everything you taught on the digital screen is kinda confusing. for me, it's hard to understand. when you use a marker and whiteboard we can see your hands moving. but on this screen, we can't see that. that's why it's hard to understand.
One shot video bnado sir plz is topic ki again🙇
Thanks your lectures are very helpful . But I didn't understand this lec . Try to teach us on White board. Thanks
Thank you sir for your hard work all your videos are good your whiteboard explanation is awesome. I really wanna request you to explain this topic on white board thank you s for reading 😊👏🤩👨🏫
♥️Sir Please 🙏 complete Digital Logic syllabus...i am not want to going to another channel for this subject only.. because you are awesome sir ♥️
Agar kisiko samjh ne problem hui to chalo chota trick bata deta hu!
Jis vi position ki parity calculate horahi he!
Us bit ka jo vi number he suppose 2
To hum 2 bit lenge then 2 bit skip karenge then repeat!
For 4th position we take 4567 then skip 891011
bohut sukriya meri vai🥰
Thanks sir 😊
Good explain
Y topic achhe s clear ni ho paya yha esa lg rha h koi ni h hmara jab koi video aap s milti ni to bht afsos hota h😢
i think p0=1 at 5:19
❤❤❤
Sita Ram 🙇♂️✨
sir it is too confusing concept is clear pls make a video on this on white board
nothing is understandable
We want lectures on Whiteboard!!!!!
Sir software engineering ka aur videos add kijiye🙏💙💚
sahi hai bosh
Thank you so much ❤
Sir please teach this once more on white board I am unable to understand it through this method .
Sir formula for p1,p2 and p0 are always same or different??
please do it slowly it's looking you are revising the concept
RUclips sir🤡my friend before 5min exam🗿
Sir padhaya to aapne bhut ache tarike se h but data in screen is not much clear...as a feedback m saying dis....except dat all is very nice...
If you are getting problem in this video, watch easy engineering classes video of this topic, then come here you will understand each point. 😌
Each parity bit controls specific bits in the data according to their position. The rules are simple:
P1 checks bits 1, 3, 5, 7, ... (all bits where the binary position has a 1 in the least significant bit).
P2 checks bits 2, 3, 6, 7, ... (all bits where the binary position has a 1 in the second least significant bit).
P4 checks bits 4, 5, 6, 7, ... (all bits where the binary position has a 1 in the third least significant bit).
Sir pls gate smashers plus pr jo dssb ke liye series suru kr rakhi thi usko continues karo...
I have been waiting these for many days.
Sir please explain it on white board again please 🙏🏻
Understood
Sir, only this video seems difficult to understand🙁
may be because of board.......
Sir mixed 🤯
Sir apne 11 bit wale mei thode se confuse ho gaye, while calculating or checking if the parity bit is valid or not, we must take the XOR of the data bits but aap first 1 ko bhi le rahe the, which is the parity bit we are calculating. Hope this solves some confusion. Otherwise really good video sir.
I have the same confusion
@@suman8336 1st bit is the parity bit so don't take it and calculate XOR of the data bits. you will get wrong answer when you change the original 9th bit.✌️
This class is also provided in paid batch...i could not understand anything and came to free class....here also the same class....
please make video again... i can't understand..... use white board method 😌
Sir plz teach us in the board , we are unable to take it in this format plzz
kuch nhi samjhra yaar
white board was awesome...
plz back to white board (concepts are more clear over white board)
Solver it wrongly sir please check 9:10
Sir EX-OR left to right calculate karna hai ya right to left??
Left to right
sir you are the best
Teach on white board with pen not like this
Not satisfied.. it wil be better if you did it on whiteboard
Sir agr hm nay haming code me 2 bit error ko find out krna tu os k leyea hm kon saa fandaa use krain gay ?
thank you sir
Ye topic lagata hai apko v hard lagata hai
Isliye to board istamal kiya hai
po,p1,p2 will be already given in question?
Thanku
Love you sir
that's why ppt is always a bad option for teaching.....traditional way of explaining on board is always the best one.
Please explain this concept on the whiteboard
Through this its difficult to understand
🍎🍎🍎🍎🍎It is for you sir ji
Great lecture ❤️
Nice
Sir incase parity bit change hogaya packet me se toh detection ke waqt ye work karega ?
Good morning sir. Kindly kvs pgt ke according videos BNA dijiye... For topic web scripting, java, .net .....
Sir ,I am getting 0 in place of adding R1 at position 1 but in your example it is written 1.plz rectify me
Same here.. i m also getting p1 parity bit as 0
Please explain on whiteboard
Not understood Sir, what is the parity as p1
Sir plz do this in white board
but parity bits mai bhi toh error a sakta hai
how to calculate the bit r8 value ?
Sir white board pr hi pdaiye
Please sir again switch on white board❤
First time in this channel I didn't understand anything
Sir please teach on white board
Taking 011 from where, cursar not visible
aaj thoda confusion tha, just because of digital board
Sir white board pr hi padaya kro plzz
Sir please... use white Board
Boerd sir
Please Dont use digital way of study its ...,sir
I cant concentrate this way of study
Sir I can't understand 😢
Please make second video 🙏🏻
Only understand a topic m whenever you used a white board
White board p hi mst smjh aata h yaha gnta palle nhi pd rha kyuki yeh English language bich m aarhi h
2nd sum done.
tu insaan nahi ,bhagwan hai bhai
please teach on white board
How can we calculate original data?
Sir please write the white boad🙏
Clear nahi hai ye numerical, aap digitally batate hain to aadha hi clear hota hai achhe se samjh nahi aata,
White board use kriye sir
Sir please ek baar white board par explain kr do
Acha bahala board par samjhata tha Sir phr pata nahi kia hova