just explain me one thing , why we need to make the solution complex by adding extra steps. directly use the condition . why we have to first add +1 to both sides and assume r1+r2=r. just directly substitute values
Hello Sir. Thank you for the video. I still have a question. Based on the Wheatstone bridge equilibrium law, I understand that , with contact on d point, we obtain P (S+r2) = Q (R+r1) . But I don't understand how - on the same time - the equilibrium of the bridge is also giving P r2= Q r1 ? (wich means R r2 = S r1 ??) . Thak your for your help
😍😍. Easily understandable... Superbbb Explanation 👌💥
Thank you so much #knowlegeunlimited for your valuable and nice explanation on Bridges concepts 👏👏👌
Cancellation part is wrong in pr/p+r
Bro it's correct P/Q(S+Q/P+Q.r) = PS/Q + [PQ .r / Q( P+Q )] it would like this
Nice explanation...very simple
Thanks bro by this video I got clarity
Fabulous explanation sir
Good explanation
Tysm for this explanation sir😊
just explain me one thing , why we need to make the solution complex by adding extra steps. directly use the condition . why we have to first add +1 to both sides and assume r1+r2=r. just directly substitute values
Super explanation sir..🔥
How to measure small resitances
Hello Sir. Thank you for the video. I still have a question. Based on the Wheatstone bridge equilibrium law, I understand that , with contact on d point, we obtain P (S+r2) = Q (R+r1) . But I don't understand how - on the same time - the equilibrium of the bridge is also giving P r2= Q r1 ? (wich means R r2 = S r1 ??) . Thak your for your help
Nice bro
good
excellent explanation sir...but the circle around the pointer is little disturbing :(
Thank you
lots of love
Very speed
☺️
There is one mistake