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It doesn't get any better than this if you're looking for mathematically rigorous, and physically intuitive introductory lectures on turbulence. Professor Chakraborty is a gifted teacher and his lectures are a treasure.
This was absolutely the best lecture about k-e model that I've seen so far.Thank you so much!
slides are not clearly visible though.... :(
Excellent lecture with much of clarity on the practicability of turbulence modeling ------great
very nice explanation Professor, still being seen after 8 years
Thank you very much Professor!! Your explanations are crystal clear and good enough to increase the students' interest on Turbulence Research :)
Hi, nice video. Why do you divide by 2 in the averaging part at 17:25
1/2 [d/dt(u^2)] differentiates into 1/2[2u (du/dt)] = u (du/dt)...u can see the same thing at 40:50.
He is applying the chain rule to d/dt(u*u) = u*du/dt + u*du/dt = 2u*du/dt.
Thanks
Execellent lecture, just save me from fail this term
Muito bom!
Very effective
Magnus. Reverse chain rule
It doesn't get any better than this if you're looking for mathematically rigorous, and physically intuitive introductory lectures on turbulence. Professor Chakraborty is a gifted teacher and his lectures are a treasure.
This was absolutely the best lecture about k-e model that I've seen so far.
Thank you so much!
slides are not clearly visible though.... :(
Excellent lecture with much of clarity on the practicability of turbulence modeling ------great
very nice explanation Professor, still being seen after 8 years
Thank you very much Professor!! Your explanations are crystal clear and good enough to increase the students' interest on Turbulence Research :)
Hi, nice video. Why do you divide by 2 in the averaging part at 17:25
1/2 [d/dt(u^2)] differentiates into 1/2[2u (du/dt)] = u (du/dt)...u can see the same thing at 40:50.
He is applying the chain rule to d/dt(u*u) = u*du/dt + u*du/dt = 2u*du/dt.
Thanks
Execellent lecture, just save me from fail this term
Muito bom!
Very effective
Magnus. Reverse chain rule