CTSC practical experiment: Internal resistance in a battery

[@L1K3ABOSS29]

Very quick and informative video. Much appreciated.

[@JM-nc8cu]

Very, very long winded to say:
=> [voltage (no load) minus the voltage (under load)] divided by the current (under load).
=>[5V-3.6V]/0.3A=4.7Ohm. Short, easy, simple.

[@phomelelokgaphola1856]

does it matter in what order the components are connected?

[@masabathamakgatho8212]

I'm enjoying these videos. Do you have worksheets for leaners?

[@austengg5559]

amazing