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Small Angle Symmetric Tilt Boundary

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  • Опубликовано: 24 фев 2018
  • Small angle symmetric tilt boundary

Комментарии • 26

  • @shantanuchoukikar
    @shantanuchoukikar 4 года назад +3

    As soon as the model is shown, one can easily understand how to connect the two seemingly unrelated topics, namely
    1. Small angle tilt boundary
    2. Parallel edge dislocation
    It was like something was right in front of my eyes and yet I couldn't notice it.

  • @powerofindian4488
    @powerofindian4488 2 года назад +2

    Thank you sir for helping the poor and needy students for free 🙏

  • @diwakartiwari9155
    @diwakartiwari9155 5 лет назад +1

    Thanks thanks...... A lot,,
    I have highly confused about the surface dislocations,,, but now it's totally fine clearrence..
    😍 .....🙏🙏🙏🙏🙏🙏🙏🙏🙏

  • @geovaniferreirabarbosa5304
    @geovaniferreirabarbosa5304 5 лет назад +3

    Hi Professor Rajesh Prasad, please, where I can buy this model of a low angle symmetric tilt boundary that appears in 3:23 minutes of this video. Thanks. Congratulations for this videos...

    • @niteshkaloria9020
      @niteshkaloria9020 2 года назад

      Build your own if you understand the concept or if you are a teacher then make your students to do it👍

  • @adarsh7307
    @adarsh7307 4 года назад +1

    excellent lecturrre

  • @anmolrattan1828
    @anmolrattan1828 4 года назад

    How to distinguish between tilt boundary and srew dislocation in real cystal.

  • @avusulagnaneshwar948
    @avusulagnaneshwar948 5 лет назад +1

    in some books given for small angles tan theta can be taken as theta, but while doing problem which one should we take tan theta r only theta..

    • @rajeshprasad101
      @rajeshprasad101 5 лет назад +2

      For angles less than 10 degrees it does not matter whether you use theta or tan (theta).

    • @avusulagnaneshwar948
      @avusulagnaneshwar948 5 лет назад

      @@rajeshprasad101Thank you Sir..

  • @aravindk237
    @aravindk237 Год назад

    Dear Sir, how can we say that distance between consecutive dislocations from opposite sides are half that of the distance in one side? Isn't the better approach is to define the denomoninator term seperately, say, 'h' which is defined as the distance between consecutive dislocations on the one side.

  • @ShuvamNayak
    @ShuvamNayak 5 лет назад +3

    Sir, can't we say tilt boundary as a series of edge dislocation for symmetric large-angle also? If not then why?

    • @introductiontomaterialsscience
      @introductiontomaterialsscience  4 года назад +14

      Every dislocation has a core where the atoms are highly disturbed from their equilibrium position. This is something which is not captured in the models which I have used. The radius of the core is equal to a few interatomic spacing. Let this radius be r. Now the spacing of dislocations in the boundary plane is h. According to the formula derived for h one can see that h decreases as theta increases. If h becomes equal to 2r then the cores of the neighbouring dislocations will start to overlap and a model in terms of individual dislocations will break down. Thus the model is true only for low-angle symmetric tilt boundary.
      According to the book "Introduction to Dislocations" by D. Hull and D.J. Bacon the core radius can be taken to be between b and 4b (p69, 5th. Edn.). If we use h=2b corresponding to to r=b in the formula we get theta =14 Degrees. For r=4b, theta comes out to be less than 4 Degree.

    • @dilipkush.9315
      @dilipkush.9315 4 года назад

      See

  • @hiteshpaul4093
    @hiteshpaul4093 3 года назад

    Woah!!! Easily exaplained sir.🙌🙌🙌🙌

  • @shivanshmehrotra25
    @shivanshmehrotra25 4 года назад

    Sir, why do chemical etchants first attack the grain boundary and not the crystal?

    • @introductiontomaterialsscience
      @introductiontomaterialsscience  4 года назад +1

      Atoms at the grain boundary are at a higher energy level, due to broken and distorted bonds. Thus to reduce its energy, the metal gets rid of these higher energy atoms at a faster rate.

    • @shivanshmehrotra25
      @shivanshmehrotra25 4 года назад

      @@introductiontomaterialsscience Thanks a lot sir for explanation.

  • @kaspashravani9019
    @kaspashravani9019 4 года назад

    Sir, the rotation of axis should be parallel to have tilt boundary but when you are explaining the rotation of axis is horizontal that means it is perpendicular , I didn't got the clarity sir.

    • @introductiontomaterialsscience
      @introductiontomaterialsscience  4 года назад +1

      The boundary is a vertical plane and the rotation axis is the horizontal line lying in that plane.

    • @kaspashravani9019
      @kaspashravani9019 4 года назад

      @@introductiontomaterialsscience sir if rotation of axis is horizontal than it will be perpendicular to the boundary.. How can we say it as tilt boundary

    • @introductiontomaterialsscience
      @introductiontomaterialsscience  4 года назад

      @@kaspashravani9019 Every vertical plane has a horizontal direction lying in the plane (the intersection of the vertical and the horizontal planes)

  • @AbhishekLakra-il7gz
    @AbhishekLakra-il7gz Год назад

    Sin or cos ??? b/2d

  • @user-oy9rg8df8l
    @user-oy9rg8df8l 5 лет назад

    why is AB 2b?

    • @introductiontomaterialsscience
      @introductiontomaterialsscience  5 лет назад +1

      It is not 2b but 2d. The distance between successive dislocations is designated as d. But the half planes of these come from different crystals. To remain in the same crystal we take alternate dislocations. Thus AB becomes 2d.

  • @dut_uut
    @dut_uut 2 года назад +1

    Aapko Hindi mein gyan dena chahiye sir.adhik chhatro ko sahayta milegi aur aapka channel kaa lokapriyata bhi badhega .
    Dhanyvaad🙏🙏🙏🙏❤️❤️❤️