We know that F=-kx here F= mw²x substitute F in the above equation then mw²x=Kx from this we get w²=k/m taking only magnitude. R/m=2b is solution of second order differential equation
It is 2 order linear differential equation for this the solution is y=C.e power m.x so in DHO energy dissipation varies as 2b Therefore R/M is Damping factor and equal to 2b The power dissipation of DHO IS ALSO P=2bE Second order differential is complete solution y=Complementary functionc +particular integral To know CF we have auxiliary equation
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Please explain, how we get R/m=2b and
k/m=w^2 ?
We know that F=-kx here F= mw²x substitute F in the above equation then mw²x=Kx from this we get w²=k/m taking only magnitude.
R/m=2b is solution of second order differential equation
vaibhavi: b=1/NT
n=1/2pi(square root of Omega square - b square)
T=2pi/omega
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in damped harmonic oscillator R/m is taking as 2b. why? Can we use only b??
It is 2 order linear differential equation for this the solution is y=C.e power m.x so in DHO energy dissipation varies as 2b
Therefore R/M is Damping factor and equal to 2b
The power dissipation of DHO IS ALSO P=2bE
Second order differential is complete solution y=Complementary functionc +particular integral
To know CF we have auxiliary equation
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@@akv2867 just now I am going to upload clear explanation for not confusing I used capital B instead of b ok
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Sir, From where it comes the solution x=A. e raised to alpha t?
It's a solution of second order differential equation
See second order differential equation in other you tube channel toget idea
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