Inflection points introduction | AP Calculus AB | Khan Academy

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  • Опубликовано: 12 сен 2024
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    Inflection points are points where the function changes concavity, i.e. from being "concave up" to being "concave down" or vice versa. They can be found by considering where the second derivative changes signs. In similar to critical points in the first derivative, inflection points will occur when the second derivative is either zero or undefined. Created by Sal Khan.
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Комментарии • 27

  • @guitarttimman
    @guitarttimman 5 лет назад +7

    Awesome job boss. I love the Khan Academy videos. Thank you.

  • @Anielisstudying
    @Anielisstudying 7 месяцев назад +3

    Alright, but in the third example, the functions graph represent a straight line. There is no concavity in that.
    I just don’t get where the inflection point came from .

    • @spiguy
      @spiguy 4 месяца назад

      But the straight line is not an arbitrary curve, it's the 2nd derivative of the top curve. The right of the screen explains how we found the inflection point in terms of the maths. The reasoning is the same: we're looking for the critical points of f'(x) which with this method will allow us to find where the slope of f(x)'s continuity is the steepest aka inflection points.

  • @tammyl4586
    @tammyl4586 3 года назад +6

    Increasing & Decreasing and Concave up & down are two different concepts...... But this video mixes them together.

    • @spiguy
      @spiguy 4 месяца назад

      The language can be confusing, but weren't they talking about depression and ascension of the slope, not the original curve?

  • @newkoreathreekingdom
    @newkoreathreekingdom 11 лет назад +15

    Lol thank you so much right when i needed help in inflection point 1 minute later you upload it.

  • @jamesepace
    @jamesepace 11 лет назад +22

    I think I learned that the inflection point is where the second derivative is 0. I suppose if the second derivative is always 0, then that isn't true.

    • @JH-hb5cc
      @JH-hb5cc 6 лет назад +9

      James Pace not all points where the second derivative is 0 is necessarily an inflection point. All inflection points do have a second derivative of 0

    • @kishansahu2518
      @kishansahu2518 3 года назад

      Manh..it's a sufficient condition

  • @SPYmatholution
    @SPYmatholution 6 лет назад +2

    Find number of inflection point for the graph f(x)= x^2, for x>=0
    f(x)=-x^2 for x

  • @elmarjuz
    @elmarjuz 11 лет назад +1

    This is not completely related to the topics you are lately showcasing, but, could you at some point turn in the future to explaining discrete math elements?
    Sets and relations and stuff. You have a couple of videos about relations and functions, but these topics can be sort of convoluted.
    Also, mathematical proofs. I'm having a lot of problems with those.

  • @whitneycarpenter691
    @whitneycarpenter691 3 года назад

    Helpful! Thank you!

  • @youtubeessentials2996
    @youtubeessentials2996 Год назад

    Thanks a lot

  • @indiawelch4592
    @indiawelch4592 7 лет назад +1

    This helped a lot. THANKS!!!!

  • @菈米的大福工坊
    @菈米的大福工坊 4 года назад +3

    0:28 The slope was decreasing?

  • @deependragaur4991
    @deependragaur4991 4 года назад

    Thanks 🙏🙇

  • @kabirkrishna8520
    @kabirkrishna8520 Год назад +1

    Top G

  • @JosePablo24
    @JosePablo24 8 лет назад +2

    He forgets to mention that inflection points also happen where f'(x) and f''(x) are undefined.

    • @parsazahed4210
      @parsazahed4210 5 лет назад

      will they be the same points? (the points where f'(x) and f"(x) are undefined)

    • @aryamanm2170
      @aryamanm2170 4 года назад +2

      those are called critical points

  • @vitorpareja
    @vitorpareja 11 лет назад

    does that aply for sin and cos functions ???
    because the f ' (sin) isn't a cos!?!?!?

  • @Genghiskaran
    @Genghiskaran 11 лет назад

    cool

  • @kabirkrishna8520
    @kabirkrishna8520 Год назад

    W

  • @mubasshirmubin7278
    @mubasshirmubin7278 4 месяца назад

    bet u cant draw 2 concave downwards together😂😂