This is a band stop filter. The "anti-resonance point " makes the current low at a particular frequency and fixed LC properties.... pretty handy for a multiband ham radio antenna.However this // circuit can also function as a radio tuner. Now use the inductor from the series LRC circuit, and place it next to the parallel circuit inductor and create a transformer. substitute a variable capacitor in place of the fixed capacitor, the parallel circuit becomes a tuner, and the series circuit a band pass filter which tunes an antenna!,has taken me 43 years since college physics to master this understanding..thank you Dr. Lewin. I did get an A back in the day.....but now my eyes are fully open. I simply cannot watch this lecture enough times...awesome....simply understanding the circuit by understanding the components limiting values , Faraday's law applies loop 2 not a poor application of KIrchhoff's voltage rule, absolutely brilliant. Phasor diagram insight, leaving out Mr. Euler's equations for now.......to focus the ideas...stunning
At 5:28, you get done writing the equation for Current through the solenoid as a function of time: (emf/w)*sin(wt) -- the integral of the equation 2. But based on the equation, shouldn't it be divided by an L term to get rid of it on the right side.
I was sitting here watching, at about 27 minutes about to go... No wait, you need to take the 2nd derivative to know if that's a maxima or minima! You only found a turning point!
I had trouble with this at school, but this made it look so obvious wtf. Hope you get 1M subscribers soon! If all schoolchildren watched these videos, we would have a whole new generation of enthusiastic physicists.
amazing explanation Sir....I love ur lectures...currently I am watching ur lecture 8.02. sir I had this doubt from my school days and from the books I got some answer but confused me a lot. inductor always confused me a lot. now I got the clear answer from u and I am sure that this is the correct explanation. once again thank u sir...
@@cricobug9778 in this case you know that maximum current is infinity and the curve is vertical line at infinity, whereas maxima/minima is a point on curve where derivative is zero which implies a horizontal line. So the extremum we got here will definitely be the minimum and not maximum.
At 4:33 you said that total instantaneous current [ through battery ] is sum of instantaneous currents through L, C, R. But in my book it is written that " The total current drawn from the supply is equal to the vector sum of the resistive, inductive and capacitive current, not the mathematical sum of the three individual branch currents, as the current flowing in resistor, inductor and capacitor are not in same phase with each other; so they cannot be added arithmetically. Could you please clear this ? Is the sum of rms currents through L , C , R = rms current through source or is this true for instantaneous current ? Does phasor method work for rms currents or instantaneous currents ? Is Kirchhoff's 2nd law not valid for instantaneous currents ?
>>>>At 4:33 you said that total instantaneous current [ through battery ] is sum of instantaneous currents through L, C, R.>>>> That is correct. The solution to the diff eq I(t) says it all. There is ONLY one I at a given time t and that takes the phase angles into account.
Isn't the current in the inductor supposed to lead the one in the resistor . We've seemed to have done the opposite here I'm sorry there's no mistake Just a bit of a misunderstanding. Really appreciate this video
In resonance : (1) is the instantaneous current through source = instantaneous current through resistor ; ie the entire current supplied by source goes through resistor ? (2) instantaneous current through inductor = instantaneous current through capacitor ( but in opposite direction )? ie ,capacitor and inductor feed each other.
Why do we ignore the constant of integration while evaluating current through the inductor? Is it justified to remove the constant just because it comes to be a DC component?
Sir , if we have a battery with no resistance , is it possible to have an induced E-field in the battery due to time changing B-fields in the circuit ?
make your own calculations and estimate realistic values of the self inductance of all your components. My guess is that the sum of all will be less than 10 micro H. Take it from there
zero frequency means a dc source aka battery. and when battery will be connected, initially capacitor will begin to charge, current will start growing in inductor and also flow throught resistor. And at steady state no current through capacitor, inductor behaves like a normal wire, and there will be a short circuit
sir..what will be the voltage across the inductor if the electric field is zero..whether it is zero or.. it is the source voltage ...pls provide me an answer..thank you
In case of non-conservative E fields, it's better not to talk about "voltage"or "potential difference" over a self-inductor as it depends on how you measure it. If you define potential difference as the integral of E dot dl through the superconducting self inductor the answer is ZERO as the E-field in the self-inductor is zero. If you place a voltmeter over the self-inductor, then you have added a loop to the circuit and you will have to apply Faraday's law in that loop. You will then find that the voltmeter reads the value + or minus L*dI/dt. I suggest you watch 2 of my lectures ruclips.net/video/LzT_YZ0xCFY/видео.html and ruclips.net/video/nGQbA2jwkWI/видео.html
sir at around 11 minute you wrote the value of tan fie....but I think there will be 1overR in the denominator not R...help me out if I am correct or not????
Lectures by Walter Lewin. They will make you ♥ Physics. i am saying that tan of fie should have a 1 OVER R downstairs.... according to the phasor......in Z there is 1 OVER R^2
my apologies, the msg I sent you yesterday was NOT meant for you but for someone else who wrote a msg about 1/R. Yes, you are right, tan of phi the R should be upstairs. 1/(1/R)=R.
Lectures by Walter Lewin. They will make you ♥ Physics. thank you sir,,,you make me feel physics equation and see through them....you make physics a art......thank you for that professor....wish I have ever a chance to meet you.....
Lectures by Walter Lewin. They will make you ♥ Physics. i live in India.....if I get there..... I will contact you.....sir.....I want to tell you one thing the most physics teacher should learn from you that Kirchoff's rule is a special case of Faraday's law....that is amazing...concept is stairway to mathematics,most of us do blind maths....you came to India 2 or a year ago in IIT,I lost the chance to meet you.....
@@lecturesbywalterlewin.they9259 I am pretty sure that R should be in the numerator. What you have is not dimensionless as tanφ should be. From the triangle tanφ = opposite / adjacent = Ε0*(ωC - 1 / ωL) / Ε0*(1/R) = R*(ωC - 1 / ωL)
Hello sir. I think you have by mistake written that, I(L)t= (epsilon 0/omega)×sin(omega t) +... I think the L is missing her. That is it must be, I(L)t= (epsilon 0/omega L) × sin(omega t)+....
Sir , imagine we have an ideal ac voltage source in series with an ideal self inductor and we connect them by superconducting wires , will we have an induced emf in that circuit and if there is an induced emf , what will be the location of the emf ?
You made me love Parallel RLC circuit. Thank you Dr. Walter Lewin!
Cheers from Brazil :)
these lectures are gold!!!
i always look upto him or HC verma ....
if you guys know a similar teacher please let me know!
Studying for my JEE ADVANCED 2020 from you sir
Thanks for helping
Love from INDIA
Please tell jee adv aspirant here from 2021 🙏
KVLonlyvalidforconservativefield
This is a band stop filter. The "anti-resonance point " makes the current low at a particular frequency and fixed LC properties.... pretty handy for a multiband ham radio antenna.However this // circuit can also function as a radio tuner. Now use the inductor from the series LRC circuit, and place it next to the parallel circuit inductor and create a transformer. substitute a variable capacitor in place of the fixed capacitor, the parallel circuit becomes a tuner, and the series circuit a band pass filter which tunes an antenna!,has taken me 43 years since college physics to master this understanding..thank you Dr. Lewin. I did get an A back in the day.....but now my eyes are fully open. I simply cannot watch this lecture enough times...awesome....simply understanding the circuit by understanding the components limiting values , Faraday's law applies loop 2 not a poor application of KIrchhoff's voltage rule, absolutely brilliant. Phasor diagram insight, leaving out Mr. Euler's equations for now.......to focus the ideas...stunning
At 5:28, you get done writing the equation for Current through the solenoid as a function of time: (emf/w)*sin(wt) -- the integral of the equation 2. But based on the equation, shouldn't it be divided by an L term to get rid of it on the right side.
yessss there should have been an L. sorry! Thanks for pointing this out.
Thank you for the confirmation!! Awesome lesson as usual.
Yeah that's what i was thinking too
I was sitting here watching, at about 27 minutes about to go... No wait, you need to take the 2nd derivative to know if that's a maxima or minima! You only found a turning point!
I had trouble with this at school, but this made it look so obvious wtf. Hope you get 1M subscribers soon! If all schoolchildren watched these videos, we would have a whole new generation of enthusiastic physicists.
amazing explanation Sir....I love ur lectures...currently I am watching ur lecture 8.02. sir I had this doubt from my school days and from the books I got some answer but confused me a lot. inductor always confused me a lot. now I got the clear answer from u and I am sure that this is the correct explanation. once again thank u sir...
Monster 😂😂 11:14
Thank you sir for bringing this 💪
🙏🙏 really helped me solving parallel ac circuits.
What an amazing professor you are sir, i think it’s the derivative of I max with respect to W that max out the function. Great video!!
You open my eye. Thank you Prof. (From Thailand)
Dhanyawad = thank you in Hindi ❤️❤️
Sir at 5:36 you write I_LT=epsilon*sin(omega*t)/omega... But shouldn't it be I_LT=epsilon*sin(omega*t)/(omega*L)
Sir please take the case in which L and R are in series and C is in parallel with the LR series combination. .
10:58 I assume tan(phi) = R(wc-1/wL).
right
that's the same, he just didn't use the reactances Xl and Xc notation, just used wL and 1/wc
Sir you are the best teacher in the world...
Awesome lecture sir, But at 5:26 shouldn't it devided by L, when you wrote integral of equation 2 🙋
yes
Lovely ♥️
:)
Mathematical demonstration that physics works....
best professor
monster was amazing
Aur lakshiyan lindanes , aagye?
.... there is Electric field inside the solenoid/ inductor, but in the radial direction. Yes, no electric field along the axis. ....
*NO*
Whoever taught u this , was certainly drunk then
Excellent! Thanks, Sir!
:)
That was great, thank you very much. But I think you meant to say that you took the derivative as a function of omega and not time at 15:08 and 16:25.
y=f(ω) yupe should have been dy/dω. Amazing that noone pointed that out in 1996 when this was on the air at MIT 24/7 for a whole week.
@@lecturesbywalterlewin.they9259 professor but how will i know this yields maxima or minima because we use same method
@@cricobug9778 in this case you know that maximum current is infinity and the curve is vertical line at infinity, whereas maxima/minima is a point on curve where derivative is zero which implies a horizontal line. So the extremum we got here will definitely be the minimum and not maximum.
how we can reach the formula?(I max) which differential equation should we solve?
At 4:33 you said that total instantaneous current [ through battery ] is sum of instantaneous currents through L, C, R. But in my book it is written that " The total current drawn from the supply is equal to the vector sum of the resistive, inductive and capacitive current, not the mathematical sum of the three individual branch currents, as the current flowing in resistor, inductor and capacitor are not in same phase with each other; so they cannot be added arithmetically.
Could you please clear this ? Is the sum of rms currents through L , C , R = rms current through source or is this true for instantaneous current ? Does phasor method work for rms currents or instantaneous currents ?
Is Kirchhoff's 2nd law not valid for instantaneous currents ?
>>>>At 4:33 you said that total instantaneous current [ through battery ] is sum of instantaneous currents through L, C, R.>>>>
That is correct. The solution to the diff eq I(t) says it all. There is ONLY one I at a given time t and that takes the phase angles into account.
For me Walter lewin is enisten, nicola , bohr , schrodinger etc . Respect from india
When I did experiment- parallel resonance,the current keep decreased,but never increase.what is the reason behind it
Thank you sir.
The way he says.. But we have time to do that
Isn't the current in the inductor supposed to lead the one in the resistor .
We've seemed to have done the opposite here
I'm sorry there's no mistake
Just a bit of a misunderstanding.
Really appreciate this video
I cannot add to the clarity of this video.
@@lecturesbywalterlewin.they9259 yes sir
I've realised where I've gone wrong
when current lags the voltage,does it mean it flows in the reverse direction to the one taken in the circuit.
Really trivial. Enjoyable though.
Great 😎
In resonance :
(1) is the instantaneous current through source = instantaneous current through resistor ; ie the entire current supplied by source goes through resistor ?
(2) instantaneous current through inductor = instantaneous current through capacitor ( but in opposite direction )? ie ,capacitor and inductor feed each other.
1. question unclear
2. NO
*watch my related 8.02 lectures.*
Why do we ignore the constant of integration while evaluating current through the inductor? Is it justified to remove the constant just because it comes to be a DC component?
how many minutes into the video?
I can't understand the Infinitely high C concept.
Sir , if we have a battery with no resistance , is it possible to have an induced E-field in the battery due to time changing B-fields in the circuit ?
make your own calculations and estimate realistic values of the self inductance of all your components. My guess is that the sum of all will be less than 10 micro H. Take it from there
Sir , at 3:53 you wrote faraday's law for loop number 2 , is the induced E-field lies inside the driving source for this loop ?
I cannot add to the clarity of this video. I suggest you watch it again and also my 8.02 lectures which cover all this.
@@lecturesbywalterlewin.they9259 it may be a trivial question for you but it will be a great help if you answered such a question .
❤
What will happen if the voltage source frequency was set up to zero ?
zero frequency means a dc source aka battery. and when battery will be connected, initially capacitor will begin to charge, current will start growing in inductor and also flow throught resistor. And at steady state no current through capacitor, inductor behaves like a normal wire, and there will be a short circuit
Sir What Is Vertasium 79 Said In Electrical energy Is its right
Which one ?
sir..what will be the voltage across the inductor if the electric field is zero..whether it is zero or.. it is the source voltage ...pls provide me an answer..thank you
In case of non-conservative E fields, it's better not to talk about "voltage"or "potential difference" over a self-inductor as it depends on how you measure it. If you define potential difference as the integral of E dot dl through the superconducting self inductor the answer is ZERO as the E-field in the self-inductor is zero. If you place a voltmeter over the self-inductor, then you have added a loop to the circuit and you will have to apply Faraday's law in that loop. You will then find that the voltmeter reads the value + or minus L*dI/dt. I suggest you watch 2 of my lectures ruclips.net/video/LzT_YZ0xCFY/видео.html and
ruclips.net/video/nGQbA2jwkWI/видео.html
thank u very much sir
sir at around 11 minute you wrote the value of tan fie....but I think there will be 1overR in the denominator not R...help me out if I am correct or not????
Lectures by Walter Lewin. They will make you ♥ Physics. i am saying that tan of fie should have a 1 OVER R downstairs.... according to the phasor......in Z there is 1 OVER R^2
my apologies, the msg I sent you yesterday was NOT meant for you but for someone else who wrote a msg about 1/R.
Yes, you are right, tan of phi the R should be upstairs. 1/(1/R)=R.
Lectures by Walter Lewin. They will make you ♥ Physics. thank you sir,,,you make me feel physics equation and see through them....you make physics a art......thank you for that professor....wish I have ever a chance to meet you.....
I'll be happy to meet with you. I live in the US (East coast).
Lectures by Walter Lewin. They will make you ♥ Physics. i live in India.....if I get there..... I will contact you.....sir.....I want to tell you one thing the most physics teacher should learn from you that Kirchoff's rule is a special case of Faraday's law....that is amazing...concept is stairway to mathematics,most of us do blind maths....you came to India 2 or a year ago in IIT,I lost the chance to meet you.....
💟💟💟
hope I have a chance to give a million likes
Shouldn't be tan(φ) = R*( ωC - (1 / ωL) ) ???
what I have is corect - 0fcoz -
@@lecturesbywalterlewin.they9259 I am pretty sure that R should be in the numerator. What you have is not dimensionless as tanφ should be. From the triangle tanφ = opposite / adjacent = Ε0*(ωC - 1 / ωL) / Ε0*(1/R) = R*(ωC - 1 / ωL)
Studying all this class 12 in school: ( in India
Hello sir. I think you have by mistake written that,
I(L)t= (epsilon 0/omega)×sin(omega t) +...
I think the L is missing her. That is it must be,
I(L)t= (epsilon 0/omega L) × sin(omega t)+....
how many minutes into the video?
Lectures by Walter Lewin. They will make you ♥ Physics.
Sorry for the late reply.
It is at 5 minutes and 25 seconds.
And love you sir.
Please sir , is the voltage across these parallel branches the same at any moment in time or i will get different values for different paths ?
watch my 8.02 lectures!
Sir , imagine we have an ideal ac voltage source in series with an ideal self inductor and we connect them by superconducting wires , will we have an induced emf in that circuit and if there is an induced emf , what will be the location of the emf ?
this is a classic question. physics.stackexchange.com/questions/108821/what-happens-in-a-circuit-when-the-wire-and-the-battery-are-superconducting-an
😘
What is he talking about 🥲